\(\dfrac{25}{24}\times\dfrac{27}{5}\times2\times\dfrac{34}{9}\times\dfrac{36}{17}\)

\(=(\dfrac{25}{24}\times\dfrac{54}{5})\times\left(\dfrac{34}{9}\times\dfrac{36}{17}\right)\)

\(=\dfrac{45}{4}\times2\times4\)

\(=90\)

TraMy

a) x²-24x​-25=x²+x-25x-25

=x(x+1)-25(x+1)

=(x-25)(x+1)

b) x²-y²+14x​+49=(^​x²​+14x+49)-y²

=(x+7)²​-y²​=(x-y+7)(x+y+7)

a) (a - 2b)x(a + 2b)
b) x²-(y-3)²
 => (x-y+3)(x+y-3)
c) (2a + b - a)(2a + b + a)
=> (a+b)(3a+b)
d) (4(x - 1))² - (5(x + y))²
⇔ (4x - 4 - 5x - 5y)(4x - 4 + 5x + 5y)
⇔ -(x + 5y + 4)(9x + 5y + -4)
e) (x + 5)²
f) (5x - 2y)²
h) (x - 5)(x² + 5x + 25)

k) (x + 5)³

\(x\in\left\{\pm5\right\}\)

x = {-5, 5}

`Answer:`

a, `4x^2-24x+36=(x-3)^3`

`<=>4(x^2-6x+9)-(x-3)^3=0`

`<=>4(x-3)^2-(x-3)^3=0`

`<=>(x-3)^2.(4-x+3)=0`

`<=>(x-3)^2.(7-x)=0`

`<=>x-3=0` hoặc `7-x=0`

`<=>x=3` hoặc `x=7`

b, `(8x^3-7x^2):x^2=3x+\sqrt{\frac{9}{25}}`

`<=>8x^3:x^2-7x^2:x^2=3x+\sqrt{\frac{9}{25}}`

`<=>8x-7=3x+\sqrt{\frac{9}{25}}`

`<=>8x-7=3x+3/5`

`<=>8x=3x+\frac{38}{5}`

`<=>8x-3x=3x+\frac{38}{5}-3x`

`<=>5x=\frac{38}{5}`

`<=>x=\frac{38}{25}`

á,(x+7)²-y²

= (x+7+y)(x+7-y)

b, (x+1)(x-25)

chúc bạn luôn thành công trong cuộc sống nha

a) 

\(x^2-y^2+14x+49\)

\(=\left(x^2+14x+49\right)-y^2\)

\(=\left(x^2+2.7.x+7^2\right)-y^2\)

\(=\left(x+7\right)^2-y^2\)

\(=\left(x+y+7\right)\left(x-y+7\right)\)

Vậy ...

b)

 \(x^2-24x-25\)

\(=x^2-24x+144-169\)

\(=\left(x^2-24x+144\right)-169\)

\(=\left(x^2-2.12.x+12^2\right)-13^2\)

\(=\left(x-12\right)^2-13^2\)

\(=\left(x-12+13\right)\left(x-12-13\right)\)

\(=\left(x+1\right)\left(x-25\right)\)

Vậy ...

a, Ta có :\(-30+\left(25-x\right)=-1\)

               \(\Leftrightarrow\left(-30\right)+25-x=-1\)

                \(\Leftrightarrow25-x=\left(-1\right)-\left(-30\right)\)

                \(\Leftrightarrow25-x=29\\ \Leftrightarrow x=25-29\)

                    \(\Leftrightarrow x=\left(-4\right)\)

     Vậy \(x=-4\)

b,Ta có :\(\left(x+5\right)+\left(x-9\right)=x+2\)

            \(\Leftrightarrow x+5+x-9=x+2\)

            \(\Leftrightarrow2.x+\left(5-9\right)=x+2\)

           \(\Leftrightarrow\)   \(2.x+\left(-4\right)=x+2\)

            \(\Leftrightarrow2.x-x=4+2\)

                 \(\Leftrightarrow x=6\)

Vậy \(x=6\)

1) \(\left(x+1\right)\left(x+2\right)-3x\left(x-4\right)=x^2+3x+2-3x^2+12x=-2x^2+15x+2\)

2) \(\left(3x-4\right)\left(x-2\right)=3x\left(x-9\right)\)

\(\Leftrightarrow3x^2-10x+8=3x^2-27x\)

\(\Leftrightarrow17x=-8\Leftrightarrow x=-\dfrac{8}{17}\)

3) \(-3\left(x-4\right)\left(x-2\right)-x^2\left(-3x+18\right)+24x-25\)

\(=-3x^3+6x^2+12x^2-24x+3x^3-18x^2+24x-25=-25\)