A=300+276+429

B=300+429+276

Suy ra A =B

\(\frac{43}{171}\)và \(\frac{45}{169}\)Phân số trung gian là: \(\frac{43}{169}\)

Ta thấy: \(\frac{43}{171}\)< \(\frac{43}{169}\)< \(\frac{45}{169}\)nên \(\frac{43}{171}\)< \(\frac{45}{169}\)

tk nhé

Ta có:\(\frac{43}{171}< \frac{43}{169}\)

Mà \(\frac{43}{169}< \frac{45}{169}\Rightarrow\frac{43}{171}< \frac{45}{169}\)

1205>1005

Ta so sánh bằng cách :

\(\Rightarrow\)776 + 429 và 300 + 429 + 276

\(\Rightarrow\)776 + 429 và 429 + 576

\(\Rightarrow\)776 + 429 = 429 + 576 \(\Rightarrow\)776 + 429 = 729 + 276

(-276).752 < 347.57

(-276).752 < 347.57

\(\frac{72}{167}>\frac{71}{169}\)

\(\frac{63}{314}< \frac{65}{321}\)

\(\frac{25}{101}< \frac{46}{180}\)

a) 5^270 < 5^300

b) 13^100 < 13^102

c) 3^4995 > 3^4000

So sánh :

a) 125^90 và 25^150

125^90 = (5^3)^90 = 5^270

25^150 = (5^2)^150 = 5^300

125^90 < 25^150

B) 13^100 và 169^51

169^51 = (13^2)^51 = 13^102

13^100 < 169^51

c,243^999 và 9^2000

243^999 = (3^5)^999 = 3^4995

9^2000 = (3^2)^2000 = 3^4000

243^999 > 9^2000

\(\text{a) }125^{90}=\left(5^3\right)^{90}=5^{270}\)

\(25^{150}=\left(5^2\right)^{150}=5^{300}\)

\(\text{Vi }5^{270}< 5^{300}\Rightarrow125^{90}< 25^{150}\)

\(\text{b) }169^{51}=\left(13^{13}\right)^{51}=13^{663}\)

\(\text{Vi }13^{100}< 13^{663}\Rightarrow13^{100}< 13^{663}\)

\(\text{c) }243^{999}>9^{999}>9^{200}\)

\(\Rightarrow243^{999}>9^{200}\)

a,-(168+325) + ( 168 + 425 )

 = -168 - 325 + 168 + 425

= [ ( -168 ) + 168 ] + [ ( -325 ) + 425]

= 0 + 100

= 100

a,750

b,11

c,-200

d,26

-(168+325)+(168+425) = (-168+168)+(-325+425)= 0+100= 100

(38-276)+(38-65+276)=(38-38-65)+(276-276)=-65+0=-65

(269+135)+(-327-169)-(135-27)= (269-169)+(135-135)+ (327-27)=100+0+300= 400

271-(-43)+271-(-17)= (271-271)+(43+17)= 0+ 60=60

Chúc bạn học tốt