[(2016/2017)-(3/2015)]÷[(-2)/3]-[(2012/2015)-(1/2017)]÷[(-2)/3]
Giúp mình với :
Những câu hỏi liên quan
(2/3 +3/4 +4/5+...+ 2016/2017) x ( 1/2+ 2/3+ 3/4+... + 2015/2016) - ( 1/2 + 2/3+ 3/4+ .... +2016/2017) x ( 2/3+ 3/4+ 4/5+... + 2015/2016) = ?
Giải chi tiết giúp mình nhé,
Giúp mình với nhé!!!!
Tìm x biết:
x+1/2013+x+2/2012+x+3/2011=x-1/2015+x-2/2016+x-3/2017
\(\text{Đầu bài viết khó nhìn thí mồ!! viết lại nhé!!}\)
\(\frac{x+1}{2013}+\frac{x+2}{2012}+\frac{x+3}{2011}=\frac{x-1}{2015}+\frac{x-2}{2016}+\frac{x-3}{2017}\)
\(\Rightarrow\frac{x+1}{2013}+1+\frac{x+2}{2012}+1+\frac{x+3}{2011}+1=\frac{x-1}{2015}+1+\frac{x-2}{2016}+1+\frac{x-3}{2017}+1\)
\(\Leftrightarrow\frac{x+2014}{2013}+\frac{x+2014}{2012}+\frac{x+2014}{2011}-\frac{x+2014}{2015}-\frac{x+2014}{2016}-\frac{x+2014}{2017}=0\)
\(\Leftrightarrow\left(x+2014\right)\left(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}-\frac{1}{2015}-\frac{1}{2016}-\frac{1}{2017}\right)=0\)
\(\text{Mà }\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}-\frac{1}{2015}-\frac{1}{2016}-\frac{1}{2017}\ne0\)
\(\text{Nên }x+2014=0\Leftrightarrow x=-2014\)
Đúng 0
Bình luận (0)
Giúp mk với
(1/2+2015/2016+2016/2017+1)(2015/2016+2016/2017+7/22)-(1/2+2015/2016+2016/2017)(2015/2016+2016/2017+7/22+1)
thục hiện phép tính: (1/2+1/3+1/4+.....+1/2017+1/2018)/(2017/1+2016/2+2015/3+.....+2/2016+1/2017)
Các bạn giúp mình nha ! Thank you very much :)
Đặt \(S=\frac{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2018}}{\frac{2017}{1}+\frac{2016}{2}+...+\frac{1}{2017}}\)
Biến đổi mẫu
\(\frac{2017}{1}+\frac{2016}{2}+...+\frac{1}{2017}\)
\(=\left(2017+1\right)+\left(\frac{2016}{2}+1\right)+...+\left(\frac{1}{2017}+1\right)-2017\)
\(=2018+\frac{2018}{2}+...+\frac{2018}{2017}+\frac{2018}{2018}-2018\)
\(=2018.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2018}\right)\)
\(\Rightarrow S=\frac{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2018}}{2018.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2018}\right)}=\frac{1}{2018}\)
Đúng 0
Bình luận (0)
A= ( 1/2017+ 2/2016+ 3/2015+...+ 2015/3+ 2016/2+ 2017) : ( 1/2+1/3+1/4+...+1/2017+1/2018)
Tính: (2/3 + 3/4 + 4/5 + ... + 2016/2017) x (1/2 + 2/3 + 3/4 + ... + 2015/2016) – (1/2 + 2/3 + 3/4 + ... + 2016/2017) x (2/3 + 3/4 + 4/5 + ... + 2015/2016).
Thông cảm, mình không viết được phân số.
chấm hỏi lớn ???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
So sánh:
a) A = 102016 - 2 / 102017 - 2 và B = 202015 + 1 / 102016 + 1
b) A = 20162017 - 3 / 20162018 - 3 và B = 20162016 + 3 / 20162017 + 3
c) A = 20172016 - 2015 / 20172017 - 2015 và B = 20172015 + 1 / 20172016 + 1
1- 2+ 3- 4+ 5- 6 ...+ 2015- 2016+ 2017
giúp mình với nha
\(1-2+3-4+5-6+...+2015-2016+2017\)
\(=\left(1-2\right)+\left(3-4\right)+\left(5-6\right)+...+\left(2015-2016\right)+2017\)
\(=\left(-1\right)+\left(-1\right)+\left(-1\right)+...+\left(-1\right)+2017\) Dãy số trên có 2017 số thì có 1008 cặp -1 và số 2017.
\(=\left(-1\right).1008+2017\)
\(=-1008+2017\)
\(=1009\)
Tk mk nhé(nếu đúng)!Thank you!
Đúng 0
Bình luận (0)
Tính :A= [(2018/1)+(2017/2)+(2016/3)+(2015/4)+...+(4/2015)+(3/2016)+(2/2017)+(1/2018)]/[(2019/1)+(2019/2)+(2019/3)+(2019/4)+...+(2019/2015)+(2019/2016)+(2019/2017)+(2019/2018)+(2019/2019)]