Thực hiện chuỗi phản ứng sau:
b) \(Al_2O_3\rightarrow Al\rightarrow Al_2\left(SO_4\right)_3\rightarrow AlCl_3\rightarrow Al\left(OH\right)_3\rightarrow Al_2O_3\)
c) \(Al\rightarrow AlCl_3\rightarrow Al\left(OH\right)_3\rightarrow Al_2O_3\rightarrow Al_2\left(SO_4\right)_3\rightarrow AlCl_3\)
a)\(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)
\(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)
\(2AlCl_3+3Ba\left(OH\right)_2\rightarrow2Al\left(OH\right)_3\downarrow+3BaCl_2\)
\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)
\(2Al+3S\underrightarrow{t^o}Al_2S_3\)
Viết PTHH hoàn thành các chuỗi phản ứng sau
1, \(Al\rightarrow Al_2O_3\rightarrow AlCl_3\rightarrow Al\left(OH\right)_3\rightarrow Al_2O_3\rightarrow Al\rightarrow AlCl_3\)
2,\(Fe\rightarrow FeSO_4\rightarrow Fe\left(OH\right)_2\rightarrow FeCl_2\)
3,\(Al\rightarrow AlCl_3\rightarrow Al\left(OH\right)_3\rightarrow Al_2O_3\rightarrow Al_2\left(SO_4\right)_3\rightarrow AlCl_3\rightarrow MgCl_2\)
giúp mk với, mk cảm ơn
1, (1) 4Al+ 3O2--(to)---> 2Al2O3
(2) Al2O3+6HCl---> 2AlCl3+ 3H2O
(3) AlCl3+3NaOH---->Al(OH)3+ 3NaCl
(4) 2Al(OH)3---(to)---> Al2O3+ 3H2O
(5)2Al2O3---(to+ đpnc)--> 4Al+ 3O2
(6) 2Al+ 3Cl2---> 2AlCl3
2, (1)Fe+ CuSO4-->Cu+ FeSO4
(2) FeSO4+ 2NaOH--> Fe(OH)2+ Na2SO4
(3) Fe(OH)2 +2HCl---> FeCl2+ 2H2O
Bài cuối tự làm nhé!
câu 3
2Al + 3Cl2 --t--> 2AlCl3
AlCl3 + 3NaOH -> 3NaCl + Al(OH)3
2Al(OH)3 -t-> Al2O3 + H2O
Al2O3 + 3H2SO4 -> Al2(SO4)3 + 3H2O
Al2(SO4)3 + 3BaCl2 -> 3BaSO4 + 2AlCl3
2AlCl3 + 3Mg -> 2Al + 3MgCl2
\(\left(1\right)4Al+3O_2\underrightarrow{t^o}2Al_2O_3\\ \left(2\right)Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3\downarrow+3NaCl\\ 2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\\ 2Al_2O_3\underrightarrow{dpnc}4Al+3O_2\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\)
Hoàn thành PT phản ứng:
\(Al\rightarrow Al_2O_3\rightarrow AlCl_3\rightarrow Al_2\left(SO_4\right)_3\rightarrow Al\left(OH\right)_3\rightarrow Al\left(NO_3\right)_3\rightarrow Al\rightarrow AlCl_3\)
\(FeS_2\rightarrow SO_2\rightarrow SO_3\rightarrow H_2SO_4\rightarrow CuSO_4\rightarrow Na_2SO_4\rightarrow NaOH\)
\(P\rightarrow P_2O_5\rightarrow H_3PO_4\rightarrow Na_3PO_4\rightarrow NaCl\rightarrow NaOH\)
\(Cl_2\rightarrow NaCl\rightarrow H_2\rightarrow H_2O\rightarrow NaOH\rightarrow Na_2SO_4\rightarrow NaNO_3\)
\(CaCO_3\rightarrow CO_2\rightarrow Na_2CO_3\rightarrow MgCO_3\rightarrow MgO\rightarrow MgCl_2\rightarrow MgSO_4\rightarrow Mg\left(NO_3\right)_2\rightarrow MgO\rightarrow Mg_3\left(PO_4\right)_2\)
Thực hiện chuỗi phản ứng
