a) 2006²⁰⁰⁶ - 2006²⁰⁰⁵ = 2006²⁰⁰⁵ x 2006 - 2006²⁰⁰⁵ = 2006²⁰⁰⁵ x (2006 - 1) = 2006²⁰⁰⁵ x 2005 chia hết cho 2005  => 2006²⁰⁰⁶ - 2006²⁰⁰⁵ chia hết cho 2005.

b) 79^m+1 - 79^m = 79^m x 79 - 79^m = 79^m x (79 - 1) = 79^m x 78 chia hết cho 78  => 79^m+1 - 79^m  chia hết cho 78.

c) 25⁷ + 5¹³ = (5²)⁷ + 5¹³ = 5¹⁴ + 5¹³ = 5¹² x 5 x (5 + 1)  = 5¹² x 5 x 6 = 5¹² x 30 chia hết cho 30  => 25⁷ + 5¹³ chia hết cho 30.

d) 10⁶ - 5⁷ = (2 x 5)⁶ - 5⁷ = 2⁶ x 5⁶ - 5⁷ = 5⁶ x (2⁶ - 5) = 5⁶ x (64 - 5) = 5⁶ x 49 chia hết cho 49  => 10⁶ - 5⁷ chia hết cho 49.

e) 7¹⁰ - 7⁹ - 7⁸ = 7⁸ x (7² - 7 - 1) = 7⁸ x (49 - 7 - 1) = 7⁸ x 41 chia hết cho 41  => 7¹⁰ - 7⁹ - 7⁸ chia hết cho 41.

f)81⁷ - 27⁹ - 9¹³ = (3⁴)⁷ - (3³)⁹ - (3²)¹³ = 3²⁸ - 3²⁷ - 3²⁶ = 3²⁴ x 3² x (3² - 3 - 1) = 3²⁴ x 9 x 5 = 3²⁴ x 45 chia hết cho 45  => 81⁷ - 27⁹ - 9¹³ chia hết cho 45.

Cảm ơn

a) 5⁵ -5⁴ + 5³ =5³ ( 5² - 5 +1) =5³ .21 \(⋮\)7 (vì 21 \(⋮\)7)

=> 5⁵ - 5⁴ + 5³ \(⋮\)7

b) 10⁹ + 10⁸ +10⁷ = 10⁷ (10²+10+1) = 10⁷ .111= 10⁶ .10. 111 = 10⁶ .5. 222\(⋮\)222 (vì 222\(⋮\)222)

=> 10⁹ + 10⁸ + 10⁷ \(⋮\)222

a)5^5-5^4+5^3=5^3.(5^2-5+1)=5^3.(25-5+1)=5^3.21 \(⋮\) 7(đpcm)

b) ta có 222=2.111

mà 10 chia hết cho 2

=>10^9+10^8+10^7 chia hết cho 2 (1)

lại có ;

10^9+10^8+10^7=10^7.(10^2+10+1)=10^7.111 (2)

từ 1 và 2 suy ra 10^9+10^8+10^7 chia hết cho 222

Cách làm như sau:

Ta có:

\(10^6-5^7=5^6\cdot2^6-5^7\)

\(=5^6\left(2^6-5\right)\)

\(=5^6\left(64-5\right)=\left(5^6\cdot59\right)⋮59\)

Vậy .....

a) \(5^5-5^4+5^3=5^3\left(5^2-5+1\right)=5^3\cdot21⋮7\left(đpcm\right)\)

b) \(7^6+7^5-7^4=7^4\left(7^2+7-1\right)=7^4\cdot55⋮11\left(đpcm\right)\)

c) \(10^9+10^8+10^7=10^7\left(10^2+10+1\right)=10^7\cdot111=10^6\cdot5\cdot222⋮222\left(đpcm\right)\)

d) \(10^6-5^5=5^6\cdot2^6-5^5=5^5\left(5\cdot2^6-1\right)=5^5\cdot319\left(sai-de\right)\)

e) \(81^7-27^9-9^{13}=3^{28}-3^{27}-3^{26}=3^{25}\left(3^3-3^2-3\right)=3^{24}\cdot2\cdot15=3^{24}\cdot45⋮45\left(đpcm\right)\)

e) \(81^7-27^9-9^{13}=3^{28}-3^{27}-3^{26}=3^{24}.\left(3^4-3^3-3^2\right)=3^{24}.45⋮45\left(Đpcm\right)\)

f) \(8^{10}-8^9-8^8=8^8.\left(8^2-8-1\right)=8^8.55⋮55\left(Đpcm\right)\)

g) \(10^9+10^8+10^7=10^7.\left(10^2+10+1\right)=10^7.111=5^6.2^7.555⋮555\left(Đpcm\right)\)

a) \(5^5-5^4+5^3=5^3.\left(5^2-5+1\right)=5^3.21⋮7\left(đpcm\right)\)

b) \(7^6+7^5-7^4=7^4.\left(7^2+7-1\right)=7^4.55⋮11\left(đpcm\right)\)

c) \(10^9+10^8+10^7=10^7.\left(10^2+10+1\right)=10^7.111=2^7.5^7.111=2^6.222.5^7\)\(⋮222\left(đpcm\right)\)

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