Bạn tự hỏi rồi từ trả lời ! Bạn xem đầu bạn có nóng không ?

olm ko cho tự hỏi tự trả lời đâu nhoa.

`Answer:`

\(A=\left(1^{100}+2^{100}+...+10^{100}\right)\left(5^{10}-25^5\right)\)

\(=\left(1^{100}+2^{100}+...+10^{100}\right)[5^{10}-\left(5^2\right)^5]\)

\(=\left(1^{100}+2^{100}+...+10^{100}\right)\left(5^{10}-5^{10}\right)\)

\(=\left(1^{100}+2^{100}+...+10^{100}\right).0\)

\(=0\)

\(B=\left(2^5+3^5+4^5\right)\left(1^2+2^2+...+100^2\right)\left(4^{10}-2^{20}\right)\)

\(=\left(2^5+3^5+4^5\right)\left(1^2+2^2+...+100^2\right)\left(2^{2.10}-2^{20}\right)\)

\(=\left(2^5+3^5+4^5\right)\left(1^2+2^2+...+100^2\right).0\)

\(=0\)

687+(2×5)+10

=687+10+10

=697+10

=707

`687 + (2 × 5) + 10`

`= 687 + 10 + 10`

`= 697 + 10`

`= 707`

687+(2x5)+10= 687+10+10=707

ghi sai đề ak, có 2 dấu trừ ở phép số 2

\(\frac{5}{4.7}+\frac{5}{7.10}+\frac{5}{10.13}+...+\frac{5}{97.100}\)

\(=5\left(\frac{1}{4.7}+\frac{1}{7.10}+\frac{1}{10.13}+...+\frac{1}{97.100}\right)\)

\(=5.\frac{1}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{97}-\frac{1}{100}\right)\)

\(=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{100}\right)\)

\(=\frac{2}{5}\)

thank you

x-10+5=100

x-10=100-5

x-10=95

x=95+10

x=105

tìm x:

a

x - 10 + 5 = 100

x - 10 =100-5=95

x=95+10=105

b

x + 10 - 5 = 100

x + 10 = 100 + 5 = 105

x = 105 - 10 = 95

tích mik ủng hộ nha bà con cô bác ơi

tìm x:

a 

x - 10 + 5 = 100

x - 10 =100-5=95

x=95+10=105

b

x + 10 - 5 = 100

x + 10 = 100 + 5 = 105

x = 105 - 10 = 95

tích mik ủng hộ nha bà con cô bác ơi

1)50+50+50+100/5

=50+50+50+20

=100+70

=170

2)100/100+20/10+5

=1+2+5

=3+5

=8

3)200/100+50/10+6

=2+5+6

=7+6

=13

minh tr nha ban

`Answer:`

\dfrac15+\dfrac1{5+10}+\dfrac1{5+10+15}\ +\,.\!.\!.+\ \dfrac1{5+10+15\ +\,.\!.\!.+\ 100}\\=\dfrac15+\dfrac1{5.(1+2)}+\dfrac1{5.(1+2+3)}\ +\,.\!.\!.+\ \dfrac1{5.(1+2+3\ +\,.\!.\!.+\ 20)}\\=\dfrac15\left(1+\dfrac1{1+2}+\dfrac1{1+2+3}\ +\,.\!.\!.+\ \dfrac1{1+2+3\ +\,.\!.\!.+\ 20}\right)\\=\dfrac15\bigg(\dfrac22+\dfrac26+\dfrac2{12}\ +\,.\!.\!.+\ \dfrac2{20.21}\bigg)\\=\dfrac25\left(\dfrac1{1.2}+\dfrac1{2.3}+\dfrac1{3.4}\ +\,.\!.\!.+\ \dfrac1{20.21}\right)\\=\dfrac25\left(1-\dfrac12+\dfrac12-\dfrac13+\dfrac13-\dfrac14\ +\,.\!.\!.+\ \dfrac1{20}-\dfrac1{21}\right)\\=\dfrac25\left(1-\dfrac1{21}\right)\\=\dfrac25\!\cdot\!\dfrac{20}{21}\\=\dfrac8{21}

`Answer:`

Mình gửi lại bài nhé. Mong lần này không bị lỗi như lần trước.

\(\dfrac15+\dfrac1{5+10}+\dfrac1{5+10+15}\ +\,.\!.\!.+\ \dfrac1{5+10+15\ +\,.\!.\!.+\ 100}\\=\dfrac15+\dfrac1{5.(1+2)}+\dfrac1{5.(1+2+3)}\ +\,.\!.\!.+\ \dfrac1{5.(1+2+3\ +\,.\!.\!.+\ 20)}\\=\dfrac15\left(1+\dfrac1{1+2}+\dfrac1{1+2+3}\ +\,.\!.\!.+\ \dfrac1{1+2+3\ +\,.\!.\!.+\ 20}\right)\\=\dfrac15\bigg(\dfrac22+\dfrac26+\dfrac2{12}\ +\,.\!.\!.+\ \dfrac2{20.21}\bigg)\\=\dfrac25\left(\dfrac1{1.2}+\dfrac1{2.3}+\dfrac1{3.4}\ +\,.\!.\!.+\ \dfrac1{20.21}\right)\\=\dfrac25\left(1-\dfrac12+\dfrac12-\dfrac13+\dfrac13-\dfrac14\ +\,.\!.\!.+\ \dfrac1{20}-\dfrac1{21}\right)\\=\dfrac25\left(1-\dfrac1{21}\right)\\=\dfrac25\!\cdot\!\dfrac{20}{21}\\=\dfrac8{21}\)

Đáp án C nhé 

Chữ số 5 trong số thập phân 62,359 có giá trị là bao nhiêu?

A.5

B. 5/10

C.5/100

D.5/100

Chữ số 5 trong số thập phân 62,359 có giá trị là bao nhiêu?

A.5

B. 5/10

C.5/100

D.5/100

Chúc học tốt!