(x + 1) + (x + 2) + (x + 3) + .... + (x + 2013) = 20132014 

(x + x + x + ... + x) + (1 + 2 + 3 + ... + 2013) = 20132014 

2013x + 2027091 = 20132014 

2013x = 20132014 - 2027091

2013x = 18104923

=> x =8994,000497

\(a,\Leftrightarrow3\left(x+3\right)=0\Leftrightarrow x=-3\\ b,\Leftrightarrow\left(x^2-2\right)\left(6x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x^2=2\\6x=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\sqrt{2}\\x=-\sqrt{2}\\x=-\dfrac{1}{6}\end{matrix}\right.\\ c,\Leftrightarrow\left(x-2013\right)\left(4x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2013\\x=\dfrac{1}{4}\end{matrix}\right.\\ d,\Leftrightarrow\left(x+1\right)^2-\left(x+1\right)=0\\ \Leftrightarrow\left(x+1\right)\left(x+1-1\right)=0\\ \Leftrightarrow x\left(x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)

(x.2013)+(1+2...+2013)=2014x

(x.2013)+......a...........=2014x

a=2014x-2013x

a=1.x

suy ra a=x(tu tim a)

Ta có :

|x+1|  0

|x+2|  0

 ..........

|x+2013|  0

=> 2014.x  0

Mà 2014 >0 nên x  0

=> (x+1) + (x+2) + (x+3) + ... + (x+2013) = 2014x

Mỗi ngoặc trên là một số hạng

=> x.2013 + (1+2+3+...+2013)=2014x

=>1+2+3+...+2013=x

hay x=1+2+3+...+2013

      x= 

      (còn lại chị tự tính, mong chị thông cảm)

\(\left(1+2+...+2012+2013\right)+\left(x+x+...+x\right)\)=\(2014x\)

=\(\left(1+2+...+2013\right)+100x=2014x\)

= \(2027091\times100x=2014x\)

                           \(100x=2014x\div2027091\)

                           \(100x=2014x\times\frac{1}{2027091}\)

                           \(100x=\frac{2014x\times1}{2027091}\)

                           \(100x=\frac{2x}{2013}\)

                           \(x=\frac{2x}{2013}\div100\)

                           \(x=\frac{2x}{2013}\times\frac{1}{100}\)

                           \(x=\frac{x}{100650}\)

                           \(x=x\div100650\)

                           \(x=x\times\frac{1}{100650}\)

                      \(\Rightarrow x\times\frac{1}{100650}-x\)=\(\frac{1}{100650}\times x-x\)

                                                           \(=\frac{1}{100650}\)

\(\frac{x+1}{2013}+\frac{x+2}{2012}+\frac{x+3}{2011}=-3\)

\(=>\frac{x+1}{2013}+\frac{x+2}{2012}+\frac{x+3}{2011}+3=0\)

\(=>\frac{x+1}{2013}+1+\frac{x+2}{2012}+1+\frac{x+3}{2011}+1=0\)

\(=>\frac{x+2014}{2013}+\frac{x+2014}{2012}+\frac{x+2014}{2011}=0\)

\(=>\left(x+2014\right)\left(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}\right)=0\)

=>x+2014=0 (vì \(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}\) khác 0)

=>x=-2014

ai làm ơn giúp mình mình sẽ trao

0000000000000000000000000000000000000000000000000000000

2012

âm 2012