\(\frac{19}{20}-x+\frac{3}{4}=\frac{8}{5}\)

\(\frac{19}{20}-x=\frac{8}{5}-\frac{3}{4}\)

\(\frac{19}{20}-x=\frac{17}{20}\)

\(x=\frac{19}{20}-\frac{17}{20}\)

 \(x=\frac{1}{10}\)

\(\frac{19}{20}-x+\frac{3}{4}=\frac{8}{5}\)

\(1,7-x=1,6\)

\(x=1,7-1,6\)

\(x=0,1\)

x=2 nhé

t ick mình

là 2 nha

Ca này bó tay rồi, ghi rõ ra đc ko, khó hiểu quá

a; \(\dfrac{3}{5}\) - \(\dfrac{-7}{10}\) - \(\dfrac{13}{-20}\)

= \(\dfrac{12}{20}\) +  \(\dfrac{14}{20}\) + \(\dfrac{13}{20}\)

= \(\dfrac{39}{20}\)

b; \(\dfrac{1}{2}\) + \(\dfrac{1}{-3}\) + \(\dfrac{1}{4}\) - \(\dfrac{-1}{6}\)

= \(\dfrac{6}{12}\) - \(\dfrac{4}{12}\) + \(\dfrac{3}{12}\) + \(\dfrac{2}{12}\)

= \(\dfrac{7}{12}\)

\(\frac{1}{4}+\frac{13}{25}+75\%+48\%=\frac{1}{4}+\frac{13}{25}+\frac{3}{4}+\frac{12}{25}=\left(\frac{1}{4}+\frac{3}{4}\right)+\left(\frac{13}{25}+\frac{12}{25}\right)\)

= 1+1 = 2

\(\dfrac{x}{5}=\dfrac{y}{4}=\dfrac{z}{2}\)

\(\Rightarrow\dfrac{x^3}{125}=\dfrac{y^3}{64}=\dfrac{z^3}{8}=\dfrac{x^3-y^3+z^3}{125-64+8}=\dfrac{69}{69}=1\)

\(\Rightarrow\left\{{}\begin{matrix}x=\sqrt[3]{125}=5\\y=\sqrt[3]{64}=4\\z=\sqrt[3]{8}=2\end{matrix}\right.\)

Jmgoxpig och ogu o chxjf yvb

8vuob