Viet ket qua sau ve dang luy thua
a) 2.4.16.32.1/8
b) 9.27.1/81.27
c) 4.64:(8.1/16)
Viet ket qua ve dang luy thua
a) 2.4.16.32.1/8
b) 9.27.1/81.27
c) 4.64: ( 8.1/16)
viet ket qua duoi dang luy thua 4^20 * 8^10
420 . 810
= 410+10 . 810
= 410 . 410 . 810
= (4 . 4 . 8)10
= 12810
VIET KET QUA SAU DUOI DANG LUY THUA CUA 1 SO TU NHIEN
8^9:2^3
VIET KET QUA SAU DUOI DANG LUY THUA CUA 1 SO TU NHIEN
8^9:2^3
trả lời :
89 : 23
= ( 23 ) 9 : 23
= 23 . 9 : 23
= 227 : 23
= 227 - 3
= 224
viet ket qua cac phep tinh sau duoi dang luy thua 329:64
\(32^9:64=\left(2^5\right)^9:2^6=2^{45}:2^6=2^{45-6}=2^{39}\)
viet ket qua phep tinh duoi dang luy thua
a, 4^2-8^5
b, 27^3.9^4
c, 64^3.167
Giải:
a) \(4^2.8^5=\left(2^2\right)^2.\left(2^3\right)^5=2^4.2^{15}=2^{19}\)
b) \(27^3.9^4=\left(3^3\right)^3.\left(3^2\right)^4=3^9.3^8=3^{17}\)
c) \(64^3.16^7=\left(4^3\right)^3.\left(4^2\right)^7=4^9.4^{14}=4^{23}\)
viet ket qua phep tinh duoi dang luy thua
a, 4^2-8^5
b, 27^3.9^4
c, 64^3.167
viet ket qua phep tinh sau duoi dang 1 luy thua
a, 2008^2000 : 2008^100
b, 2000^2001 : 2000
c, 16^2002 : 4^2
d, (2^2009 × 2^2001): ( 2^2008× 2^2000)
a) 20082000 : 2008100 = 20082000-100 = 20081900
b) 20002001 : 2000 = 20002001 : 20001 = 20002001-1 = 20002000
c) 162002 : 42 = (42)2002 : 42 = 44004 : 42 = 44004-2 = 44002
d) (22009.22001):(22008.22000) = (22009+2001):(22008+2000) = 24010 : 24008 = 24010-4008 = 22
a . 20082000-100
20081900
b. 20002001-1
20002000
c. 162002 : 4*4
162000 : 16
162000-1
161999
d.( 22009+2001 ) : ( 22008+2000 )
24010 : 24008
24010-4008
22
viet cac ket qua sau duoi dang 1 luy thua
a/ 35 :33
b/ 125:53
c/75:343
d/a12:a8
Viet ket qua moi phep tinh sau duoi dang mot luy thua
a 11^8:11^3
b 17^11:17^9
c 4^3:2^2
d a^5:a(a khac 0)