1. khi thêm 4 vào bên trái số đó nghĩa là ta đã cộng thêm với 400

ta được số mới gấp 9 lần số ban đầu

nên 400 gấp 8 lần số ban đầu

hay số ban đầu là \(400:8=50\)

2. khi thêm 9 vào bên trái số đó nghĩa là ta đã cộng thêm với 900

ta được số mới gấp 13 lần số ban đầu

nên 900 gấp 12 lần số ban đầu

hay số ban đầu là \(900:12=75\)

Gọi số phải tìm là ab. Viết thêm chữ số 4 vào bên trái ta dược số 4ab. Theo bài ra ta có:
94ab = ab x 9
400 + ab = ab x 9
400 = ab x 9 – ab
400 = ab x (9 – 1)
400 = ab x 8
ab = 400: 8
ab = 50

gọi số đó là abcd

abcd5=5x1abcd

abcdx10+5=50000+abcdx5

suy ra abcdx5=49995

nên abcd=49995:5

     abcd=9999

vậy số đó là 9999

gọi số đó là abcd

ta có

1abcd x 5 =abcd5 
(10000+abcd).5=abcd.10+5 
50000+5.abcd=10.abcd+5 
5.abcd=50000-5 
abcd=49995:5 
abcd=9999

vậy số đó là : 9999

1,Gọi số cần tìm là ab 

Khi viết thêm chữ số 9 vào bên trái ta có : 9ab

Theo bài ra ta có :

ab x 13 = 9ab

ab x 13 = 900 + ab

ab x 13 - ab =900 

ab x ( 13 - 1 ) = 900

ab x 12 = 900

ab = 900 : 12

ab = 75

2, Nếu viết thêm chữ số 5 vào bên phải thì số đó sẽ tăng 10 lần và 5 đơn vị 

 ( bạn tự vẽ sơ đồ )

Số cần tìm là : ( 1112  - 5 ) : (10 - 1 ) = 123 

Gọi số phải tìm là A. Nếu viết thêm chữ số 4 vào bên trái ta dược số 4A.Theo bài ra ta có:
94A = A x 9
400 + A = A x 9
400 = A x 9 – A
400 = A x (9 – 1)
400 = A x 8
A= 400: 8
A = 50

                               Bai giai

    goi so can tim la ab (a>0)

    Khi viet them chu so 4 vao ben trai so can tim ta duoc mot so gap chin lan so phai tim( 9ab) va so do chia het  cho 9.                                     Neu         a= 1;b= 4 -> 414                                                                                                                                                                                 a= 2;b= 3 -> 423                                                                                                                                                                                   a= 3;b= 2 -> 432                                                                                                                                                                                  a= 4;b= 1 -> 441                                                                                                                                                                                  a= 5;b= 0 -> 450                                                                                                                                                                                   a= 6;b= 8 -> 468                                                                                                                                                                                   a=7;b= 7 ->  477                                                                                                                                                                                  a=8;b=6 ->  486                                                                                                                                                                                    a=9;b=6 -> 496                                                                                                                                                                       Ta thay a=5;b=0 thi thoa man, vay so can tim la 50                                                                                                                                   bai nay dung day co giao minh giang bai nay ma

Gọi số phải tìm là A. Nếu viết thêm chữ số 4 vào bên trái ta dược số 4A.Theo bài ra ta có:
94A = A x 9
400 + A = A x 9
400 = A x 9 – A
400 = A x (9 – 1)
400 = A x 8
A= 400: 8
A = 50 

Số đó là : 50 nha bạn. cho mik nha

Gọi số cần tìm là ab ( 0 < a,b < 10 ) => Số mới là 4ab 

Theo đề ra ta có :

 4ab         =    ab x 9

400 + ab =    ab x 9

  400        =    ab x 8

 400 : 8   =       ab 

     50      =        ab 

Vậy số cần tìm là 50

Thử lại : 450 : 50 = 9 (Đ)

                                Đáp số : 50 

Khi viết thêm chữ số 4 vào bên trái số có 2 chữ số thì số đó tăng 400 đơn vị.

       Số cần tìm là:

            400 : ( 9 – 1 ) = 50

TL: 50 x 9 = 450 (Đ)

                          Vậy số đó là 50.

Gọi 3 số là abc

theo đb ta có

abc1=3  x  2abc

abc x 10   +1 =3x 2000+3abc

7 abc= 5999

abc=857 

vậy số đó là 857

 857 dung 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\(1,\Rightarrow\overline{7ab}=36\cdot\overline{ab}\Rightarrow\overline{ab}+700=36\cdot\overline{ab}\\ \Rightarrow35\cdot\overline{ab}=700\Rightarrow\overline{ab}=20\\ 2,\Rightarrow\overline{30abc}=151\cdot\overline{abc}\Rightarrow\overline{abc}+30000=151\cdot\overline{abc}\\ \Rightarrow\overline{abc}\cdot150=30000\Rightarrow\overline{abc}=200\\ 3,\Rightarrow\overline{ab5}=10\cdot\overline{ab}+5=554+\overline{ab}\\ \Rightarrow\overline{ab}\cdot9=549\Rightarrow\overline{ab}=61\\ 4,\Rightarrow\overline{ab78}=\overline{ab}\cdot100+78=1266+\overline{ab}\\ \Rightarrow\overline{ab}\cdot99=1188\Rightarrow\overline{ab}=12\\ 5,\Rightarrow\overline{abc85}=\overline{abc}\cdot100+85=43348+\overline{abc}\\ \Rightarrow\overline{abc}\cdot99=43263\Rightarrow\overline{abc}=437\\ 6,7,\text{Đề thiếu}\)

a, Gọi số đó là ab(có gạch trên đầu) đk ab thuộc N

Theo đề bài ta có 

9ab=ab.13

900+10a+b=(10a+b).13

900+10a+b=130a+13b

900=120a+12b

Ta có a=7 vì a<7 thì 12b=180 vậy b=15 ko thỏa mãn a=8,9 cũng ko thỏa mãn

từ đó 12b=900-840=60

Vậy b=60:12

b=5

Vậy số đó là 75

b Gọi số đó là abc(có gạch trên đầu) đk abc thuộc N và a,b,c thuộc N a khác 0

Nếu viết thêm chữ số 5 vào bên phải số đó thì tức là đã gấp số đó lên 10 lần và 5 đơn vị

9.abc=1112-5

9.abc=1107

Vậy abc=1107:9

abc=123 Vậy số đó là 123

b) Gọi số cần tìm là abc

theo đề ta có abc5= abc+1112

=> abc.10+5=abc+1112

=> abc.9=1112-5

=> abc.9=1107

=> abc=1107chia 5

=> abc=123

a.

     Gọi số cần tìm là : ab

nếu viết thêm chữ số 9 vào bên trái ta được:9ab

hiệu của 9ab và ab là:

9ab-ab=900

ta có sơ đồ:

số ab:   1 ô

số 9ab:  13 ô(số 9ab lớn hơn ab là 900)

hiệu số phần bằng nhau:

13-1=12(phần)

số ab là:

900:12 nhân 1= 75

đáp số:75