\(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{7^x.7^2+7^x.7+7^x}{57}=\frac{7^x.\left(7^2+7+1\right)}{57}=7^x\)

\(\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}=\frac{5^{2x}+5^{2x}.5+5^{2x}.5^3}{131}=\frac{5^{2x}\left(1+5+5^3\right)}{131}=\frac{25^x.131}{131}=25^x\)

\(\Rightarrow7^x=25^x\Rightarrow x=0\)

ai tích mình mình tích lại cho

ai tích mình mình tích lại cho

\(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)

\(\frac{7^x\left(7^2+7^1+1\right)}{57}=\frac{5^{2x}\left(1+5^1+5^3\right)}{131}\)

\(\frac{7^x\left(49+7+1\right)}{57}=\frac{5^{2x}\left(1+5+125\right)}{131}\)

\(\frac{7^x\times57}{57}=\frac{5^{2x}\times131}{131}\)

\(7^x=25^x\)

\(x=0\)

Chúc bạn học tốt

\(\frac{7^x\left(7^2+7+1\right)}{57}=\frac{5^{2x}\left(1+5+5^3\right)}{131}\)

\(\frac{7^x.57}{57}=\frac{5^{2x}.131}{131}\)

\(7^x=5^{2x}\)khi và chỉ khi x = 0.

\(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)

\(\Rightarrow\frac{7^x.7^2+7^x.7^1+7^x}{57}=\frac{5^{2x}+5^{2x}.5+5^{2x}.5^3}{131}\)

\(\Rightarrow\frac{7^x.\left(7^2+7+1\right)}{57}=\frac{5^{2x}.\left(1+5+5^3\right)}{131}\)

\(\Rightarrow\frac{7^x.57}{57}=\frac{5^{2x}.131}{131}\)

\(\Rightarrow7^x=5^{2x}\)

Bạn tự làm phần còn lại nhé