\(\left|\frac{5}{2}-3x\right|=\left|-2,5x-1,2\right|\)
\(\Rightarrow\left|\frac{5}{2}-3x\right|-\left|-2,5x-1,2\right|=0\)

\(\Rightarrow\left(\frac{5}{2}-3x\right)-\left(-2,5x-1,2\right)=0\)

\(\Rightarrow\frac{5}{2}-3x+2,5x+1,2=0\)

\(\Rightarrow\left(\frac{5}{2}+1,2\right)+\left(-3x+2,5x\right)=0\)

\(\Rightarrow\frac{37}{10}-0,5x=0\)

\(\Rightarrow0,5x=\frac{37}{10}\)

\(\Rightarrow x=\frac{37}{5}\)

lớp 6 đâu có học bài này??

=))

\(\left|\frac{5}{2}-3x\right|=\left|-2,5x-1,2\right|\)

\(\Rightarrow\left|\frac{5}{2}-3x\right|-\left|2,5x-1,2\right|=0\)

\(\Rightarrow\left(\frac{5}{2}-3x\right)-\left(2,5x-1,2\right)=0\)

đến đây tự lm

| 5/2 - 3x | = | -2/5x - 1/2 |

| 5/2 - 3x | - | -2/5x - 1/2 | = 0

Mà GTTĐ luôn lớn hơn hoặc bằng 0

+) 5/2 - 3x = 0

3x = 5/2

x = 5/6

+) -2/5x - 1,2 = 0

-2/5x = 1,2

x = -3

Vậy,...........

ko biết có giữ lời không ta !?? ^^

em ko giai duoc ,em lop 2

-3/2 - | 3x + 4 |.2/5= 2

<=> | 3x + 4 | = (2+3/2)/(2/5)

<=>  | 3x + 4 | = 35/4

<=>3x + 4 =35/4

Hoặc 3x + 4 = - 35/4

Tự giải nốt nha

\(|3x+4|.\frac{2}{5}=\frac{-3}{2}-2\)

\(|3x+4|.\frac{2}{5}=\frac{-7}{2}\)

\(|3x+4|=\frac{-7}{2}:\frac{2}{5}\)

\(|3x+4|=\frac{-35}{4}\)

\(\Leftrightarrow3x+4=\frac{-35}{4}\)        hoặc          \(3x+4=\frac{35}{4}\)

         x=\(\frac{-17}{4}\)                                                x=\(\frac{19}{12}\)

Vậy x=\(\frac{-17}{4}\) hoặc    x= \(\frac{19}{12}\)

|-1,3.x+1/2| = |-5/6+0,2.x|

TH1: -1,3.x+1/2 = -5/6+0,2.x

=> -1,3.x - 0,2.x = -5/6 - 1/2 

-1,5.x = -4/3

x = -8/9

TH2: -1,3.x+1/2 = 5/6-0,2.x

=> -1,3.x + 0,2.x = 5/6-1/2

-1,1.x = 1/3

x =  -10/33

KL:...

\(\left|-\frac{2}{5}x-\frac{4}{3}\right|=\left|4x-\frac{5}{6}\right|\)

\(=-\frac{2x}{5}-\frac{4}{3}=4x-\frac{5}{6}\)

\(=-\frac{2x}{5}-\frac{4}{3}=-\left(4x-\frac{5}{6}\right)\)

\(=x=-\frac{5}{44};\frac{65}{108}\)

\(\Rightarrow x=\orbr{\begin{cases}x=-\frac{5}{44}\\x=\frac{65}{108}\end{cases}}\)

|−25 x−43 |=|4x−56 |

=−2x5 −43 =4x−56 

=−2x5 −43 =−(4x−56 )

=x=−544 ;65108 

⇒x=[

mình thiếu dấu gạch p/s sorry

5/8 + 0,2 : |-x/4 + 2/5| = 3/2

         0,2 : |-x/4 + 2/5| = 3/2 - 5/8 

         0,2 : |-x/4 + 2/5| = 7/8

                 |-x/4 + 2/5| = 7/8 . 0,2

                 |-x/4 + 2/5| = 7/40

\(\Rightarrow\orbr{\begin{cases}-\frac{x}{4}+\frac{2}{5}=\frac{7}{40}\\-\frac{x}{4}+\frac{2}{5}=-\frac{7}{40}\end{cases}\Rightarrow\orbr{\begin{cases}-\frac{x}{4}=-\frac{9}{40}\\-\frac{x}{4}=-\frac{23}{40}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{9}{10}\\x=\frac{23}{10}\end{cases}}}\)

 Báo cáo sai phạm

5/8 + 0,2 : |-x/4 + 2/5| = 3/2

         0,2 : |-x/4 + 2/5| = 3/2 - 5/8 

         0,2 : |-x/4 + 2/5| = 7/8

                 |-x/4 + 2/5| = 7/8 . 0,2

                 |-x/4 + 2/5| = 7/40

⇒[

⇒[

⇒[

\(\frac{5}{8}+0,2:\left|\frac{-x}{4}+\frac{2}{5}\right|=\frac{3}{2}\)

