\(\frac{5^2.3^3-25.17}{25.3^2-5^2.8}\)
Những câu hỏi liên quan
Rút gọn biểu thức:
a) \(\frac{2.8^4.27^2+4.6^9}{2^7.6^7+2^7.40.9^4}\)
b) \(\frac{\left(\frac{2}{3}\right)^3.\left(\frac{-3}{4}\right)^2.\left(-1\right)^5}{\left(\frac{2}{5}\right)^2.\left(\frac{-5}{12}\right)^3}\)
a, \(\dfrac{2\cdot8^4\cdot27^2+4\cdot6^9}{2^7\cdot6^7+2^7\cdot40\cdot9^4}\)
=\(\dfrac{2\cdot\left(2^3\right)^4\cdot\left(3^3\right)^2+2^2\cdot2^9\cdot3^9}{2^7\cdot2^7\cdot3^7+2^7\cdot2^3\cdot5\cdot\left(3^2\right)^4}\)
=\(\dfrac{2\cdot2^{12}\cdot3^6+2^{11}\cdot3^9}{2^{14}\cdot3^7+2^{10}\cdot5\cdot3^8}\)
=\(\dfrac{2^{11}\cdot3^6\cdot\left(2^2+3^3\right)}{2^{10}\cdot3^7\cdot\left(2^4+5\cdot3\right)}\)
=\(\dfrac{2^{11}\cdot3^6\cdot31}{2^{10}\cdot3^7\cdot31}\)
=\(\dfrac{2}{3}\)
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b, \(\dfrac{\dfrac{8}{27}\cdot\dfrac{9}{16}\cdot\left(-1\right)}{\dfrac{4}{25}\cdot\dfrac{-125}{1728}}\)
=\(\dfrac{\dfrac{8\cdot9\cdot\left(-1\right)}{27\cdot16}}{\dfrac{4\cdot\left(-125\right)}{25\cdot1728}}\)
=\(\dfrac{\dfrac{-1}{6}}{\dfrac{-5}{432}}\)
=\(\dfrac{-1}{6}\cdot\dfrac{-432}{5}\)
=\(\dfrac{72}{5}\)
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Tính:
a,\(D=\frac{2.8^9.27+4.6^9}{2^7.6^7+2^7.40.9^4}\)
b,\(E=\frac{\left(\frac{2}{3}\right)^3.\left(\frac{-3}{4}\right)^2.\left(-1\right)^5}{\left(\frac{2}{5}\right)^2.\left(\frac{-5}{12}\right)^3}\)
\(D=\frac{2\cdot8^9\cdot27+4\cdot6^9}{2^7\cdot6^7+2^7\cdot40\cdot9^4}\)
\(=\frac{2^{28}\cdot3^3+2^{11}\cdot3^9}{2^{14}\cdot3^7+2^{10}\cdot5\cdot3^8}\)
\(=\frac{3^3\cdot2^{11}\left(2^{17}+3^6\right)}{2^{10}\cdot3^7\left(2^4+5\cdot3\right)}\)
\(=\frac{2^{18}+2\cdot3^6}{6^4+3^5}\)
Đúng ko ta.Kết quả hổng đẹp chút nào:(((
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\(E=\frac{\left(\frac{2}{3}\right)^3\cdot\left(-\frac{3}{4}\right)^2\cdot\left(-1\right)^5}{\left(\frac{2}{5}\right)^2\cdot\left(\frac{-5}{12}\right)^3}\)
\(E=\frac{\frac{2^3}{3^3}\cdot\frac{3^2}{4^2}\cdot\left(-1\right)}{\frac{2^2}{5^2}\cdot\frac{\left(-5\right)^3}{12^3}}\)
\(E=\frac{\frac{-2}{3\cdot4}}{\frac{2^2}{5^2}\cdot\frac{-5^3}{2^6\cdot3^3}}=-\frac{\frac{1}{3}}{-\frac{5}{2^4\cdot3^3}}=\frac{2^4\cdot3^2}{5}\)
