Bạn học căn thức chưa ?

phan tich cac da thuc sau thanh nhan tu theo mau:

a)\(2x^3-x\)

\(=x\left(2x^2-1\right)\)

\(=x\left(\left(\sqrt{2}x\right)^2-1^2\right)\)\

\(=x\left(\sqrt{2}x-1\right)\left(\sqrt{2}x+1\right)\)

b)\(5x^2\left(x-1\right)-15x\left(x-1\right)\)

\(=\left(5x^2-15x\right)\left(x-1\right)\)

\(=5x\left(x-3\right)\left(x-1\right)\)

d)\(3x\left(x-2y\right)+6y\left(2y-x\right)\)

\(=3x\left(x-2y\right)-6y\left(x-2y\right)\)

\(=\left(3x-6y\right)\left(x-2y\right)\)

\(=3\left(x-2y\right)\left(x-2y\right)\)

\(=3\left(x-2y\right)^2\)

x²-xy-2y²

= x²-2xy+xy-2y²

=x(x-2y)+y(x-2y)

=(x-2y)(x+y)

a, = (xy-y^2) + (2x-2y) = y(x-y) + 2.(x-y) = (x-y).(y+2) 

b, = (x+y)^2 - 9 = (x+y-3).(x+y+3)

\(xy-y^2-2x-2y\)   

=(xy-y).(2x-2y)

=y(x-y).2(x-y)

=(x-y).(y-2)

camr ơn bạn nha

P= 125x^3-8y^3

  =5^3x^3-2^3y^3

  =(5x)^3-(2y)^3

  =(5x-2y)(25x^2+10xy+4y^2)

P=4x(x-2y)+8y(2y-x)

  =4x(x-2y)-8y(x-2y)

  =(4x-8y)(x-2y)

  =4(x-2y)(x-2y)

  =4(x-2y)^2

(2x+1)^2-(x-1)^2=(2x+1-x+1)(2x+1+x-1)

                       =(x+2)3x

K NHA!

2xy.(3x^2y-4xy^2)-1/2x^2y^2.(12x-16y)+xy.(3-13xy)+13.(x^2y^2-1)

\(=x\left(x^2-2xy+y^2\right)=x\left(x-y\right)^2\)

a) x^2+4x+3=x^2+x+3x+3=x(x+1)+3(x+1)=(x+1)(x+3)

b) 4x^2+4x-3=4x^2+4x+1-4=(2x+1)^2-4=(2x+1-2)(2x+1+2)=(2x-1)(2x+3)

c) x^2-x-12=x^2-4x+3x-12=x(x-4)+3(x-4)=(x-4)(x+3)

d) 4x^4+4x^2y^2-8y^4=4(x^4+x^2y^2-2y^4)=4(x^4-x^2y^2+2x^2y^2-2y^4)=4(x^2-y^2)(x^2+2y^2)=4(x-y)(x+y)(x^2+2y^2)

a) \(x^2+4x+3\)

\(=x^2+x+3x+3\)

\(=\left(x^2+x\right)+\left(3x+3\right)\)

\(=x\left(x+1\right)+3\left(x+1\right)\)

\(=\left(x+1\right)\left(x+3\right)\)

c) \(x^2-x-12\)

\(=x^2-4x+3x-12\)

\(=\left(x^2-4x\right)+\left(3x-12\right)\)

\(=x\left(x-4\right)+3\left(x-4\right)\)

\(=\left(x-4\right)\left(x+3\right)\)

\(x^2+4x+3\)

\(=x^2+x+3x+3\)

\(=x\left(x+1\right)+3\left(x+1\right)\)

\(=\left(x+1\right)\left(x+3\right)\)

Đây mà là toán lớp 8ak

Đặt hết nhân tử chung ra là ra có gì đâu

Đây mà là toán lớp 8ak

Đặt hết nhân tử chung ra là ra có gì đâu