\(2^x+2^{x+2}=32.\left(2^2+1\right)\)

\(\Rightarrow2^x+2^{x+2}=32.5\)

\(\Rightarrow2^x+2^{x+2}=160\)

\(\Rightarrow2^x\left(1+4\right)=160\)

\(\Rightarrow2^x.5=160\)

\(\Rightarrow2^x=160:5=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

Vậy x = 5

2^x+1-2^x=32

2^xx2^-2x^x1=32

2^xx(2-1)=32

2^xx1=32

2^x=32:1

2^x=32

=>2^x=2⁵

=>x=5

HT

2^{x + 1} - 2^x = 32

2^x . 2 - 2^x . 1 = 32

2^x . ( 2 - 1 ) = 32

2^x . 1 = 32

2^x = 32

2^x = 2⁵

=> x = 5

Bài làm:

Ta có: \(2^x\div2=32\)

\(\Leftrightarrow2^{x-1}=2^5\)

\(\Rightarrow x-1=5\)

\(\Rightarrow x=6\)

Hướng 1 .

2^x : 2 = 32

<=> 2^x : 2 = 2⁵

<=> 2^x = 2⁵.2

<=> 2^x = 2⁶

<=> x = 6

2^x-2 = 32

Hướng 2.

2^x:2 = 32

<=> 2^x:2 = 2⁵

<=> x : 2 = 5

<=> x = 10 

2^x=32x2

2^x=64

2^x=2^6

vậy x=6

\(\left(\frac{2}{5}\right)^{\text{x}+1}\cdot4=\frac{32}{125}\)

\(\Rightarrow\left(\frac{2}{5}\right)^{\text{x}+1}=\frac{32}{125}\div4\)

\(\Rightarrow\left(\frac{2}{5}\right)^{\text{x}+1}=\frac{8}{125}\)

\(\Rightarrow\left(\frac{2}{5}\right)^{\text{x}+1}=\left(\frac{2}{5}\right)^3\)

\(\Rightarrow x+1=3\Rightarrow x=3-1=2\)

Vậy x = 2 

* = nhân nhé

( ( x . 32 ) - 17 ) . 2 = 42

( ( x . 32 ) - 17 ) = 42 : 2

( ( x . 32 ) - 17 ) = 21

x . 32 = 21 + 17

x . 32 = 38

x = 38 : 32

x = 19/16

88 - 3 . ( 7 + x ) = 64

3 . ( 7 + x ) = 88 - 64 

3 . ( 7 + x ) = 24

7 + x = 24 : 3 

7 + x = 8

x = 8 - 7

x = 1

khó quá ai đó giúp mình với

      (x/2-3)⁵=32

<=>(x/2-3)⁵=2⁵

<=>x/2-3=2

<=>x=(2+3).2

<=>x=10

      (x/2-3)⁵=32

<=>(x/2-3)⁵=2⁵

<=>x/2-3=2

<=>x=(2+3).2

<=>x=10

!!!!!CHÚC!!MAY!!MẮN!!!!!

bạn giúp mình câu này với 1 phần 2 nhân 2 mũ x cộng 4 nhân 2 mũ x = 3 mũ 2 nhân 2 mũ 5