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ai giúp mình câu này với,mình tick choa)left(-frac{1}{2}right)^2:left(1frac{5}{16}-sqrt{4}+frac{1}{2}right)+2008^0 b)7frac{1}{6}:left(-sqrt{frac{49}{36}}right)+10frac{5}{6}.left(-frac{14}{2^2.3}right)+left|-frac{1}{2}right|c)left(-frac{1}{2}right)^2+5frac{1}{2}left(4,5-sqrt{sqrt{16}}right)+frac{2^3}{-left|-2right|^2} d)frac{4^2.8^6.9^{13}}{6^6.16^2.27}
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ai giúp mình câu này với,mình tick cho
a)\(\left(-\frac{1}{2}\right)^2:\left(1\frac{5}{16}-\sqrt{4}+\frac{1}{2}\right)+2008^0\) b)\(7\frac{1}{6}:\left(-\sqrt{\frac{49}{36}}\right)+10\frac{5}{6}.\left(-\frac{14}{2^2.3}\right)+\left|-\frac{1}{2}\right|\)
c)\(\left(-\frac{1}{2}\right)^2+5\frac{1}{2}\left(4,5-\sqrt{\sqrt{16}}\right)+\frac{2^3}{-\left|-2\right|^2}\) d)\(\frac{4^2.8^6.9^{13}}{6^6.16^2.27}\)
a)
1/4:(31/16-2+1/2)+1
=1/4:(-1/16+1/2)+1
=(1/4:7/16)+1
=4/7+1
=11/7
b)
43/6:(-7/6)+65/6.(-7/6)+1/2
=-43/7+-455/36+1/2
=-4607/252
c)
1/4+11/2.5/2+-2
=23/4.5/2+-2
=115/8+-2
=99/8
d) bài 4 rất dễ bạn tự làm đi nhé
tick cho mk đi nhanh lên đó nhiên
=
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Xem thêm câu trả lời
Rút gọn các biểu thức sau :
A=\(\frac{2.8^4.27^2+4.6^9}{2^7.6^7+2^7.40.9^4}\)
B=\(\frac{\left(\frac{2}{3}\right)^3.\left(-\frac{3}{4}\right)^2.\left(-1\right)^5}{\left(\frac{2}{5}\right)^2.\left(-\frac{5}{12}\right)^3}\)
Rút gọn
A=\(\frac{2.8^4.27^2+4.6^9}{2^7.6^7+2^7.40.9^4}\)
B=\(\frac{\left(\frac{2}{3}\right)^2.\left(-\frac{3}{4}\right)^2.\left(-1\right)^5}{\left(\frac{2}{5}\right)^2.\left(-\frac{5}{12}\right)^3}\)
\(\frac{27^2.8^5}{6^6.32^3}\)
\(\frac{27^2.8^5}{6^6.32^3}=\frac{\left(3^3\right)^2.\left(2^3\right)^5}{2^6.3^6.\left(2^5\right)^3}\)
\(=\frac{3^6.2^{15}}{2^6.3^6.2^{15}}\)
\(=\frac{1}{2^6}\)
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Giải các phương trình, bất pt sau:
\(\sqrt{2.6^x-4^x}+\sqrt[3]{3.12^x-2.8^x}=2.3^x\)
\(\frac{1}{2^{\sqrt{x^2-2x}}}\le2^{x-1}\)
rút gọn rồi quy đồng mẫu các phân số
\(\frac{25.9-25.17}{-8.80-8.10}\) và \(\frac{48.12-48.15}{-3.270-3.30}\)
\(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}\) và \(\frac{3^4.5-3^6}{3^4.13+3^4}\)
Rút gọn
A=\(\frac{2.8^4.27^2+4.6^9}{2^7.6^7+2^7.40.9^4}\)
B=\(\frac{\left(\frac{2}{3}\right)^2.\left(-\frac{3}{4}\right)^2.\left(-1\right)^5}{\left(\frac{2}{5}\right)^2.\left(-\frac{5}{12}\right)^3}\)