Tím x :128 - 3 (x+4)=23
128 -3 x ( x + 4 ) = 23
3x(x+4)=128-23
3x(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
cich dung cho minh di
3x(x+4)=128-23
3x(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
128 – 3(x + 4) = 23
128 – 3(x + 4) = 23
3.(x + 4) = 128 – 23
3.(x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 – 4
x = 31
`128-3(x+4)=23`
`3(x+4)=128-23`
`3(x+4)=105`
`x+4=105:3=35`
`x=35-4=31`
3 x (x + 4) = 128 - 23
3 x (x + 4) = 105
x + 4 = 105 : 3
x+4=35
x=35-4
x=31
a, 128-3x(x+4)=23
b, [(4.x+23).3+55]
c, (12.x-4/3).8/3=4.8/4
d, 720:[41-(2.x-5)]
tim x
128-3*(x+4)=23
128-3*(x+4)=23
3*(x+4)=128-23=105
x+4=105/3=35
x=31
Tìm x
128-3.(x+4)=23
\(128-3.\left(x+4\right)=23\)
\(128-3x-12=23\)
\(116-3x=23\)
\(3x=116-23\)
\(3x=93\)
\(x=31\)
128 - 3 . ( x + 4 ) = 23
=> 3 . ( x + 4 ) = 128 - 23
=> 3 . ( x + 4 ) = 105
=> x + 4 = 105 : 3
=> x + 4 = 35
=> x = 35 - 4
=> x = 31
Vậy x = 31
128-3.(x+4)=23
3.(x+4)=128-23
3.x(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
Tìm x biết 128-3(x+4)=23
128-3.(x+4)=23
128 - 3 ( x + 4 ) = 23
3( x + 4 ) = 128 - 23 = 105
x + 4 = 105 : 3 = 35
x = 35 - 4 = 31
128-3.(x+4)=23
=> 3.(x+4)=128-23
=> 3.(x+4)=105
=> x+4=105:3
=> x+4=35
=> x=35-4
=> x=31
128-3.(x+4)=23
128 - 3(x + 4) = 23
\(\Leftrightarrow\)3(x + 4) = 128 - 23 = 105
\(\Leftrightarrow\)x + 4 = 105 : 3 = 35
\(\Leftrightarrow\)x = 35 - 4 = 31
Vậy x = 31
128-3.(x+4)=23
3.(x+4)=128-23
3.(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
128-3.(x+4)=23
3.(x+4)=128-23
3.(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
OK k mk nha
128-3(X+4)=23