(11/11×12+11/12×23+11/23×34+....+11/89×100)+x=2/3
415 x 530 =?
11/12+11/12x23+11/23+34+...+11/78+89+11/89+100 = ?
4^15 x 5^30 = 2^30 x 5^30 = 10^30
\(\frac{11}{1.12}+\frac{11}{12.23}+\frac{11}{23.34}+.......+\frac{11}{78.89}+\frac{11}{98.100}\)
\(=1-\frac{1}{12}+\frac{1}{12}-\frac{1}{23}+....+\frac{1}{89}-\frac{1}{100}\)
\(=1-\frac{1}{100}\)
\(=\frac{99}{100}\)
a) mình ko biết làm
b)\(8^x\cdot8^5=8^{25}\)
\(8^x=8^{25}:8^5=8^{20}\Rightarrow x=20\)
\(\left(\frac{11}{12}+\frac{11}{12\times13}+\frac{11}{23\times24}+...+\frac{11}{89\times100}\right)+x=\frac{5}{3}\)
Tim x biet
ai guips tui với
Trước hết tính tổng :
\(\frac{11}{12}+\frac{11}{12\times13}+...+\frac{11}{89\times100}=1-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{89}-\frac{1}{100}\)
\(=1-\frac{1}{100}=\frac{99}{100}\)
Do đó \(\frac{99}{100}+x=\frac{5}{3}\)
Vậy \(x-\frac{5}{3}-\frac{99}{100}=\frac{500-297}{300}=\frac{203}{300}\)
Vậy...
bang 112222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222233333333333333333333333356152784327152718452314983254623145652186521865216416524
dung ko??
a) 1-2+3-4+5-6+7-8+9-10+11
b)98+87+76+...+21-12-23-34-...-89
a) 1 - 2 + 3 - 4 + 5 - 6 + 7 - 8 + 9 - 10 + 11
= (1 - 2) + (3 - 4) + (5 - 6) + (7 - 8) + (9 - 10) + 11
= -1 + (-1) + (-1) + (-1) + (-1) + 11
= -1 x 5 + 11
= -5 + 11
= 6
b) 98 + 87 + 76 + ... + 21 - 12 - 23 - 34 - ... - 89
= (98 89) + (87 - 78) + ... + (21 - 12) (có 8 nhóm)
= 9 + 9 + ... + 9 (có 8 số 9)
= 9 x 8
= 72
\(1-2+3-4+.....-10+11\)
\(=\left(1-2\right)+\left(3-4\right)+...\left(9-10\right)+11\)
\(=1+\left(-1\right)+\left(-1\right)+\left(-1\right)+\left(-1\right)+11\)
\(=-1\times5+11\)
\(=6\)
a)1-2+3-4+5-6+7-8+9-10+11 b)98+87+76+...+21-12-23-34-...89 =(1-2)+(3-4)+(5-6)+...+(9-10)+11 =(98-89)+(87-67)+...+(21-12)(8 nhóm) =-1+(-1)+....+(-1)+11 =9+9+9+...+9 =-1x5+11 =9x8 =6 =72
Tìm \(x\) biết: \(\left(\frac{11}{12}+\frac{11}{12\cdot23}+\frac{11}{23\cdot34}+...+\frac{11}{89\cdot100}\right)+x=\frac{5}{3}\)
1.(11/12+11/23+11/23+11/24+...+11/89+11/100)+x=5/3
1.(11/12+11/100)+x=5/3
77/75+x=5/3
x=5/3-77/75
x=16/25
de ot
=> ( 11/12+ 1/12- 1/23+ 1/23- 1/34+...+ 1/89-1/100 ) +x=5/3
=> (11/12+ 1/12-1/100 ) + x=5/3
=> (11/12+ 11/150) + x=5/3
=>99/100 +x = 5/3
=> x = 5/3 - 99/100
=> x= 203 / 300
K dung NHA
Ta có : (\(\frac{11}{12}+\frac{11}{12\times23}+\frac{11}{23\times34}+...+\frac{11}{89\times100}\)) + x =\(\frac{5}{3}\)
=> (\(\frac{11}{1\times12}+\frac{11}{12\times23}+\frac{11}{23\times34}+...+\frac{11}{89\times100}\)) + x =\(\frac{5}{3}\)
=> (\(1-\frac{1}{12}+\frac{1}{12}-\frac{1}{23}+\frac{1}{23}-\frac{1}{34}+...+\frac{1}{89}-\frac{1}{100}\)) + x =\(\frac{5}{3}\)
=> (\(1-\frac{1}{100}\)) + x =\(\frac{5}{3}\)
=> \(\frac{99}{100}\)+ x =\(\frac{5}{3}\)
=> x = \(\frac{5}{3}-\frac{99}{100}=\frac{203}{300}\)
Vậy x = \(\frac{203}{300}\)
Tìm x biết [11/12+11/12x13+11/23x24+...+11/89/100]+ x= 2/3,phần b :[2/11x13+2/13x15+...+2/19x21]+ x +221/231=4/3
Mình nghĩ bạn chép sai đề rồi. Hãy kiểm tra và sửa lại đề nhé
-11 +(-3+5-7+8-14)-(-34+23-12+23-45)
= 23 nha bạn
k cho mik nha
Bài 1: Chứng minh B = \(3^{21}+3^{22}+3^{23}+.........+3^{29}\) chia hết cho 13
Bài 2: So sánh \(\frac{100}{11^{11}}+\frac{100}{11^{12}}\)và \(\frac{99}{11^{11}}+\frac{101}{11^{12}}\)
3^21*(1+3+3^2)+3^24*(1+3+3^2)+3^27*(1+3+3^2)=13*3^21+13*3^24+13*3^27=13*(3^21+3^24+3^27)chia hết cho 13
Giải nghĩa ^:mũ
*:nhân