\(\left(\dfrac{3x}{4}+5\right)-\left(\dfrac{2x}{3}-4\right)-\left(\dfrac{x}{6}+1\right)=\left(\dfrac{1}{3}+4\right)-\left(\dfrac{1}{3}x-3\right)\)

\(\Leftrightarrow\dfrac{3x}{4}-\dfrac{2x}{3}-\dfrac{x}{6}+5+4-1=\dfrac{13}{3}-\dfrac{1}{3}x+9\)

\(\Leftrightarrow\dfrac{9x-8x-2x}{12}+8=\dfrac{13-x}{3}+\dfrac{27}{3}\)

\(\Leftrightarrow\dfrac{-x}{12}+\dfrac{96}{12}=\dfrac{40-x}{3}\Leftrightarrow\dfrac{96-x}{12}=\dfrac{160-4x}{12}\)

\(\Rightarrow96-160=-4x+x\Leftrightarrow-64=-3x\Leftrightarrow x=\dfrac{64}{3}\)

3/4x + 5-(2/3x-4)-(1/6+1)=(1/3x+4)-(1/3x-3)

=3/4x+5-2/3x-4-1/6x+1=1/3x+4-1/3x-3

=-1/12=7

x=84

Đ/S...

ta co (2x-1)(3x+1)+(3x+4)(3-2x)=5

     (=)6x²-3x+2x-1+6x-6x²+12-8x=5

     (=)-4x+11=5

     (=)-4x=-6

     (=)x=3/2

(2x-1)(3x+1)+(3x-4)(3-2x)=5

<=> 6x²+2x-3x-1+9x-6x²-12+8x=5

<=> 16x-13=5

<=> 16x = 18

<=> x=9/8

Đăng từng câu đio

,(8x-3).(3x+2)-(4x+7).(x+4)=(2x+1).(5x-1)-33 đúng không bạn

Theo đề bài ta có : x−12=y+34=z−56x−12=y+34=z−56 và 5z−3x−4y=505z−3x−4y=50

\Leftrightarrow 3(x−1)6=4(y+3)16=5(z−5)303(x−1)6=4(y+3)16=5(z−5)30 và 5z−3x−4y=505z−3x−4y=50

\Leftrightarrow 3x−36=4y+1216=5z−25303x−36=4y+1216=5z−2530 và 5z−3x−4y=505z−3x−4y=50

Áp dụng tính chất dãy tỉ số bằng nhau ta có :

3x−36=4y+1216=5z−2530=(5z−25)−(3x−3)−(4y+12)30−6−16=5z−3x−4y−25+3−128=168=23x−36=4y+1216=5z−2530=(5z−25)−(3x−3)−(4y+12)30−6−16=5z−3x−4y−25+3−128=168=2

\Rightarrow x−12=2x−12=2 \Rightarrow x−1=4x−1=4 \Leftrightarrow x=5x=5

\Rightarrow y+34=2y+34=2 \Rightarrow y+3=8y+3=8 \Leftrightarrow y=5y=5

\Rightarrow z−56=2z−56=2 \Rightarrow z−5=12z−5=12 \Leftrightarrow z=17z=17

tk nha bạn