Tính
P= \(\sqrt{1+999^2+\dfrac{999^2}{1000^2}}\)+\(\dfrac{999}{1000}\)
Những câu hỏi liên quan
tính: \(x=\sqrt{1+999^2+\dfrac{999^2}{1000^2}}+\dfrac{999}{1000}\)
Áp dụng \(\sqrt{1+\dfrac{1}{n^2}+\dfrac{1}{\left(n+1\right)^2}}=1+\dfrac{1}{n}-\dfrac{1}{n+1}\) ta có:
\(x=\sqrt{1+\dfrac{1}{\left(\dfrac{1}{999}\right)^2}+\dfrac{1}{\left(\dfrac{1}{999}+1\right)^2}}+\dfrac{999}{1000}=1+\dfrac{1}{\dfrac{1}{999}}-\dfrac{1}{\dfrac{1}{999}+1}+\dfrac{999}{1000}=1+999-\dfrac{999}{1000}+\dfrac{999}{1000}=1000\)
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Tính A biết \(A=\dfrac{1000}{1}+\dfrac{999}{2}+\dfrac{998}{3}+...+\dfrac{2}{999}+\dfrac{1}{1000}\)
Yêu cầu bài toán chỉ đơn thuần tính cái này thôi à em!
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Tính: \(\left(\dfrac{1000}{1}+\dfrac{999}{2}+\dfrac{998}{3}+...+\dfrac{2}{999}+\dfrac{1}{1000}\right):\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{1001}\right)\)
Tính: \(\left(\dfrac{1000}{1}+\dfrac{999}{2}+\dfrac{998}{3}+...+\dfrac{2}{999}+\dfrac{1}{1000}\right):\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{1001}\right)\)
Tính A biết \(A=\dfrac{1000}{1}+\dfrac{999}{2}+\dfrac{998}{3}+...+\dfrac{2}{999}+\dfrac{1}{1000}\)
Tính : A=\(\sqrt{1+999^2+\frac{999^2}{1000^2}}+\frac{999}{1000}\)
Tính M=\(\sqrt{1+999^2+\frac{999^2}{1000^2}}\)+\(\frac{999}{1000}\)
Tính nhanh : \(\dfrac{1}{1}.\dfrac{1}{2}+\dfrac{1}{2}.\dfrac{1}{3}+\dfrac{1}{3}.\dfrac{1}{4}+...+\dfrac{1}{998}.\dfrac{1}{999}+\dfrac{1}{999}.\dfrac{1}{1000}\)
\(\dfrac{1}{1}.\dfrac{1}{2}+\dfrac{1}{2}.\dfrac{1}{3}+\dfrac{1}{3}.\dfrac{1}{4}+...+\dfrac{1}{999}.\dfrac{1}{1000}\\ =\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{999.1000}\\ =1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{999}-\dfrac{1}{1000}\\ =1-\dfrac{1}{1000}=\dfrac{999}{1000}\)
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ta có
1/1.1/2=1-1/2
1/2.1/3=1/2-1/3
1/3.1/4=1/3-1/4
............
1/999.1/1000=1/999-1/1000
Từ đó suy ra
1/1.1/2+1/2-1/3+1/3+.......+1/998.1/999+1/999.1/1000
=1/1-1/2+1/2-1/3+1/3-.....+1/998-1/999+1/999-1/1000
=1-1/1000
=1000/1000-1/1000
=999/1000
nhớ like bạn nhé
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Tính nhanh : \(\frac{1}{\sqrt{1}+\sqrt{2}}+\frac{1}{\sqrt[1]{2}+\sqrt[2]{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}+\frac{1}{\sqrt[3]{4}+\sqrt[4]{5}}+...+\frac{1}{\sqrt{999}+\sqrt{1000}}+\frac{1}{\sqrt[999]{1000}+\sqrt[1000]{1001}}\)