so sanh : 1/2010 va -7/19
so sanh
(19^2009+5^2009)^2010 va (19^2010+5^2010)^2009
so sanh A=(192009+52009)2010 va B=(192010+52010)2009
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Cac ban giup may.khong quy dong so sanh;A=-9/10^2010+-9/10^2011 va B=-9/10^2011+-19/10^2010
\(A=\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}\)
\(B=\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
\(\frac{-9}{10^{2010}}>\frac{-19}{10^{2010}}\)
\(\Rightarrow\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}>\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
\(\Rightarrow A>B\)
so sanh (20102011+1)/(20102012+1)va( 20102010+1)/(20102011+1)
so sanh (20102011+1)/(20102012+1)va( 20102010+1)/(20102011+1)
so sanh 2^1+2^2+2^3+...+2^2010 va 2^2010+1
So sanh A va B biet A=2010/2011+2011/2012+2012/2010 va B=1/3+1/4+1/5+....+1/17
So sanh :2009^2009+1/2009^2010+1 va 2009^2010-2/2009^2011-2
so sanh 201050+1/201049+1 va 201049+1/201048+1