1x1=
1x2=
1x3=
(a - 19.99) : 2 = 1x1+1x2+1x3+1x4+...+9x7+9x8+9x9
Tìm a
(a - 19.99) : 2 = 1 x 1 + 1 x 2 + 1 x 3 + 1 x 4 +...+ 9 x 7 + 9 x 8 + 9 x 9
(a - 19.99) : 2 = 1 x (1 + 2 + 3 + 4 + 5 + 6 + 7 )
Á Xl, mình ấn nhầm nhé '-' Câu trl k đúng đâu !!
xong chưa????????????????
A=1x2+2x3+3x4+...+49x50
B=1x3+3x5+5x7+...+99x101
C=1x2x3+2x3x4+3x4x5+...+50x51x52
D=1x4+2x5+3x6+...+60x63
E=1x1+2x2+3x3+...+50x50
F=1x1+3x3+5x5+...+71x71
G=1x1+4x4+7x7+...+100x100
I=1x2x3+3x4x5+5x6x7+...+69x70x71
A=1x2+2x3+3x4+...+49x50
3A= 3(1.2+2.3+3.4+...+49.50)
3A= 1.2.3+2.3.3+3.4.3+...+49.50.3
3A= 1.2.(3-0)+2.3(4-1)+3.4(5-2)+...+49.50.(51-48)
3A= 0.1.2-1.2.3+1.2.3-2.3.4+2.3.4-3.4.5+...+48.49.50-49.50.51
3A= 49.50.51
A= 49.50.51/3=41650
B=1x3+3x5+5x7+...+99x101
B=1/1.3 +1/3.5 +...+1/99.101
2B=2/1.3 + 2/3.5 +...+2/99.101
2B=1-1/3+1/3-1/5+...+1/99-1/101
2B=1-1/101
2B=100/101
B=100/101:2=100/202
C=1x2x3+2x3x4+3x4x5+...+50x51x52
Nhân C với 4 ta được:
C x 4 = 1x2x3x4 + 2x3x4x 4 + 3x4x5x4 +…+50x51x52x4
C x 4 = 1x2x3x4 + 2x3x4x(5-1) + 3x4x5x(6-2) + ... + 50x51x52x(53-49)
C x 4 = 1x2x3x4 + 2x3x4x5 - 1x2x3x4 + 3x4x5x6 - 2x3x4x5 + ... +49x 50x51x52 - 50x51x52x53
Sau khi cộng - trừ giản ước ta có : C x 4 = 50x51x52x53
C = 50x51x52x53 : 4 = 1756950
1+1x2+1x0+1x1=?
1x1+1X2+3X1+5=
1*1+ 1* 2 + 3* 1 + 5 = 1 + 2 + 3 + 5
= 11
1+1:1x1+1-1:1x2
\(1+1\div1\times1+1-1\div1\times2=1\)
1x1+2=?
Vậy 1x2+1
1+1x2=?
vậy: 1x1+2 bằng mấy?
l i m x → - 1 x 3 + 1 x 2 + x bằng:
A. -3
B. -1
C. 0
D. 1
Chọn A
lim x → − 1 x 3 + 1 x 2 + x = lim x → − 1 x + 1 x 2 − x + 1 x x + 1 = lim x → − 1 x 2 − x + 1 x = − 3
l i m x → 1 x 3 + 1 x 2 + x bằng:
A. -3
B. -1
C. 0
D. 1