ĐỀ bài thiếu dữ kiện

mình chắc chắn ;lun

hong hieu thieu de bai hay sao y

a) \(\left(x-\frac{1}{3}\right)^2-\frac{1}{4}=0\)

\(\Leftrightarrow\left(x-\frac{1}{3}\right)^2=\frac{1}{4}\)

\(\Leftrightarrow\left(x-\frac{1}{3}\right)^2=\left(\frac{1}{2}\right)^2\)

\(\Leftrightarrow\orbr{\begin{cases}x-\frac{1}{3}=\frac{1}{2}\\x-\frac{1}{3}=\frac{-1}{2}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{5}{6}\\x=\frac{-1}{6}\end{cases}}}\)

Vậy x= 5/6 hoặc -1/6

b) - Nếu x=0 thì \(5^y=2^0+624=1+624=625=5^4\Rightarrow y=4\left(y\in N\right)\)

- Nếu x \(\ne\) 0 thì vế trái là số chẵn , vế phải là số lẻ \(\forall x;y\inℕ\) ( vô lí)

Vậy x=0, y=4

thank you bạn.

1)3^x+1.(3³)^x=3⁵

3^(x+1+3x)=3⁵

^{\(\Rightarrow\)}x+1+3x=5

4x+1=5

4x=5-1

4x=4

x=4:4

x=1 vậy x=1

(-2x-7)-(-5x+18)=35

=>-2x-7+5x-18=35

=>3x-25=35

=>3x=35+25

=>3x=60

=>x=60:3

=>x=20

(-2x-7)-(-5x+18)=35

-2x-7+5x-18=35

(-2x+5x)-(7+18)=35

3x-25=35

3x=35+25

3x=60

x=60:3

x=20

Vậy x=20

\(\left(-2x-7\right)-\left(5x+18\right)=35.\)

\(\Leftrightarrow-2x-7-5x-18=35\)

\(\Leftrightarrow-7x-25=35\)

\(\Rightarrow-7x=60\)

\(\Leftrightarrow x=-\frac{60}{7}\)

Vậy \(x=-\frac{60}{7}\)

-12+20=5x-x

8=4x

x=2

vậy x=2

\(-12+x=5x-20\)

\(-12+20=5x-x=4x\)

\(\Rightarrow8=4x\)

\(\Leftrightarrow x=2\)

giải

(-12)+x=5.x-20

5x+x=(-12)-20

6x = -32

x = (-32) : 6 

x = fhdguhijitr

\(A=\left\{2x-3\left(x-1\right)-5\left[x-4\left(3-2x\right)+10\right]\right\}.\left(-2x\right)\)

\(=\left\{2x-3x+3-5\left[x-12+8x+10\right]\right\}.\left(-2x\right)\)

\(=\left\{-x+3-5\left(7x-2\right)\right\}.\left(-2x\right)\)

\(=\left(-x+3-35x+10\right).\left(-2x\right)\)

\(=\left(-36x+13\right).\left(-2x\right)\)

\(=72x^2-26x\)

\(\frac{1}{2}\left(\frac{4}{9}-x\right)-\frac{3}{2}\left(16-x\right)+\frac{1}{2}\left(5x+10\right)=0\)

\(\Leftrightarrow\frac{2}{9}-\frac{1}{2}x-24+\frac{3}{2}x+\frac{5}{2}x+5=0\)

\(\Leftrightarrow-\frac{169}{9}=\frac{7}{2}x\Leftrightarrow x=-\frac{338}{63}\)

Sai thì thông cảm cho mk nha

đkxđ:xx>3 

\(\left|5-2x\right|=x-4\) 

=>TH1:

\(5-2x=x-4\)

-x-2x=-5-4

-3x=-9

x=3(loại)

TH2:

5-2x=-x+4

x-2x=-5+4

-x=-1

x=1(loại)

vậy ko tìm đc x thỏa mãn đề bài

\(\left|5-2x\right|-3=x-7\)

\(\left|5-2x\right|=x-7+3\)

\(\left|5-2x\right|=x-4\)

Đk: \(x-4\ge0\)\(\Rightarrow x\ge4\)

Ta có: \(\left|5-2x\right|=x-4\)

\(\Rightarrow\orbr{\begin{cases}5-2x=x-4\\5-2x=-x+4\end{cases}\Rightarrow}\orbr{\begin{cases}-2x-x=-4-5\\-2x+x=4-5\end{cases}\Rightarrow}\orbr{\begin{cases}3x=9\\-x=1\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)( cả 2 trường hợp x ko thỏa mãn )

Vậy \(x\in\varnothing\)

Nhầm :(

-2x + x = 4 - 5

<=> -x = -1

<=> x = 1 ( ko thỏa mãn )

\(3^{x+4}=9^{2x-1}\)

\(\Rightarrow3^{x+4}=3^{4x-2}\)

\(\Rightarrow x+4=4x-2\)

\(\Rightarrow3x=6\Rightarrow x=2\)

3x+4=92x−13x+4=92x−1

⇒3x+4=34x−2⇒3x+4=34x−2