\(\frac{-2011}{2012}\): (\(\frac{1999}{2011}\)-\(\frac{2011}{2012}\)) + \(\frac{1999}{2011}\):(\(\frac{-2011}{2012}\)+\(\frac{1999}{2011}\))
Những câu hỏi liên quan
\(\frac{-2011}{2012}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}+\frac{1999}{2011}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}=?\)
Ai đó giúp mình giải nha, cảm ơn
Bạn chỉ giùm mình từng bước nha, cảm ơn
Đúng 0
Bình luận (0)
Mọi người giải giúp mình nha, xin cảm ơn
\(\frac{-2011}{2012}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}+\frac{1999}{2011}:\left\{\frac{1999}{2011}-\frac{2011}{2012}\right\}\)
Rút gọn \(\left(-\frac{2011}{2012}\right)\):\(\left(\frac{1999}{2011}-\frac{2011}{2012}\right)+\frac{1999}{2011}\):\(\left(-\frac{2011}{2012}+\frac{1999}{2011}\right)\)
So sánh A và B trong những trường hợp sau:
a) A = \(\frac{-2012}{4025}\); B = \(\frac{-1999}{3997}\)
b) A = \(\frac{2011}{1.2}+\frac{2011}{3.4}+...+\frac{2011}{1999.2000}\); B = \(\frac{2012}{1001}+\frac{2012}{1002}+...+\frac{2012}{2000}\)
Ta có:
A=-2012/4025=>-2012/4025x2=-4024/4025
B=-1999/3997=>-1999/3997x2=-3998/3997
Ta có: 4024/4025<1<3998/3997
=>4024/4025<3998/3997
=>-4024/4025>-3998/3997
=>-2012/4025>-1999/3997
Đúng 0
Bình luận (0)
Có ai biết làm câu b) ko vậy, mình ko biết làm, giúp mình với!!
1. Tinh a left(6^9.2^{10}+12^{10}right)+left(2^{19}.27^3+15.4^9.9^4right)2. So sanh A va B.a) Afrac{-2012}{4025};Bfrac{-1999}{3997}b) A3^{21};B2^{31}c) Afrac{2011}{1.2}+frac{2011}{3.4}+frac{2011}{5.6}+....+frac{2011}{1999.2000};Bfrac{2012}{1001}+frac{2012}{1002}+frac{2012}{1003}+....+frac{2012}{2000}
Đọc tiếp
1. Tinh a \(\left(6^9.2^{10}+12^{10}\right)+\left(2^{19}.27^3+15.4^9.9^4\right)\)
2. So sanh A va B.
a) \(A=\frac{-2012}{4025};B=\frac{-1999}{3997}\)
b) \(A=3^{21};B=2^{31}\)
c) \(A=\frac{2011}{1.2}+\frac{2011}{3.4}+\frac{2011}{5.6}+....+\frac{2011}{1999.2000};\)\(B=\frac{2012}{1001}+\frac{2012}{1002}+\frac{2012}{1003}+....+\frac{2012}{2000}\)
1/ (69.210+1210)+(219.273+15.49.94) = 29.39.210+310.220+219.39+5.3.218.38 = 219.39+310.220+219.39+5.218.39
= 218.39(2+3.22+5)=19.218.39
Đúng 0
Bình luận (0)
sao bạn lại nhắn vớ va vớ vậy PHẠM ĐỨC PHÚC
Đúng 0
Bình luận (0)
1/ (69
.210+1210
)+(219
.273+15.49
.94
) = 29
.39
.210+310
.220+219
.39+5.3.218
.38
= 219
.39+310
.220+219
.39+5.218
.39
= 2
18
.39
(2+3.22+5)=19.218
.39
Không tính cụ thể , hãy sắp xếp các biểu thức sau theo thứ tự giảm dần :frac{frac{2010}{2011}}{frac{2012}{2013}}+frac{frac{2011}{2012}}{frac{2013}{2014}}+frac{frac{2012}{2013}}{frac{2014}{2015}}frac{frac{2010}{2011}+frac{2011}{2012}+frac{2012}{2013}}{frac{2012}{2013}+frac{2013}{2014}+frac{2014}{2015}}frac{frac{2010+2011+2012}{2011+2012+2013}}{frac{2012+2013+2014}{2013+2014+2015}}frac{frac{2010}{2011}+frac{2011}{2012}+frac{2012}{2013}}{frac{2012+2013+2014}{2013+2014+2015}}frac{frac{2010+2011+2012...
Đọc tiếp
Không tính cụ thể , hãy sắp xếp các biểu thức sau theo thứ tự giảm dần :
\(\frac{\frac{2010}{2011}}{\frac{2012}{2013}}+\frac{\frac{2011}{2012}}{\frac{2013}{2014}}+\frac{\frac{2012}{2013}}{\frac{2014}{2015}}\)
\(\frac{\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}}{\frac{2012}{2013}+\frac{2013}{2014}+\frac{2014}{2015}}\)
\(\frac{\frac{2010+2011+2012}{2011+2012+2013}}{\frac{2012+2013+2014}{2013+2014+2015}}\)
\(\frac{\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}}{\frac{2012+2013+2014}{2013+2014+2015}}\)
\(\frac{\frac{2010+2011+2012}{2011+2012+2013}}{\frac{2012}{2013}+\frac{2013}{2014}+\frac{2014}{2015}}\)
$\frac{\frac{2010}{2011}}{\frac{2012}{2013}}+\frac{\frac{2011}{2012}}{\frac{2013}{2014}}+\frac{\frac{2012}{2013}}{\frac{2014}{2015}}$
$\frac{\frac{2010}{2011}}{\frac{2012}{2013}}+\frac{\frac{2011}{2012}}{\frac{2013}{2014}}+\frac{\frac{2012}{2013}}{\frac{2014}{2015}}$
$\frac{\frac{2010+2011+2012}{2011+2012+2013}}{\frac{2012+2013+2014}{2013+2014+2015}}$
$\frac{\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}}{\frac{2012+2013+2014}{2013+2014+2015}}$
$\frac{\frac{2010+2011+2012}{2011+2012+2013}}{\frac{2012}{2013}+\frac{2013}{2014}+\frac{2014}{2015}}$
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
$A=\frac{2011}{1.2}+\frac{2011}{3.4}+\frac{2011}{5.6}+...+\frac{2011}{1999.2000}$
$B=\frac{2012}{1001}+\frac{2012}{1002}+\frac{2012}{1003}+...\frac{2012}{2000}$
\(S=\sqrt{1+2010^2+\frac{2010^2}{2011^2}}+\frac{2010}{2011}+\sqrt{1+2011^2+\frac{2011^2}{2012^2}}+\frac{2011}{2012}+\sqrt{1+2012^2+\frac{2012^2}{2013^2}}+\frac{2012}{2013}\)
So sanh P va Q
P=\(\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}\)
Q=\(\frac{2010+2011+2012}{2011+2012+2013}\)
Xem thêm câu trả lời