\(Al_2O_3\rightarrow AlCl_3\rightarrow Al\left(NO_3\right)\rightarrow Al\left(OH\right)_3\rightarrow NaAlO_2\)
\(\text{Al2O3+6HCl->2AlCl3+3H2O}\)
\(\text{AlCl3+3AgNO3->3AgCl+Al(NO3)3}\)
\(\text{Al(NO3)3+3NaOH->Al(OH)3+3NaNO3}\)
\(\text{Al(OH)3+NaOH->NaAlO2+2H2O}\)
Al2O3+6HCl---->2AlCl3+3H2O
AlCl3+3AgNO3----->Al(NO3)3+3AgCl
Al(NO3)3+3NaOH---->3NaNO3+Al(OH)3
Al(OH)3+NaOH---->NaAlO2+2H2O
Nhầm @@
\(Al\left(NO_3\right)_3\)
Viết các PTHH thực hiện các chuỗi biến hóa sau, ghi rõ điều kiện phản ứng ( nếu có ) :
a, \(SO_2\rightarrow Na_2SO_3\rightarrow Na_2SO_4\rightarrow NaOH\rightarrow Na_2CO_3\)
b, \(CaO\rightarrow CaCO_3\rightarrow CaO\rightarrow Ca\left(OH\right)_2\rightarrow CaCO_3\rightarrow CaSO_4\)
c, \(Fe\rightarrow FeCl_3\rightarrow Fe\left(OH\right)_3\rightarrow Fe_2O_3\rightarrow Fe_2\left(SO_4\right)_3\rightarrow FeCl_3\)
d, \(Fe\rightarrow FeCl_2\rightarrow Fe\left(NO_3\right)_2\rightarrow Fe\left(OH\right)_2\rightarrow FeSO_4\)
e, \(Cu\rightarrow CuO\rightarrow CuCl_2\rightarrow Cu\left(OH\right)_2\rightarrow CuO\rightarrow Cu\rightarrow CuSO_4\)
f, \(Al_2O_3\rightarrow Al\rightarrow AlCl_3\rightarrow NaCl\rightarrow NaOH\rightarrow Cu\left(OH\right)_2\)
a) SO2 + Na2O -> Na2SO3
Na2SO3 + H2SO4 -> Na2SO4 + SO2 + H2O
Na2SO4 + Ba(OH)2 -> BaSO4 \(\downarrow\)+ 2NaOH
2NaOH + CO2 -> Na2CO3 + H2O
b) CaO + CO2 -> CaCO3
CaCO3 \(\rightarrow^{t^o}\) CaO + CO2
CaO + H2O -> Ca ( OH)2
Ca ( OH)2 + CO2 -> CaCO3 + H2O
CaCO3 + H2SO4 -> CaSO4 + CO2 + H2O
c) 2Fe + 3Cl2 \(\rightarrow^{t^o}\) 2FeCl3
FeCl3 + 3NaOH -> Fe(OH)3 \(\downarrow\) + 3NaCl
2Fe(OH)3 \(\rightarrow^{t^o}\) Fe2O3 + 3H2O
Fe2O3 + 3H2SO4 -> Fe2(SO4)3 + 3H2O
Fe2(SO4)3 + 3BaCl2 -> 2FeCl3 + 3BaSO4\(\downarrow\)
d) Fe + 2HCl -> FeCl2 + H2
FeCl2 + 2AgNO3 -> 2AgCl\(\downarrow\) + Fe(NO3)2
Fe(NO3)2 + 2NaOH -> Fe(OH)2\(\downarrow\) + 2NaNO3
Fe(OH)2 + H2SO4 -> FeSO4 + 2H2O
a, SO2 + 2NaOH \(\rightarrow\)Na2SO3 + H2O
Na2SO3 + H2SO4 \(\rightarrow\)Na2SO4 + H2O + SO2
Na2SO4 + Ba(OH)2\(\rightarrow\) BaSO4+ 2 NaOH
CO2 + 2 NaOH \(\rightarrow\)Na2CO3 + H2O
b, CaO + CO2\(\rightarrow\) CaCO3
CaCO3 -t0-> CaO + CO2
CaO + H2O \(\rightarrow\)Ca(OH)2
Ca(OH)2 + CO2 \(\rightarrow\)CaCO3 + H2O
CaCO3 + H2SO4 \(\rightarrow\)CaSO4 + H2O + CO2
c, 2Fe + 3Cl2 -t0-> 2FeCl3
FeCl3 + 3NaOH \(\rightarrow\)Fe(OH)3 + 3NaCl
2Fe(OH)3 -t0-> Fe2O3 + 3H2O
Fe2O3 + 3H2SO4 \(\rightarrow\)Fe2(SO4)3 + 3H2O
Fe2(SO4)3 + 3BaCl2 \(\rightarrow\)2FeCl3 + 3BaSO4
d, Fe + 2HCl \(\rightarrow\)FeCl2 + H2
FeCl2 + 2AgNO3 \(\rightarrow\)Fe(NO3)2 + 2AgCl
Fe(NO3)2 + 2NaOH \(\rightarrow\)Fe(OH)2 + 2NaNO3
