rút gọn biểu thức A =-2/1.3 -2/3.5 -2/5.7 -...........-22/19.21 -2/23.25- -5/25.27 -1/27
Rút gọn biểu thức
A=-2/1.3-2/3.5-2/5.7-....-2/19.21-2/23.25-2/25.27-1/27
A=........
\(A=-\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{25.27}\right)-\frac{1}{27}\)
\(=-\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{25}-\frac{1}{27}\right)-\frac{1}{27}\)
\(=-\left(1-\frac{1}{27}\right)-\frac{1}{27}\)
\(=-1+\frac{1}{27}-\frac{1}{27}\)
\(=-1\)
rút gọn biểu thức
A= -2/1.3-2/3.5-2/5.7-..-2/19.21-2/23.25-2/25.27-1/27
ta được A=
\(A=-\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{25.27}\right)-\frac{1}{27}\)
\(=-\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{25}-\frac{1}{27}\right)-\frac{1}{27}\)
\(=-\left(1-\frac{1}{27}\right)-\frac{1}{27}\)
\(=-1+\frac{1}{27}-\frac{1}{27}\)
\(=-1\)
sao làm như vậy được??? 2/19.21 và 2/23.25 bn k làm được như thế đâu vì nó k cùng quy luật với các ps kia
Rút gọn:
A= 2/1.3 - 2/3.5 - 2/5.7 - ... - 2/19.21 - 2/23.25 - 2/25.27 - 1/27
Đề thi violympic vong 17 hay 16 j ó
Bn nào giải nhnh mk tik cho
\(A=-\left(\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{25.27}\right)-\dfrac{1}{27}\)
\(=-\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{25}-\dfrac{1}{27}\right)-\dfrac{1}{27}\)
\(=\)\(-\left(1-\dfrac{1}{27}\right)-\dfrac{1}{27}\)
\(=-1+\dfrac{1}{27}-\dfrac{1}{27}\)
\(=-1+\left(\dfrac{1}{27}-\dfrac{1}{27}\right)\)
\(=-1+0\)
\(=-1\)
A=2/1.3-2/3.5-2/5.7-...-2/19.21-2/21.23-2/23.25-1/27
A=\(\dfrac{2}{1.3}-\dfrac{2}{3.5}-\dfrac{2}{5.7}-.....-\dfrac{2}{23.25}-\dfrac{1}{27}\)
A=\(\dfrac{2}{3}-\left(\dfrac{2}{3.5}+\dfrac{2}{5.7}+....+\dfrac{2}{23.25}\right)-\dfrac{1}{27}\)
A=\(\dfrac{2}{3}-\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+......+\dfrac{1}{23}-\dfrac{1}{25}\right)-\dfrac{1}{27}\)
A=\(\dfrac{2}{3}-\left(\dfrac{1}{3}-\dfrac{1}{25}\right)-\dfrac{1}{27}\)
A=\(\dfrac{2}{3}-\dfrac{22}{75}-\dfrac{1}{27}\)
A=\(\dfrac{227}{675}\)
rút gọn phân số A= \(\frac{-2}{1.3}\)- \(\frac{2}{3.5}\)- \(\frac{2}{5.7}\)-...-\(\frac{2}{25.27}\)-\(\frac{2}{27}\)
\(=-\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{25.27}\right)-\frac{2}{27}\)
\(=-\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{25}-\frac{1}{27}\right)-\frac{2}{27}\)
\(=-\left(1-\frac{1}{27}\right)-\frac{2}{27}\)
\(=-1+\frac{1}{27}-\frac{2}{27}\)
\(=-\frac{28}{27}\)
Rút gọn biểu thức
\(A=\)\(-\)\(\dfrac{2}{1.3}\)\(-\)\(\dfrac{2}{3.5}\)\(-\)\(\dfrac{2}{5.7}\)\(-\)...\(-\)\(\dfrac{2}{19.21}\)\(-\)\(\dfrac{2}{23.25}\)\(-\)\(\dfrac{2}{25.27}\)\(-\)\(\dfrac{1}{27}\)
ta được \(A=\)\(...\)
Tính A=2/1.3-4/3.5+6/5.7-8/7.9+...-20/19.21
a)Tính: 1/1.3 + 1/3.5 + 1/5.7 +...+1/19.21
b) chúng minh: A= 1/1.3 + 1/3.5 +...+ 1/(2n-1)(2n+1) < 1/2
a) Đặt B= 1/1.3 + 1/3.5 + 1/5.7 + .....+ 1/19.21
Ta có: 2B= 2/1.3 + 2/3.5 + 2/5.7 + ....+ 2/19.21
= 1- 1/3 + 1/3-1/5 + 1/5-1/7 +....+ 1/19-1/21
= 1-1/21 = 20/21
=> B= 20/21 : 2 => B= 10/21
b) Như trên, ta có: 2A= 1- (1/2n + 1) => A=( 1-1/2n+1).1/2
=> A= 1/2- 1/2n+1
=> A< 1/2 ( đpcm )