1 He doesn't play games

2 I don't go to the art club

3 What about sitting down?

4 We are going to take part in the stamp collector's club

5 How about relaxing?

6 My favorite subject is English

7 My favorite sport is football

8 Pink and blue are my favorite colors

9 My favorite subject is English

10 My favorite sport is football

ĐKXĐ:

3.

\(cos\left(3x-\dfrac{\pi}{4}\right)\ne0\Leftrightarrow3x-\dfrac{\pi}{4}\ne\dfrac{\pi}{2}+k\pi\)

\(\Leftrightarrow3x\ne\dfrac{3\pi}{4}+k\pi\Rightarrow x\ne\dfrac{\pi}{4}+\dfrac{k\pi}{3}\)

4.

\(sin\left(2x+\dfrac{\pi}{6}\right)\ne0\Leftrightarrow2x+\dfrac{\pi}{6}\ne k\pi\)

\(\Rightarrow x\ne-\dfrac{\pi}{12}+\dfrac{k\pi}{2}\)

5.

\(\left\{{}\begin{matrix}cosx\ne0\\sin3x\ne0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x\ne\dfrac{\pi}{2}+k\pi\\3x\ne k\pi\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x\ne\dfrac{\pi}{2}+k\pi\\x\ne\dfrac{k\pi}{3}\end{matrix}\right.\)

Vận tốc của chất điểm:

\(v\left(t\right)=s'\left(t\right)=3t^2-6t+9=3\left(t-1\right)^2+6\ge6\)

Dấu "=" xảy ra khi \(t-1=0\Rightarrow t=1s\)

\(\dfrac{1+sin^2x}{1-sin^2x}-2tan^2x=\dfrac{1+sin^2x}{cos^2x}-2tan^2x=\dfrac{1}{cos^2x}+tan^2x-2tan^2x\)

\(=\left(1+tan^2x\right)-tan^2x=1\)

a, cường độ dđ mạch 

\(I=\dfrac{U}{R_{td}}=\dfrac{12}{10+5}=0,8\left(A\right)\)

\(\Rightarrow U_1=I.R_1=8\left(V\right)\)

\(\Rightarrow U_2=I.R_2=5.0,8=4\left(V\right)\)

b, \(\Rightarrow U_1=\dfrac{4}{2}=2\left(V\right)\)

\(I=I_2=\dfrac{4}{5}=0,8\left(A\right)\)

\(I_1=\dfrac{2}{10}=0,2\left(A\right)\)

\(I_3=I_2-I_1=0,6\left(A\right)\)

\(\Rightarrow R_3=\dfrac{U_1}{I_3}=\dfrac{2}{0,6}=\dfrac{10}{3}\left(\Omega\right)\)

câu 1

a, \(R_{tđ}=\dfrac{R_1R_2}{R_1+R_2}=\dfrac{10.20}{10+20}=\dfrac{20}{3}\left(\Omega\right)\)

b, \(U_{AB}=R_2I_2=20.0,6=12\left(V\right)\)

\(I_1=\dfrac{U_{AB}}{R_1}=\dfrac{12}{10}=1,2\left(A\right)\)

C ( y=20)

Có: `-C_2021 ^0 +C_2021 ^1 -C_2021 ^2 +....+C_2021 ^2019-C_2021 ^2020 -C_2021 ^2021 =-1-1=-2`

Mà `C_2021 ^0 +C_2021 ^1 +C_2021 ^2 +....+C_2021 ^2019 +C_2021 ^2020 +C_2021 ^2021 =2^2021`

   `=>2(C_2021 ^1 + C_2021 ^3 +C_2021 ^5 +...+C_2021 ^2017 + C_2021 ^2019 )=-2+2^2021`

 `=>C_2021 ^1 + C_2021 ^3 +...+C_2021 ^2017 + C_2021 ^2019 =-1+2^2020`