trả lời dùm mình đi

viết rõ lại cái đề giùm tui tui mới làm được

a. 6 và 5/3 + 7 và 13/8 +3 và 1/3- 4 và 5/8

=23/3+69/8+4/3-37/8

=391/24+4/3+37/8=141/8-37/8=103/8

b.=(27/5+69/11)-(17/5-52/11)

=642/55+73/55=13

giúp mik với

\(\frac{6}{7}+\frac{2}{5}-\frac{1}{2}+2\frac{38}{91}-\frac{4}{5}=\frac{27300}{31850}+\frac{12740}{31850}-\frac{15925}{31850}+\) \(2\frac{13300}{31850}\)\(-\frac{25480}{31850}\)

\(=2\frac{27300+12740-15925+13300-25480}{31850}\)\(=2\frac{341}{910}\)

HỌC TỐT!!!

hỏi google phay

Hỏi gg đi khó lắm

Xin lỗi  vì ko giúp cho bạn vì khó lắm

cvfbhm,

Xin lỗi em ko biết làm , em vẫn chưa lên lớp 9

1)\(\left(\frac{1}{a-\sqrt{a}}+\frac{1}{\sqrt{a}-1}\right):\frac{\sqrt{a}+1}{a-2\sqrt{a}+1}\)

\(=\left(\frac{1}{\sqrt{a}\left(\sqrt{a}-1\right)}+\frac{\sqrt{a}}{\sqrt{a}\left(\sqrt{a}-1\right)}\right)\cdot\frac{\left(\sqrt{a}-1\right)^2}{\sqrt{a}+1}\)

\(=\frac{\sqrt{a}+1}{\sqrt{a}\left(\sqrt{a}-1\right)}\cdot\frac{\left(\sqrt{a}-1\right)^2}{\sqrt{a}+1}\)

\(=\frac{\sqrt{a}-1}{\sqrt{a}}\)

nhớ ghi rõ cách làm ( tính nhanh )

Ta có : \(\frac{3}{5}+\frac{6}{11}+\frac{7}{13}+\frac{2}{5}+\frac{5}{11}+\frac{19}{13}+\frac{1}{2}+\frac{2}{3}-\frac{1}{6}\)

\(=\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{6}{11}+\frac{5}{11}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)+\left(\frac{1}{2}+\frac{2}{3}-\frac{1}{6}\right)\)

\(=1+1+2+1=5\)

\(\frac{3}{5}+\frac{6}{11}+\frac{7}{13}+\frac{2}{5}+\frac{5}{11}+\frac{19}{13}:\frac{1}{2}+\frac{2}{3}-\frac{1}{6}\)

\(=\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{19}{13}-\frac{7}{13}\right)+\left(\frac{6}{11}+\frac{5}{11}\right):\frac{2}{3}+\frac{1}{6}\)

\(=1+1+1:\frac{2}{3}+\frac{1}{6}\)

\(=3:\frac{2}{3}+\frac{1}{6}\)

\(=\frac{9}{2}+\frac{1}{6}\)

\(=\frac{14}{3}\)

= (3/5 + 2/5) + (6/11 + 5/11) + (7/13 + 19/13) : 1/2 + 2/3 - 1/6

= (1 + 1 + 2) : (1/2 + 4/6 - 1/6)

= 4 : (1/2 + 1/2)

= 4 : 1

= 4

Vậy kết quả bằng 4

giúp mk với

mong ban ghi han hoi :)

khó đọc quá

Đặt A=\(\frac{1}{3}.5+\frac{1}{5}.7+...+\frac{1}{97}.99\)

=>A=\(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{97.99}\)

=>2A=\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{97.99}\)

=>2A=\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\)

=>2A=\(\frac{1}{3}-\frac{1}{99}=\frac{33}{99}-\frac{1}{99}=\frac{32}{99}\)

=>A=\(\frac{32}{99}:2=\frac{32}{99}.\frac{1}{2}=\frac{32}{198}=\frac{16}{99}\)

a; \(\dfrac{3}{5}\) - \(\dfrac{-7}{10}\) - \(\dfrac{13}{-20}\)

= \(\dfrac{12}{20}\) +  \(\dfrac{14}{20}\) + \(\dfrac{13}{20}\)

= \(\dfrac{39}{20}\)

b; \(\dfrac{1}{2}\) + \(\dfrac{1}{-3}\) + \(\dfrac{1}{4}\) - \(\dfrac{-1}{6}\)

= \(\dfrac{6}{12}\) - \(\dfrac{4}{12}\) + \(\dfrac{3}{12}\) + \(\dfrac{2}{12}\)

= \(\dfrac{7}{12}\)