phan tich da thuc thanh nhan tu 4x^2 - y ^2+8(y-2)
phan tich da thuc thanh nhan tu 4x^2-y^2+8(y-2)
=4x2-y2+8y-16
=4x2-(y2 - 8y+16)
=4x2-(y-4)2
=(2x+y-4)(2x-y+4)
4x2-y2+8(y-2)
=4x2-y2+8.y-8.2
=4x2-y2+8y-16
phan tich da thuc thanh nhan tu
x^2-x-y^2-y
x^2-2xy+y^2-z^2
bai 32 va 33 sbt
lop 8 bai phan tich da thuc thanh nhan tu bang cach nhom hang tu
Ta có
a, x2-x-y2-y
=x2-y2-(x+y)
=(x-y)(x+y) - (x+y)
=(x+y)(x-y-1)
b, x2-2xy+y2-z2
=(x-y)2-z2
=(x-y-z)(x-y+z)
con bai 32, 33 neu ban tra loi duoc minh h them
phan tich da thuc thanh nhan tu:
4x^4-21x^2y^2+y^4
4x4 - 21 x2y2 + y4
= (4x4 + 4x2y2 + y4) - 25x2y2
= [(2x2)2 + 2x2 . 2 . y2 + (y2)2] - 25x2y2
= (2x2 + y2) - 25x2y2
= (2x2 + y2 - 5xy) (2x2 + y2 + 5xy)
phan tich da thuc sau thanh nhan tu (bang cach dat nhan tu chung)
(4x-y)(a+b)(4x-y)(c-1)
\((4x-y)(a+b)(4x-y)(c-1)\)
\(=\left(4x-y\right)\left(4x-y\right)=\left(4x-y\right)^{1+1}=\left(4y-2\right)^2\)
\(=\left(a+b\right)\left(4x-y\right)^2\left(c-1\right)\)
(4x-y)(a+b)(4x-y)(c-1)
= ( 4x - y ) ( 4x - y ) = ( 4x - y ) 1 + 1 = ( 4y - 2 ) 2
= (a + b ) ( 4x - y )2 ( c - 1 )
Bài giải :
(4x-y)(a+b)(4x-y)(c-1)
= ( 4x - y ) ( 4x - y ) = ( 4x - y ) 1 + 1
= ( 4y - 2 ) 2
= (a + b ) ( 4x - y )2 ( c - 1 )
1. x2-4x-y2+4
2. (x-y)2-(x+y)2
Phan tich da thuc thanh nhan tu
1. = (x-2)^2 - y^2 = (x - 2 - y)(x-2+y)
2. = (x-y-x-y)(x-y+x+y) = 2(-y)2x = -4xy
(x^2+x)^2+4x^2+4x-12 phan tich da thuc thanh nhan tu
4x^2-36x+56 phan tich da thuc thanh nhan tu
4x2 - 36x + 56
= 4x2 - 28x - 8x + 56
= ( 4x2 - 28x ) - ( 8x - 56 )
= 4x( x - 7 ) - 8( x - 7 )
= ( x - 7 )( 4x - 8 )
= 4( x - 7 )( x - 2 )
4x^2-4x+1
phan tich da thuc thanh nhan tu chung
\(4x^2-4x+1\)\(=\) \((2x^2)-2.2x.1+1^2\)
\(=\left(2x-1\right)^2\)
Học tốt!
phan tich da thuc thanh nhan tu: 4x^4-32x^2+1
4x^4 - 32x^2 +1 = 4x^4 + 4x^2 +1 - 36x^2 = (2x^2 + 1)^2 - 36x^2 = (2x^2 - 6x + 1)(2x^2 + 6x + 1)
4 x4 - 32 x2 + 1
= ( 2 x2 )2 - 2 . 2x2. 8 + 64 - 63
= ( 2 x2 - 8 )2 - 63
= ( 2x2 - 8 + √63 ) ( 2x2 - 8 - √63 )
Xong