Tìm thương A:B bt
A= 9/1+8/2+7/3+...+1/9
B=1/2+1/3+1/4+...+1/10
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Tìm thương A:B, biết:
A= 9/1 + 8/2 + 7/3 + 6/4 + 5/5 + 4/6 + 3/7 + 2/8 + 1/9
B=1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 + 1/9 + 1/10
\(A=\frac{9}{1}+\frac{8}{2}+\frac{7}{3}+\frac{6}{4}+\frac{5}{5}+\frac{4}{6}+\frac{3}{7}+\frac{2}{8}+\frac{1}{9}\)
\(=\left(9-1-1-...1\right)+\left(\frac{8}{2}+1\right)+\left(\frac{7}{3}+1\right)+...+\left(\frac{1}{9}+1\right)\)
\(=1+\frac{10}{2}+\frac{10}{3}+...+\frac{10}{9}=\frac{10}{2}+\frac{10}{3}+...+\frac{10}{9}+\frac{10}{10}\)
\(=10\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}\right)=10B\)
vậy A:B=10
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Cho B=9/1+8/2+7/3+…+1/9 C=1/2+1/3+1/4+…+1/10
Tìm thương A:B
Tìm thương A:B biết:
\(A=\frac{9}{1}+\frac{8}{2}+\frac{7}{3}+...+\frac{1}{9};B=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}\)
A = \(10\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)\)
A : B = 10
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Bài 5: tìm thương A:B bt
A= 9/1+8/2+7/3+...+1/9
B=1/2+1/3+1/4+.....+1/10
Giúp mình với gấp lắm nha(chú ý / là dấu = của phân số nha)❤
Tìm thương A:B, biết:
\(A=\frac{9}{1}+\frac{8}{2}+\frac{7}{3}+...+\frac{1}{9}\)
\(B=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}\)
Tìm A:B, biết:
A=\(\frac{9}{1}+\frac{8}{2}+\frac{7}{3}+\frac{6}{4}+\frac{5}{5}+\frac{4}{6}+\frac{3}{7}+\frac{2}{8}+\frac{1}{9}\)
B=\(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{9}+\frac{1}{10}\)
\(\frac{A}{B}=\frac{\frac{9}{1}+\frac{8}{2}+\frac{7}{3}+\frac{6}{4}+\frac{5}{5}+\frac{4}{6}+\frac{3}{7}+\frac{2}{8}+\frac{2}{9}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}}\)
\(\frac{A}{B}=\frac{\left(\frac{8}{2}+1\right)+\left(\frac{7}{3}+1\right)+...+\left(\frac{1}{9}+1\right)+1}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}}\)
\(\frac{A}{B}=\frac{\frac{10}{2}+\frac{10}{3}+\frac{10}{4}+...+\frac{10}{9}+\frac{10}{10}}{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}}\)
\(\frac{A}{B}=\frac{10\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}\right)}{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}}\)
\(\frac{A}{B}=10\)
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\(A=\frac{9}{1}+\frac{8}{2}+\frac{7}{3}+...+\frac{2}{8}+\frac{1}{9}\)
Tách 9=1+1+...+1 ( có 9 số 1)
\(\Rightarrow A=1+\left(\frac{8}{2}+1\right)+\left(\frac{7}{3}+1\right)+...+\left(\frac{2}{8}+1\right)+\left(\frac{1}{9}+1\right)\)
\(A=\frac{10}{10}+\frac{10}{2}+\frac{10}{3}+...+\frac{10}{8}+\frac{10}{9}\)
\(A=10.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)\)
\(\Rightarrow A:B=\frac{10.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)}{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}}=10\) ( vì \(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\ne0\) )
Vậy \(A:B=10\)
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Tính:
a, 4 1/3 . 4/9 + 13 2/3 . 4/9
b, 5 1/4 . 3/8 + 10 3/4 . 3/8
c, 6 1/5 . ( -2/7 ) + 14 4/5 . ( -2/7 )
d, 7 1/6 . ( -7/6 ) + 10 5/6 . ( -7/6 )
Tìm thương A : B biết A=9/1+8/2+7/3+...+1/9 ; B=1/2+1/3+1/4+...+1/10
TÌM THƯƠNG A/B
A= 9/1 + 8/2 + 7/3 + 6/4 + 5/5 + 4/6 + 3/7 + 2/8 + 1/9
B=1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 + 1/9 + 1/10
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