phan tich da thuc thanh nhan tu
a)a^2x+a^2y-7x-7y
b)x^4-x^3-x+1
c)x.(x+1)^2+x.(x-5)-5.(x+1)^2
d)a^3-a^2x-ay+xy
a, x^3-x^2-4x^2+8x-4
b, 4x^2-25-(2x-5)2x+7
c, x^3+27+(x+3)(x-9)
d, 2x^2-2y^2+5x-5y
e, x^2-y^2-2y-1
phan tich da thuc thanh nhan tu
Cach phan tich da thuc thanh nhan tu
a)X^3+2X^2+2X+1
b)X^3-4X^2+12X-27
c)a^6-a^4+2a^3+2a^2
d)x^4+2x^3+2x^2+2x+1
e)x^5+x^4+x^3+x^2+x+1
a)
=x3+x2+x2+x+x+1
=x2(x+1)+x(x+1)+(x+1)
=(x+1)(x2+x+1)
b)
=x3-3x2-x2+3x+9x-27
=x2(x-3)-x(x-3)+9(x-3)
=(x-3)(x2-x+9)
a)
=x3+x2+x2+x+x+1
=x2(x+1)+x(x+1)+(x+1)
=(x+1)(x2+x+1)
b)
=x3-3x2-x2+3x+9x-27
=x2(x-3)-x(x-3)+9(x-3)
=(x-3)(x2-x+9)
d)x^4+2x^3+2x^2+2x+1(no)
e)x^5+x^4+x^3+x^2+x+1 ( no)
phan tich da thuc thanh nhan tu
A=x^6-2x^5-4x^4+6x^3+4x^2-2x-1
x^3 - 2x^2y + xy^2
phan tich da thuc thanh nhan tu a
\(=x\left(x^2-2xy+y^2\right)=x\left(x-y\right)^2\)
phân tích cac da thuc sau thanh nhan tu:
a) x^3-2x^2 +2x -13
b) x^2y+xy +x +1
c) ax+by+ay+bx
d) x^2 -(a+b)x +ab
e) x^2y +xy^2 -x-y
f) ax^2 +ay-bx^2-by
bn post nhiều nên mình ghi đáp án thôi nhé phần nào sai đề mình cho qua
b)\(\left(x+1\right)\left(xy+1\right)\)
c)\(\left(a+b\right)\left(x+y\right)\)
d)\(\left(x-a\right)\left(x-b\right)\)
e)\(\left(x+y\right)\left(xy-1\right)\)
f)\(\left(a-b\right)\left(x^2+y\right)\)
phan tich da thuc thanh nhan tu :x^5+2x^4+3x^3+2x^2+2x+1
x^5+2x^4+2x^3+2x^2+2x+1
=(x^5+x^4)+(x^4+x^3)+(x^3+x^2)+(x^2+x)+(x+1)
=x^4(x+1)+x^3(x+1)+x^2(x+1)+x(x+1)+(x+1)
=(x+1)(x^4+x^3+x^2+x+1)
Phan tich da thuc thanh nhan tu
1) (2x+1)^2 - (x-1)^2
2) 9(x+3)^2 - 4(x-2)^2
3) 25(2x - y) ^2 - 16(x+2y)^2
4) x^4 + x^3 +x + 1
5) x^3 + 3x^2 + 3x + 1 -8y^3
Phan tich da thuc thanh nhan tu :
a) x^2 - x - y^2 - y
b) x^2 - 2 xy + y^2 - z^2
c) 5x - 5y + ax - ay
d) a^3 - a^2 x - ay + xy
e) 4x^2 - y^2 +4x + 1
a) x2-x-y2-y=(x2-y2)-(x+y)=(x+y)(x-y)-(x+y)=(x+y)(x-y-1)
b)x2-2xy+y2-z2=(x-y)2-z2=(x-y-z)(x-y+z)
c)5x-5y+ax-ay=5(x-y)+a(x-y)=(x-y)(5+a)
d)a3-a2x-ay+xy=a2(a-x)-y(a-x)=(a-x)(a2-y)
e)4x2-y2+4x+1=[(2x)2+2.2x.1+12]-y2=(2x+1)2-y2=(2x+1-y)(2x+1+y)
Chúc bạn học tốt!
phan tich da thuc thanh nhan tu
a, x^5+x-1
b, (x^2+3x+2)(x62+7x+12)-24
b ( x^2 + 3x + 2)( x^2 + 7x + 12) - 24
= [ x^2 +x + 2x + 2) ( x^2 +3x + 4x + 12) - 24
= [x(x+1) + 2 (x + 1) [x(x+3) + 4(x+3) ] - 24
= ( x + 1)(x+2) (x+3)(x+4) - 24
= ( x + 1).(x+4) (x+2)(x+3) - 24
=(x^2 + 5x + 4)(x^2+5x+6) - 24
Đặt x^2 + 5x +4 =y ta có:
= y(y+2) - 24
= y^2 + 2y - 24
= y^2 + 2y + 1 - 25
= ( y + 1)^2 - (5)^2
= ( y + 1 - 5 )( y + 1 + 5)
= ( y- 4)(y +6)
Thay y trở lại là đc
đúng nha