\(\Leftrightarrow\frac{33}{40}:\left|\frac{-x}{4}+\frac{2}{5}\right|=\frac{3}{2}\)

\(\Leftrightarrow\left|\frac{-x}{4}+\frac{2}{5}\right|=\frac{33}{40}:\frac{3}{2}\)

\(\Leftrightarrow\left|\frac{-x}{4}+\frac{2}{5}\right|=\frac{11}{20}\)

\(\Leftrightarrow\hept{\begin{cases}\Leftrightarrow\frac{-x}{4}+\frac{2}{5}=-\frac{11}{20}\\\Leftrightarrow\frac{-x}{4}+\frac{2}{5}=\frac{11}{20}\end{cases}}\Leftrightarrow\hept{\begin{cases}-\frac{x}{4}=\frac{-19}{20}\\\frac{-x}{4}=\frac{3}{20}\end{cases}\Leftrightarrow}\hept{\begin{cases}-x=-3,8\\-x=0,6\end{cases}}\Leftrightarrow\hept{\begin{cases}x=3,8\\x=-0,6\end{cases}}\)

Vậy :  \(x=3,8\) hoặc \(x=-0,6\)

\(\frac{7}{12}-0,75:\left(4x-3\right)^2=\frac{-3}{2}\)

\(\frac{3}{4}:\left(4x-3\right)^2=\frac{25}{12}\)

\(\left(4x-3\right)^2=\frac{9}{25}=\left(\frac{\pm3}{5}\right)^2\)

+) 4x - 3 = 3/5

4x = 18/5

x = 9/10

+) 4x - 3 = -3/5

4x = 12/5

x = 3/5

Vậy,.........

\(\frac{7}{12}-0,75:\left(4x-3\right)^2=-\frac{3}{2}\)

\(\Leftrightarrow\frac{7}{12}.12\left(4x-3\right)^2-\frac{0,75}{\left(4x-3\right)^2}.12\left(4x-3\right)^2=-\frac{3}{2}.12\left(4x-3\right)^2\)

\(\Leftrightarrow7\left(4x-3\right)^2-9=-18\left(4x-3\right)^2\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{9}{10}\\x=\frac{3}{5}\end{cases}}\)

\(\frac{7}{12}-0,75:\left(4x-3\right)^2=\frac{-3}{2}\)

\(0,75:\left(4x-3\right)^2=\frac{7}{12}-\frac{-3}{2}\)

\(0,75:\left(4x-3\right)=\frac{7+18}{12}\)

\(0,75:\left(4x-3\right)=\frac{25}{12}\)

\(\frac{3}{4}:\left(4x-3\right)=\frac{25}{12}\)

\(4x-3=\frac{3}{4}:\frac{25}{12}\)

\(4x-3=\frac{3.12}{4.25}=\frac{9}{25}\)

\(4x=\frac{9}{25}+3\)

\(4x=\frac{9+75}{25}\)

\(4x=\frac{84}{25}\)

\(x=\frac{84}{25}:4\)

\(x=\frac{84.1}{25.4}\)

\(x=\frac{21}{25}\)

Vậy \(x=\frac{21}{25}\)

a. \(3-4x\left(25-2x\right)-8x^2+x-300=0\)

\(\Leftrightarrow3-100x+8x^2-8x^2+x-300=0\)

\(\Leftrightarrow-297-99x=0\)

\(\Leftrightarrow x=3\)

Vậy \(n_0\) của PT là: x=3

b. \(\Leftrightarrow\frac{\left(2-6x\right)}{5}-2+\frac{3x}{10}=7-\frac{3x+3}{4}\)

\(\Leftrightarrow\frac{\left(4-12x\right)}{5}-\frac{20}{10}+\frac{3x}{10}=\frac{\left(28-3x-3\right)}{4}\)

\(\Leftrightarrow\frac{\left(-16-9x\right)}{10}=\frac{\left(25-3x\right)}{4}\)

\(\Leftrightarrow-64-36x=250-30x\)

\(\Leftrightarrow-6x=314\)

\(\Leftrightarrow x=-\frac{157}{3}\)

Vậy -\(n_0\) của PT là: \(x=\frac{-157}{3}\)

c. \(5x+\frac{2}{6}-8x-\frac{1}{3}=4x+\frac{2}{5}-5\)

\(\Leftrightarrow-3x=4x-\frac{23}{5}\)

\(\Leftrightarrow7x=\frac{23}{5}\)

\(\Leftrightarrow x=\frac{23}{35}\)

Vậy \(n_0\) của PT là: \(x=\frac{23}{35}\)

d. \(3x+\frac{2}{3}-3x+\frac{1}{6}=2x+\frac{5}{3}\)

\(\Leftrightarrow\frac{5}{6}=2x+\frac{5}{3}\)

\(\Leftrightarrow x=-\frac{5}{12}\)

Vậy \(n_0\) của Pt là: \(x=-\frac{5}{12}\)