a) ab+ac= a(b+c)

b) ab-ac+ad= a(b-c+d)

c) ax-bx-cx+dx= x(a-b-c+d)

a.(b+c)

a.(b-c+d)

x.(a-b-c+d)

Mk chắc chắn 100% luôn, k mk nha

\(ab+ac=a\left(b+c\right)\)

\(ab-ac+ad=a\left(b+c+d\right)\)

\(ax-bx-cx+dx=x\left(a-b-c+d\right)\)

k mk nha bn

thank you

1,  ab+ac= a(b+c)

2,  ab-ac+ad = a(b-c+d)

3,  ax-bx-cx+dx = x(a-b-c+d)

ab + ac = a( b + c )

ab - ac + ad = a( b - c + d )

ax + bx - cx + dx = x( a + b - c + d )

1)ab+ac=a(b+c)

2)ab-ac+ad=a(b-c+d)

3)ax+bx-cx+dx=x(a+b-c+d)

tk minh nha dung 100% luon

ab + ac = a.(b + c )

ab - ac + ad = a.( b - c + d )

ax + bx - cx + dx = x.( a + b -c + d )

Ta có: a(b-c+d)

=a(b-c+d)

chúc bn hok tốt 

forever

\(ab-ac+ad=a\left(b-c+d\right)\)

ab + ac = a( b + c)

hok tốt!!!

Trả lời:

ab+ac viết dưới dạng tích là:

\(a.\left(b+c\right)\)

Chúc em học tốt

Forever

ab+ac=a.(b+c)

Chúc bn học tốt

1) ab + ac = a(b + c)

2) ab - ac + ad = a(b - c + d)

3) ax - bx - cx + dx = x(a - b - c + d)

4) a(b + c) - d(b + c) = (b + c)(a - d)

5) ac - ad + bc - bd = a(c - d) + b(c - d) = (c - d)(a + b)

6) ax + by + bx + ay = (ax + ay) + (bx + by) = a(x + y) + b(x + y) = (x + y)(a + b)

ab + ac = a ( b + c )

ab - ac + ad = a ( b - c + d )

ax - bx - cx + dx = x ( a - b - c + d )

1/ab+ac=a(b+c)

2/ab-ac+ad=a(b-c)+ad=a(b-c+d)

3/ax-bx-cx+dx=x(a-b-c)+xd=x(a-b-c+d)

4/a(b+c)-d(b+c)=(ab+ac)-(bd+cd)=b(a+d)-c(a+d)=a+d(b+c)

5/ac-ad+bc-bd=a(c-d)+b(c-d)=c-d(a+b)

6/ax+by+bx+ay=a(x+y)+b(x+y)=x+y(a+b)

1/ ab+ac=a(b+c)

2/ab-ac+ad=a(b-c+d)

3/ax-bx-cx+dx=x(a-b-c+d)

4/a(b+c)-d(b+c)=(b+c)(a-d)

5/ac-ad+bc-bd=a(c-d)+b(c-d)=(c-d)(a+b)

6/ax+by+bx+ay=a(x+y)+b(y+x)=(y+x)(a+b)

\(1,ab+ac\)

\(=a\left(b+c\right)\)

\(2,ab-ac+ad\)

\(=a\left(b-c+d\right)\)

\(3,ax-bx-cx+dx\)

\(=x\left(a-b-c+d\right)\)

\(4,a\left(b+c\right)-d\left(b+c\right)\)

\(=\left(b+c\right)\left(a-d\right)\)

\(5,ac-ad+bc-bd\)

\(=a\left(c-d\right)+b\left(c-d\right)\)

\(=\left(a+b\right)\left(c-d\right)\)

\(6,ax+by+bx+ay\)

\(=\left(ax+bx\right)+\left(by+ay\right)\)

\(=x\left(a+b\right)+y\left(a+b\right)\)

\(=\left(x+y\right)\left(a+b\right)\)

1? 

a(b+c)

a(b-c+d)

x(a-b-c+d)

(b+c)(a-d)

(c-d)(a+b)

(x+-y)(a+b)