\(25\le5^{x+1}\le625\Leftrightarrow5^2\le5^{x+1}\le5^4\)

\(\Leftrightarrow2\le x+1\le4\)

\(\Rightarrow x\in\left(1;2;3\right)\)

x=2,3,4,5

\(25\leq5^x\leq3125\)

\(\implies 5^2\leq5^x\leq5^5\)

\(\implies 2\leq x\leq5\)

\(\implies x\in\{2;3;4;5\}\)

~ Học tốt a~

\(a,\)\(A=\left\{x\in R|x< 3\right\}\Rightarrow A=\left(\text{ -∞;3}\right)\)

\(B=\left\{-1;0;1;2;3;4;5\right\}\)

\(\Rightarrow A\cap B=\left\{-1;0;1;2\right\}\)

\(b,x=-1\Rightarrow y=1-2\left(-1\right)+m=m+3\) 

\(x=1\Rightarrow y=1-2+m=m-1\)

\(\Rightarrow C=(m-1;m+3]\subset A\)

\(\Rightarrow C\subset A\Leftrightarrow m+3< 3\Leftrightarrow m< 0\)

a) x=19

b) x=6

c) x có thể là 2,3,4,5

Phạm Kim Cương bn có thể giải hẳn ra cho mik đc ko

Tìm x€ Z : 

\(c,25\le5^x\le3125\)

\(\Leftrightarrow5^2\le5^x\le5^5\)

\(\Rightarrow2\le x\le5\)

\(\Leftrightarrow2\le2;3;4;5\le5\)

Vậy \(x\in\left\{2;3;4;5\right\}\)

Ta thấy \(\left|2x+3\right|\ge0\forall x\)

Để \(\left|2x+3\right|\le5\) 

\(\Rightarrow-5\le2x+3\le5\)

\(\Rightarrow-4\le x\le1\)

Mà x > 0

\(\Rightarrow x=1\)

KL x=1

Ta có:\(2x+3=5\)

\(\Rightarrow2x=5-3\)

\(\Rightarrow2x=2\)

\(\Rightarrow x=1\)

Vậy \(x=1\).Mình nhanh nhất tịck nhé

a)X= 40-15=25

b)2(x+35)=215-15

2(x+35)=200

x+35=100

X=65

c)(2x-3)^3=5^3

2x-3=5

2x=8

x=4

1)x=-3;3

y=-5;5