Fe(OH)2 + H2SO4\(\rightarrow\) FeSO4 + 2H2O
e, 2Cu + O2 -t0-> 2CuO
CuO + 2HCl \(\rightarrow\)CuCl2 + H2O
CuCl2 + 2NaOH\(\rightarrow\) Cu(OH)2 + 2NaCl
Cu(OH)2 -t0-> CuO + H2O
CuO + H2 -t0-> Cu + H2O
Cu + 2H2SO4đặc \(\rightarrow\)CuSO4 + SO2 + 2H2O
f, 2Al2O3 -đpnc/ criolit-> 4Al + 3O2
2Al + 3Cl2 -t0-> 2AlCl3
AlCl3 + 3NaOH \(\rightarrow\)Al(OH)3 + 3NaCl
2NaCl + 2H2O -đpmn-> 2NaOH + Cl2 + H2
2NaOH + CuCl2 \(\rightarrow\)Cu(OH)2 + 2NaCl
Cân bằng PTHH sau:
a) \(K_2O+H_2O\rightarrow KOH\)
b) \(Fe+Cl_2\rightarrow FeCl_3\)
c) \(Al\left(OH\right)_3+H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+H_2O\)
d) \(FeS_2+O_2\rightarrow Fe_2O_3SO_2\)
e) \(Al+HCl\rightarrow AlCl_3+H_2\)
f) \(KClO_3\rightarrow KCl+O_2\)
g) \(P+O_2\rightarrow P_2O_5\)
h) \(Fe+O_2\rightarrow Fe_3O_4\)
i) \(Al+CuSO_4\rightarrow Al_2\left(SO_4\right)_3+Cu\)
j) \(K+H_2O\rightarrow KOH+H_2\)
a) \(K_2O+H_2O->2KOH\)
b) \(2Fe+3Cl_2->2FeCl_3\)
c) \(2Al\left(OH\right)_3+3H_2SO_4->Al_2\left(SO_4\right)_3+6H_2O\)
d) \(4FeS_2+11O_2->2Fe_2O_3+8SO_2\)
e)\(2Al+6HCl->2AlCl_3+3H_2\)
f) \(2KClO_3->KCl+3O_2\)
g) \(4P+5O_2->2P_2O_5\)
h) \(3Fe+2O_2->Fe_3O_4\)
i) \(2Al+3CuSO_4->Al_2\left(SO_4\right)_3+3Cu\)
j) \(2K+2H_2O->2KOH+H_2\)
Cân bằng PTHH:
\(Fe+HCl\rightarrow FeCl_2+H_2\)
\(Na+HCl\rightarrow NaCl+H_2\)
\(Al+HCl\rightarrow AlCl_3+H_2\)
\(Al\left(OH\right)_3+H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+H_2O\)
`Fe + 2HCl -> FeCl_2 + H_2`
`2Na + 2HCl -> 2NaCl + H_2`
`2Al + 6HCl -> 2AlCl_3 + 3H_2`
`2Al(OH)_3 + 3H_2SO_4 -> Al_2(SO_4)_3 + 6H_2O`
Fe + 2HCl → FeCl2 + H2
2Na + 2HCl → 2NaCl + H2
2Al + 6HCl → 2AlCl3 + 3H2
2Al + 3H2SO4 → Al2(SO4)3 + 6H2O
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(2Na+2HCl\rightarrow2NaCl+H_2\)
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)
Cân bằng các PTHH sau :
a) \(\left(NH_4\right)_2CO_3+NaOH\rightarrow Na_2CO_3+NH_3+H_2O\)
b) \(Cu+H_2SO_4\rightarrow CuSo_4+SO_2+H_2O\)
c) \(KMnO_4+HCl\rightarrow KCl+MnCl_2+Cl_2+H_2O\)
d) \(FeSO_4+KMnO_4+H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+K_2SO_4+MnSO_4+H_2O\)
e) \(Al+HNO_3\rightarrow Al\left(NO_3\right)_3+NH_4NO_3+H_2O\)
Mới lớp 8 mà cân bằng electron rồi à bạn :3
a) 1:2:1:2:2
b) 1:2:1:1:2
c) 2:16:2:2:5:8
d) 10:2:8:5:1:2:8
e) 8:30:8:3:9
Cân bằng các PTHH sau :
a)
b)
c)2
d)10
e)8
Giúp mình luôn nha!
Hoàn thành các chuỗi phản ứng sau:
\(S\rightarrow SO_2\rightarrow SO_3\rightarrow H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3\)
Cảm ơn trc!
Thêm cách khác dễ hơn của PT số 4:
\(2Fe\left(OH\right)_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+6H_2O\)
