\(B=\frac{4^2.25^2+32.125}{2^3.5^2}\)

   \(=\frac{\left(2^2\right)^2.\left(5^2\right)^2+2^5.5^3}{2^3.5^2}\)

   \(=\frac{2^4.5^4+2^5.5^3}{2^3.5^2}\)

   \(=\frac{2^3.5^2.\left(2.5^2+2^2.5\right)}{2^3.5^2}\)

   \(=2.5^2+2^2.5\)

   \(=2.25+4.5\)

\(=50+20=70\)

\(B=\frac{2^4.5^4+2^5.5^3}{2^3.5^2}=\frac{2^4.5^3\left(5+2\right)}{2^3.5^2}=2.5.7=70\)

thanks nhiều

\(B=\frac{4^2.25^2+32.125}{2^3.5^2}=\frac{2^4.5^4+2^5.5^3}{2^3.5^2}\)

  \(=\frac{2^4.5^3\left(5+2\right)}{2^3.5^2}=\frac{2^3.5^2.2.5.7}{2^3.5^2}=2.5.7=70\)

\(B=\frac{4^2.25^2+32.125}{2^3.5^2}\)

\(\Rightarrow B=\frac{2^3.5^3+2^5.5^3}{2^3.5^2}\)

\(\Rightarrow B=???\)

Để tính B bn rút gọn các số theo hàng chéo 

VD : 2^3 (phân số) rút gọn vs 2^3 (mẫu số)

tíc mình nha

= 14000 / 200

= 70 

Trả lời :

\(B=\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}=\frac{\left(2^2\right)^2\cdot\left(5^2\right)^2+2^5\cdot5^3}{2^3\cdot5^2}=\frac{2^4\cdot5^4+2^5\cdot5^3}{2^3\cdot5^2}=\frac{2^3\cdot5^2\left(2\cdot5^2+2^3\cdot5\right)}{2^3\cdot5^2}\)

\(=2\cdot5^2+2^3\cdot5=2\cdot25+8\cdot5=50+40=90\)

\(B=\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}\)

\(B=\frac{2^4\cdot5^4+2^5\cdot5^3}{2^3\cdot5^2}\)

\(B=\frac{2^4\cdot5^3\left(5+2\right)}{2^3\cdot5^2}\)

\(B=\frac{2^4\cdot5^3\cdot7}{2^3\cdot5^2}\)

B = 2 . 5 . 7

B = 70

Không chắc =))

\(B=\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}\)

\(\Rightarrow B=\frac{\left(2^2\right)^2\cdot\left(5^2\right)^2+2^5\cdot5^3}{2^3\cdot5^2}\)

\(\Rightarrow B=\frac{2^4\cdot5^4+2^5\cdot5^3}{2^3\cdot5^2}\)

\(\Rightarrow B=\frac{2^3\cdot5^2\cdot\left(2\cdot5^2+2^2\cdot5\right)}{2^3\cdot5^2}\)

\(\Rightarrow B=2\cdot5^2+2^2\cdot5\)

\(\Rightarrow B=2\cdot25+4\cdot5\)

\(\Rightarrow B=50+20\)

\(\Rightarrow B=70\)

\(\dfrac{4^2.25^2+32.125}{2^3.5^2}=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}=\dfrac{2^3.5^2\left(2.5^2+2^2.5\right)}{2^3.5^2}=2.5^2+2^2.5=50+20=70\)

\(\dfrac{4^2.25^2+32.125}{2^3.5^2}=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}=\dfrac{2^4.5^3\left(5+2\right)}{2^3.5^2}=2.5\left(5+2\right)=10.7=70\)

\(\dfrac{4^2.25^2+32.125}{2^3.5^2}\)

\(=\dfrac{\left(2^2\right)^2.\left(5^2\right)^2+2^5.5^3}{2^3.5^2}\)

\(=\dfrac{2^4.5^4+2^5.5^3}{2^3.5^2}\)

\(=\dfrac{2^3.5^2\left(2.5^2+2^2.5\right)}{2^3.5^2}\)

\(=2.5^2+2^2.5\)

\(=2.25+4.5=50+20=70\)