hay chung minh 2+2^2+2^3+2^4+...+2^90 chia het cho 21
hay chung minh
A= 2^1+2^2 +2^3+2^4+...+2^2013 ma chia het cho 7
chung minh A= 2 + 2^2 +2^3 +2^4 +.........+2^60 chia het cho 7
tim so tu nhien n de : n+4 chia het cho n+1
chung minh ( 1+2 +2^2 +2^3+2^4+2^5+2^6+2^7) chia het cho 3
1. A = 2 + 22 + 23 + 24 + ... + 260
A = ( 2 + 22 + 23 ) + ( 24 + 25 + 26 ) + ... + ( 258 + 259 + 260 )
A = 2 ( 1 + 2 + 22 ) + 24 ( 1 + 2 + 22 ) + ... + 258 ( 1 + 2 + 22 )
A = 2 . 7 + 24 . 7 + ... + 258 . 7
A = ( 2 + 24 + ... + 258 ) . 7 => A \(⋮\)7
Vậy ...
2.Ta có : \(n+4⋮n+1\)
Mà : \(n+1⋮n+1\)
\(\Rightarrow\left(n+4\right)-\left(n+1\right)⋮n+1\Rightarrow n+4-n-1⋮n+1\)
\(\Rightarrow3⋮n+1\Rightarrow n+1\in\left\{1;3\right\}\)
\(\Rightarrow n\in\left\{0;2\right\}\)
3. Đặt B = 1 + 2 + 22 + 23 + 24 + 25 + 26 + 27
B = ( 1 + 2 ) + ( 22 + 23 ) + ( 24 + 25 ) + ( 26 + 27 )
B = ( 1 + 2 ) + 22 ( 1 + 2 ) + 24 ( 1 + 2 ) + 26 ( 1 + 2 )
B = 1 . 3 + 22 . 3 + 24 . 3 + 26 . 3
B = ( 1 + 22 + 24 + 26 ) . 3 \(\Rightarrow\) B \(⋮\)3
Vậy ...
A=4+4^2+4^3+...+4^20
a) chung minh A chia het cho 20
b) chung minh A chia het cho 21
lam ho toi tick cho
1.Hay viet vao ben phai so 2005 so co 2 chu so de duoc so nho nhat co 6 chu so khi chia 5 du 1 nhung chia het cho 2
2. Cho A =13 giao thua - 11 giao thua
A co chia het cho 2 hay khong
A co chia ht cho 5 hay khong
3. Tong cac so tu nhien tu 1 den 154
Co chia het cho 2 hay khong
Co chia het cho 5 hay khong
4.
Cho A = 115+118+117+...+11+1
Chung minh rang A chia het cho 5
5.
Chung minh rang voi moi nguoi so tu nhien thi N2+N+6 khong chia het cho 5
6.Trong cac so tu nhien nho hon 1000 co bao nhieu so chia het cho 2 nhung khong chia het cho 5
Có 13 giao thừa = 1.2.3.4.5.6.7.8.9.10.11.12.13 chia hết cho 2
Có 11 giao thừa = 1.2.3.4.5.6.7.8.9.10.11 chia hết cho 2
suy ra 13 giao thừa - 11 giao thừa chia hết cho 2
xin các bạn k cho mình nhé
cho A=21+22+23+...+ 230
Chung minh A chia het cho 21
A = 2 1 + 2 2 + 2 3 + ... + 2 30
= ( 2 1 + 2 2 + 2 3 + 2 4 + 2 5 + 2 6 ) + .... + ( 2 25 + 2 26 + 2 27 + 2 28 + 2 29 + 2 30 )
= 2 ( 1 + 2 + 2 2 + 2 3 + 2 4 + 2 5 ) + ..... + 2 25 ( 1 + 2 + 2 2 + 2 3 + 2 4 + 2 5 )
= 2 . 63 + .... + 2 25 . 63
= 63 . ( 2 + .... + 2 25 )
= 3 . 21 . ( 2 + ... + 2 25 ) Chia hết cho 21 ( Do 21 chia hết cho 21 )
Vậy A = 2 1 + 2 2 + 2 3 + ... + 2 30 chia hết cho 21
hay chung minh rang voi moi so nguyen a thi (a+2)2-(a-2)2 chia het cho 4
Ta có :
\(\left(a+2\right)^2-\left(a-2\right)^2\)
\(=\left(a+2-a+2\right)\left(a+2+a-2\right)\)
\(=4.2a\)
\(=8a\)
Mà \(a\in Z\Leftrightarrow8a⋮4\)
\(\Leftrightarrow\left(a+2\right)^2-\left(a-2\right)^2⋮4\left(đpcm\right)\)
a, cho A= 3+3^2+3^3+...+3^90 chung minh A chia het cho 11
\(A=3+3^2+3^3+...+3^{90}\)
\(A=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^{89}+3^{90}\right)\)
\(A=11+3^2\left(3+3^2\right)+...+3^{98}\left(3+3^2\right)\)
\(A=11+3^2.11+...+3^{98}.11\)
\(A=11\left(1+3^2+...+3^{98}\right)⋮11\) (đpcm)
Cho A=3+3^2+3^3+...+3^90.chung minh rang A chia het cho11 va 13
A=(3+3^2+3^3+3^4+3^5)+......+(3^86+3^87+3^88+3^89+3^90)
Chia làm 18 ngoặc mỗi ngoặc đều chia hết cho 11
vay A CHIA HET CHO 11
A=(3+3^2+3^3)+...+(3^88+3^89+3^90)
chia làm 30 ngoặc mỗi ngoặc đều chia hết cho 13
Vậy A chia hết cho 13
Cho A = 2 + 2^2+ 2^3 + 2^4 + 2^5 + 2^6 + 2^6 + 2^7 + 2^8 + 2^9. Khong tinh, hay chung to A chia het cho 7.
Ai ma lam nhanh va chinh xac nhat, minh hua se tick cho nha !
A=2 + 2^2+ 2^3 + 2^4 + 2^5 + 2^6 + 2^6 + 2^7 + 2^8 + 2^9
=>A=(2+2^2+2^3)+....+(2^7+2^8+2^9)
A=(2.1+2.2+2.2^2)+.......+(2^7.1+2^7.2+2^7.2^2)
A=2(1+2+2^2)+....+2^7(1+2+2^2)
A=2.7+....+2^7.7
A=(2+...+2^7).7 chia hết cho 7
vậy A chia hết cho 7
tick nha