Bai 1 : Tim gia tri nho nhat cua bieu thuc :
1, \(x^2-6x+6\)
2, \(3x^2-5x+2\)
3, \(5x^4+9x^2+13\)
4, \(x^2-5x+3\)
5, \(2x^2-5x-1\)
Những câu hỏi liên quan
giup to 3 bai nay
1. gia tri cua x thoa man (2x+3)(x+1)2-(2x+3)(2x-3)
2. so nghiem cua da thuc x3+6x2+11x+6 la ?
3. bieu thuc C = 8-5x-2x2 dat gia tri lon nhat tai x = ?
giup to 3 bai nay
1. gia tri cua x thoa man (2x+3)(x+1)2-(2x+3)(2x-3)
2. so nghiem cua da thuc x3+6x2+11x+6 la ?
3. bieu thuc C = 8-5x-2x2 dat gia tri lon nhat tai x = ?
1.gia tri a de da thuc P(x)=3x3-8x2+6x-a chia het cho Q(x)=3x2-5x+1 la a =?
2.khi a+b=1 .gia tri nho nhat cua bieu thuc a3+b3+ab la?
3.tong cac gia tri cua x thoa man x5=x4+x3+x2+x+2 la?
1. gia tri cua x thoa man (2x+3)(x+1)2-(2x+3)(2x-3)
2. so nghiem cua da thuc x3+6x2+11x+6 la ?
3. bieu thuc C = 8-5x-2x2 dat gia tri lon nhat tai x = ?
Tim gia tri nho nhat cua cac bieu thuc sau:
B=2x2+10x-1
C=5x-x2
\(2x^2+10x-1\)
\(=2\left(x^2+5x-\frac{1}{2}\right)\)
\(=2\left(x^2+2.x.\frac{5}{2}+\frac{25}{4}-\frac{27}{4}\right)\)
\(=2\left(\left(x+\frac{5}{2}\right)^2-\frac{27}{4}\right)\)
\(=\frac{-27}{2}-2\left(x+\frac{5}{2}\right)^2\le\frac{-27}{2}\)
\(MinB=\frac{-27}{2}\Leftrightarrow x+\frac{5}{2}=0\Rightarrow x=-\frac{5}{2}\)
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+) \(B=2.\left(x^2+5x-\frac{1}{2}\right)\)
\(B=2.\left(x^2+2.x.\frac{5}{2}+\frac{25}{4}-\frac{27}{4}\right)\)
\(B=2.\left[\left(x+\frac{5}{2}\right)^2-\frac{27}{4}\right]\)
\(B=1.\left(x+\frac{5}{2}\right)^2-\frac{27}{2}\ge-\frac{27}{2}\)
Vậy Min B=-27/2 khi và chỉ khi x=-5/2
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Xem thêm câu trả lời
tim gia tri lon nhat ( hoac nho nhat ) cua cac bieu thuc sau:
a) A = x^2 - 6x + 11
b) B = 2x^2 + 10x - 1
c) C = 5x - x^2
giai jup mik voi
cho x.0 .Tim gia tri nho nhat cua bieu thuc A=9x2-5x+1/9x+2013
tim gia tri nho nhat cua bieu thuc
A= (x-1)(x+2)(x+3)(x+6)
B=\(5x^2-4xy+y^2+4x+7\)
A=(x^2+5x-6)(x^+5x+6)=(x^2+5x)^2-36>=-36
A min=-36 <=> x(x+5)=0
<=>x=0;x=-5
B=(4x^2-4xy+y^2)+(x^2+4x+4)+3=(2x-y)^2+(x+2)^2+3>=3
B min=3 <=> x=-2;y=-4
tick mik nha
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tim cac gia tri cua x de bieu thuc sau nhan gia tri am
a)x mu 2 + 5x b)x mu 2 - 5/2x c)3(2x+3)(3x-5) d)x - 2/x-6 e) x mu 2 -1/x mu 2