a)ta có xy=7*9=7*3*3

vậy x =9;21 , y=7;3

b) xy=-2*5

mà x<0<y

nên x=-2 ,y=5

c)x-y=5 hay x=y+5

\(\frac{y+5+4}{y-5}=\frac{4}{3}\Rightarrow3y+27=4y-20\Rightarrow y=47\Rightarrow x=52\)

câu c mk nhầm đề sr bạn nha

\(\frac{y+5-4}{y-5}=\frac{4}{3}\Rightarrow3y+3=4y-5\Rightarrow y=8\Rightarrow x=13\)

bài 2: (x-3).(y+2) = -5

    Vì x, y \(\in\)Z   => x-3 \(\in\)Ư(-5) = {5;-5;1;-1}

Ta có bảng: 

bài 3: a(a+2)<0

TH1 : \(\orbr{\begin{cases}a< 0\\a+2>0\end{cases}}\)=>\(\orbr{\begin{cases}a< 0\\a>-2\end{cases}}\)=> -2<a<0 ( TM)

TH2: \(\orbr{\begin{cases}a>0\\a+2< 0\end{cases}}\Rightarrow\orbr{\begin{cases}a>0\\a< -2\end{cases}}\Rightarrow loại\)
 

           Vậy -2<a<0

Bài 5: \(\left(x^2-1\right)\left(x^2-4\right)< 0\)

TH 1 : \(\hept{\begin{cases}x^2-1>0\\x^2-4< 0\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x^2>1\\x^2< 4\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x>1\\x< 2\end{cases}}\)\(\Rightarrow\)1 < a < 2

TH 2: \(\hept{\begin{cases}x^2-1< 0\\x^2-4>0\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x^2< 1\\x^2>4\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x< 1\\x>2\end{cases}}\)\(\Rightarrow\)loại

                         Vậy 1<a<2

a, \(x-\frac{1}{9}=\frac{8}{3}\Rightarrow x=\frac{8}{3}+\frac{1}{9}=\frac{25}{9}\)

\(-\frac{x}{4}=-\frac{9}{x}\Rightarrow x^2=-9.-4=36\Rightarrow\orbr{\begin{cases}x=6\\x=-6\end{cases}}\)

\(\frac{x}{4}=\frac{18}{x+1}\Rightarrow x\left(x+1\right)=18.4\Rightarrow x\left(x+1\right)=72\Rightarrow x=8\)

\(\frac{x}{7}=\frac{9}{y}\Rightarrow xy=63.\) Bạn tự làm tiếp là ra nhé

x-1/9=8/3

x=8/3+1/9

x=25/9

b)-x/4=-9/x

=>x/4=9/x

=>x.x=9.4

=>x²=36

=>x\(\in\){-6;6}

c)x/4=18/x+1

=>x(x+1)=18.4

=>x(x+1)=72=8.9

=>x=8

d) x/7=9/y

=>x.y=9.7=63

Mà x>9  =>y<63:9=7

=>y=1 hoặc y=3

Với y=1, ta có x=63

Với y=3 ta có x=21

e) -2/x=y/5

=> x.y=-2.5=-10

Vì x<0<y nên ta có bảng sau

\(\frac{x-4}{y-3}=\frac{4}{3}\)

\(\Rightarrow\left(x-4\right)\cdot3=\left(y-3\right)\cdot4\)

\(\Rightarrow3x-12=4y-12\)

\(\Rightarrow3x=4y\)

\(\Rightarrow\frac{x}{y}=\frac{4}{3}\)

1.

-2...4/5....

*Khi x<-2

4-5x=-x-2=> x=6/4=3/2 loại

*khi -2<=x<4/5

4-5x=x+2=> x=2/6=1/3<4/5 nhân

*kho x>=4/5

5x-4=x+2=> x=6/4=3/2 nhận

2.

x(1+y)+y+1=10

(x+1)(y+1)=10

x+1={-10,-5,-2,-1,1,2,5,10}=> x={-11,-6,-3,-2,0,1,4,9}

y+1={-1,-2,-5,-10,10,5,2,1)=> y={-2,-3,-6,-11,9,4,1,0}

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1

x=3/2

htp onlinemath