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Five centimeters per sec...
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Soái Nhi
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Mới vô
14 tháng 5 2017 lúc 8:32

\(E=\dfrac{1}{3}-\dfrac{2}{3^2}+\dfrac{3}{3^3}-\dfrac{4}{3^4}+...+\dfrac{2015}{3^{2015}}-\dfrac{2016}{3^{2016}}\\ 3E=1-\dfrac{2}{3}+\dfrac{3}{3^2}-\dfrac{4}{3^3}+...+\dfrac{2015}{3^{2014}}-\dfrac{2016}{3^{2015}}\\ 3E+E=\left(1-\dfrac{2}{3}+\dfrac{3}{3^2}-\dfrac{4}{3^3}+...+\dfrac{2015}{3^{2014}}-\dfrac{2016}{3^{2015}}\right)+\left(\dfrac{1}{3}-\dfrac{2}{3^2}+\dfrac{3}{3^3}-\dfrac{4}{3^4}+...+\dfrac{2015}{3^{2015}}-\dfrac{2016}{3^{2016}}\right)\\ 4E=1-\dfrac{1}{3}+\dfrac{1}{3^2}-\dfrac{1}{3^3}+...+\dfrac{1}{3^{2014}}-\dfrac{1}{3^{2015}}-\dfrac{2016}{3^{2016}}\\ 4E< 1-\dfrac{1}{3}+\dfrac{1}{3^2}-\dfrac{1}{3^3}+...+\dfrac{1}{3^{2014}}-\dfrac{1}{3^{2015}}\left(1\right)\)

Gọi \(D=1-\dfrac{1}{3}+\dfrac{1}{3^2}-\dfrac{1}{3^3}+...-\dfrac{1}{3^{2015}}\)

\(3D=3-1+\dfrac{1}{3}-\dfrac{1}{3^2}+...+\dfrac{1}{3^{2013}}-\dfrac{1}{3^{2014}}\\ 3D+D=\left(3-1+\dfrac{1}{3}-\dfrac{1}{3^2}+...+\dfrac{1}{3^{2013}}-\dfrac{1}{3^{2014}}\right)+\left(1-\dfrac{1}{3}+\dfrac{1}{3^2}-\dfrac{1}{3^3}+...+\dfrac{1}{3^{2014}}-\dfrac{1}{3^{2015}}\right)\\ 4D=3-\dfrac{1}{3^{2015}}< 3\\ \Rightarrow D< \dfrac{3}{4}\left(2\right)\)

Từ (1) và (2) ta có:

\(4E< \dfrac{3}{4}\\ \Rightarrow E< \dfrac{3}{16}\)

Lương Thị Thu Hương
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HT2k02
5 tháng 4 2021 lúc 20:29

Bạn ơi thiếu đề rồi, cái biểu thức này không tính được đâu , mình nghĩ thế

Hà Nguyễn
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Vũ Thị Quỳnh Phương
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Sahara
18 tháng 3 2023 lúc 20:51

\(M=\dfrac{3}{1\times2}+\dfrac{3}{2\times3}+\dfrac{3}{3\times4}+...+\dfrac{3}{2015\times2016}+\dfrac{3}{2016\times2017}\)
\(=3\times\left(\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+...+\dfrac{1}{2015\times2016}+\dfrac{1}{2016\times2017}\right)\)
\(=3\times\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2015}-\dfrac{1}{2016}+\dfrac{1}{2016}-\dfrac{1}{2017}\right)\)
\(=3\times\left(1-\dfrac{1}{2017}\right)\)
\(=3\times\dfrac{2016}{2017}\)
\(=\dfrac{6048}{2017}\)
#DatNe

Trương Thị  Lợi
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Mới vô
10 tháng 5 2017 lúc 14:48

\(E=\dfrac{1}{3}-\dfrac{2}{3^2}+\dfrac{3}{3^3}-\dfrac{4}{3^4}+...+\dfrac{2015}{3^{2015}}-\dfrac{2016}{3^{2016}}\\ 3E=1-\dfrac{2}{3}+\dfrac{3}{3^2}-\dfrac{4}{3^3}+...+\dfrac{2015}{3^{2014}}-\dfrac{2016}{3^{2015}}\\ 3E+E=\left(1-\dfrac{2}{3}+\dfrac{3}{3^2}-\dfrac{4}{3^3}+...+\dfrac{2015}{3^{2014}}-\dfrac{2016}{3^{2015}}\right)+\left(\dfrac{1}{3}-\dfrac{2}{3^2}+\dfrac{3}{3^3}-\dfrac{4}{3^4}+...+\dfrac{2015}{3^{2015}}-\dfrac{2016}{3^{2016}}\right)\\ 4E=1-\dfrac{1}{3}+\dfrac{1}{3^2}-\dfrac{1}{3^3}+...+\dfrac{1}{3^{2014}}-\dfrac{1}{3^{2015}}-\dfrac{2016}{3^{2016}}\\ 12E=3-1+\dfrac{1}{3}-\dfrac{1}{3^2}+...+\dfrac{1}{3^{2013}}-\dfrac{1}{3^{2014}}-\dfrac{6048}{3^{2016}}\\ 4E+12E=\left(3-1+\dfrac{1}{3}-\dfrac{1}{3^2}+...+\dfrac{1}{3^{2013}}-\dfrac{1}{3^{2014}}-\dfrac{2016}{3^{2015}}\right)+\left(1-\dfrac{1}{3}+\dfrac{1}{3^2}-\dfrac{1}{3^3}+...+\dfrac{1}{3^{2014}}-\dfrac{1}{3^{2015}}-\dfrac{2016}{3^{2016}}\right)\\ 16E=3-\dfrac{2017}{3^{2015}}-\dfrac{2016}{3^{2016}}\\ 16E=3-\left(\dfrac{2017}{3^{2015}}+\dfrac{672}{3^{2015}}\right)\\ 16E=3-\dfrac{2689}{3^{2015}}< 3\\ \Rightarrow E< \dfrac{3}{16}\)

kobato
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Kudo Sinichi
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Nguyễn Minh Phương
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