a) 5x.(x+3/4) = 0

=> x = 0

x+3/4 = 0 => x = -3/4

b) \(\frac{x+7}{2010}+\frac{x+6}{2011}=\frac{x+5}{2012}+\frac{x+4}{2013}.\)

\(\Rightarrow\frac{x+7}{2010}+\frac{x+6}{2011}-\frac{x+5}{2012}-\frac{x+4}{2013}=0\)

\(\frac{x+7}{2010}+1+\frac{x+6}{2011}+1-\frac{x+5}{2012}-1-\frac{x+4}{2013}-1=0\)

\(\left(\frac{x+7}{2010}+1\right)+\left(\frac{x+6}{2011}+1\right)-\left(\frac{x+5}{2012}+1\right)-\left(\frac{x+4}{2013}+1\right)=0\)

\(\frac{x+2017}{2010}+\frac{x+2017}{2011}-\frac{x+2017}{2012}-\frac{x+2017}{2013}=0\)

\(\left(x+2017\right).\left(\frac{1}{2010}+\frac{1}{2011}-\frac{1}{2012}-\frac{1}{2013}\right)=0\)

=> x + 2017 = 0

x = -2017

a) để 2x - 3 > 0

=> 2x > 3

x > 3/2

b) 13-5x < 0

=> 5x < 13

x < 13/5

c) \(\frac{x+3}{2x-1}>0\)

=> x + 3 > 0

x > -3

d) \(\frac{x+7}{x+3}=\frac{x+3+4}{x+3}=1+\frac{4}{x+3}\)

Để x+7/x+3 < 1

=> 1 + 4/x+3 < 1

=> 4/x+3 < 0

=> không tìm được x thỏa mãn điều kiện

\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}}{\frac{2013}{1}+\frac{2012}{2}+\frac{2011}{3}+...+\frac{1}{2013}}\)

\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}}{\left(\frac{2012}{2}+1\right)+\left(\frac{2011}{3}+1\right)+...+\left(\frac{1}{2013}+1\right)+1}\)

\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}}{\frac{2014}{2}+\frac{2014}{3}+...+\frac{2014}{2013}+\frac{2014}{2014}}\)

\(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}}{2014.\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2014}\right)}\)\

\(A=\frac{1}{2014}\)

Số lượng số của dãy số trên là :

( 2012 - 1 ) : 1 + 1 = 2012 ( số ) 

Do 2012 chia hết cho 2 nên ta nhóm 2 số liền nhau thành 1 nhóm như sau : 

( 1 - 2 ) + ( 3 - 4 ) + ( 5 - 6 ) + ...+ ( 2011 - 2012 )

Tổng của mỗi nhóm là :    1 - 2  = -1 , 3 - 4 = -1 , ... 2011 - 2012 = -1

Số nhóm là : 2012 : 2 = 1006 ( nhóm ) 

Tổng của dãy số trên là :

1006 . ( -1 ) = -1006 

              Đ/s : -1006 

Chúc bạn học giỏi !!!

1 - 2 + 3 - 4 + 5 - 6 + ........... + 2011 - 2012 ( có 2012 số hạng )

= - 1 + ( - 1 ) + ( - 1 ) + ........ + ( - 1 )        ( có 1006 số - 1 )

= - 1 . 1006

= - 1006

a) \(\frac{x+4}{x+3}< 1\)

\(\Leftrightarrow\frac{x+4}{x+3}-1< 0\)

\(\Leftrightarrow\frac{x+4-x-3}{x+3}< 0\)

\(\Leftrightarrow\frac{1}{x+3}< 0\)

\(\Leftrightarrow x+3< 0\)

\(\Leftrightarrow x< -3\)

Vậy \(x< -3\)

b) \(\frac{x+3}{x+4}>1\)

\(\Leftrightarrow\frac{x+3}{x+4}-1>0\)

\(\Leftrightarrow\frac{x+3-x-4}{x+4}>0\)

\(\Leftrightarrow-\frac{1}{x+4}>0\)

\(\Leftrightarrow x+4< 0\)

\(\Leftrightarrow x< -4\)

Vậy \(x< -4\)

c) \(\frac{x+3}{2010}+\frac{x+2}{2011}+\frac{x+1}{2012}+\frac{x+2025}{4}=0\)

\(\Leftrightarrow\left(\frac{x+3}{2010}+1\right)+\left(\frac{x+2}{2011}+1\right)+\left(\frac{x+1}{2012}+1\right)+\left(\frac{x+2025}{4}-3\right)=0\)

\(\Leftrightarrow\frac{x+2013}{2010}+\frac{x+2013}{2011}+\frac{x+2013}{2012}+\frac{x+2013}{4}=0\)

\(\Leftrightarrow\left(x+2013\right)\left(\frac{1}{2010}+\frac{1}{2011}+\frac{1}{2012}+\frac{1}{4}\right)=0\)

\(\Leftrightarrow x+2013=0\) (Vì \(\frac{1}{2010}+\frac{1}{2011}+\frac{1}{2012}+\frac{1}{4}\ne0\))

\(\Leftrightarrow x=-2013\)

Vậy \(x=-2013\)

Nhớ tick đó ✔✔✔

\(\left(\frac{2013}{2011}+\frac{2014}{2012}+\frac{2015}{2013}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)=0\)

thanks