Rút gọn phân số:
a) \(\dfrac{3.7.13.37.39-10101}{505050-70707}\)
b)\(\dfrac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
rút gọn p/s:
a,\(\dfrac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
b, \(\dfrac{3.7.13.37.39-10101}{505050-70707}\)
Help me
a) \(\dfrac{18.34-18.124}{-36.17+9.\left(-4\right).13}=\dfrac{18.\left(34-124\right)}{-36.\left(17+13\right)}=\dfrac{18.\left(-90\right)}{36.\left(-30\right)}=\dfrac{1.\left(-3\right)}{2.\cdot\left(-1\right)}=\dfrac{3}{2}\)
b) \(\dfrac{393939-10101}{505050-70707}=\dfrac{10101.39-10101}{10101.50-10101.7}=\dfrac{10101.\left(39-1\right)}{10101.\left(50-7\right)}=\dfrac{38}{43}\)
a) \(\dfrac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}=\dfrac{36.17+36.\left(-62\right)}{36.\left(-17\right)+35.\left(-13\right)}=\dfrac{36\left[17+\left(-62\right)\right]}{36\left[\left(-17\right)+\left(-13\right)\right]}=\dfrac{45}{20}=\dfrac{9}{4}\)
b) \(\dfrac{3.7.13.37.39-10101}{505050-70707}=\dfrac{10101.39-10101}{10101.50-10101.7}=\dfrac{10101\left(39-1\right)}{10101\left(50-7\right)}=\dfrac{38}{43}\)
Rút gọn phân số
\(\frac{2.3+4.6+14.21}{3.5+6.10+21.35}\) ; \(\frac{3.7.13.37.39-10101}{505050-70707}\) ; \(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
rút gọn:
a) \(\frac{-1997.1996+1}{\left(-1995\right).\left(-1997\right)+1996}\)b) \(\frac{3.7.13.37.39-10101}{505050-70707}\)c) \(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)rút gọn phân số:
1, -1997.1996+1 / (-1995).(-1997)+1996
2, 2.3+4.6+14.21 / 3.5+6.10+21.35
3, 3.7.13.37.39-10101 / 505050 - 70707
4, 18.34+(-18).124 / -36.17+9.(-52)
Rút gọn phân số:
a)\(\frac{2929-101}{2.1919+404}\)
b)\(\frac{-1997.1996+1}{-1995.\left(-1997\right)+1996}\)
c)\(\frac{2.3+4.6+14.21}{3.5+6.10+21.35}\)
d)\(\frac{3.7.13.37.39-10101}{505050-70707}\)
e)\(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
dễ quá đi. Nếu muốn mình giải hãy k trước đi
a) \(\frac{2929-101}{2.1919+404}\)\(=\frac{101.29-101}{2.1919+2.202}\)\(=\frac{101\left(29-1\right)}{2\left(1919+202\right)}\)\(=\frac{101.28}{2.2121}\)\(=\frac{2.101.7.2}{2.101.7.3}\)\(=\frac{2}{3}\)
b) \(\frac{-1997.1996+1}{-1995\left(-1997\right)+1996}\)\(=\frac{-1997.\left(1995+1\right)+1}{-1995\left(-1997\right)+1996}\)\(=\frac{-1997.1995-1997+1}{-1\left(-1997\right).1995+1996}\)\(=\frac{-1997.1995-1996}{1997.1995+1996}\)\(=\frac{-\left(1997.1995+1996\right)}{1997.1995+1996}\)\(=-1\)
c) \(\frac{2.3+4.6+14.21}{3.5+6.10+21.35}\)\(=\frac{2.3+4.2.3+2.7.3.7}{3.5+2.3.2.5+3.7.5.7}\)\(=\frac{2.3\left(1+4+7.7\right)}{3.5\left(1+2.2+7.7\right)}\)\(=\frac{2\left(1+4+49\right)}{5\left(1+4+49\right)}\)\(=\frac{2}{5}\)
d) \(\frac{3.7.13.37.39-10101}{505050-70707}\)\(=\frac{3.7.13.37.39-3.7.13.37}{2.3.5.5.7.13.37-3.7.7.13.37}\)\(=\frac{3.7.13.37\left(39-1\right)}{3.7.13.37\left(2.5.5-7\right)}\)\(=\frac{38}{43}\)
e) \(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)\(=\frac{18.2.17-18.2.62}{\left(-1\right).2.2.3.3.17+\left(-1\right)2.2.3.3.13}\)\(=\frac{18.2\left(17-62\right)}{\left(-1\right).2.2.3.3\left(17+13\right)}\)\(=\frac{\left(-1\right).2.2.3.3.45}{\left(-1\right).2.2.3.3.30}\)\(=\frac{45}{30}\)\(=\frac{3}{2}\)
a, \(\frac{29.101-101}{2.101.19+4.101}=\frac{101.\left(29-1\right)}{38.101+4.101}=\frac{101.28}{101.42}=\frac{28}{42}=\)\(\frac{2}{3}\)
b, \(\frac{-1997.1996+1}{-1995.\left(-1997\right)+1996}=\frac{-1997.\left(1995+1\right)+1}{1995.1997+1996}\)\(=\frac{-1997.1995+1997-1}{1995.1997+1996}=\frac{-1997.1995+1996}{1995.1997+1996}=-1\)
c,\(\frac{2.3+2\left(2.3\right)+7\left(2.3\right)}{3.5+2\left(3.5\right)+7\left(3.5\right)}=\frac{2.3\left(1+2+7\right)}{3.5\left(1+2+7\right)}=\frac{2.3}{3.5}=\frac{2}{5}\)
d,\(\frac{3.7.13.37.39-3.7.13.37}{2.3.5^2.7.13.37-3.7^2.13.37}=\frac{3.7.13.37.38}{3.7.13.37\left(2.5^2-7\right)}\)\(=\frac{3.7.13.37.38}{3.7.13.37.43}=\frac{38}{43}\)
e, \(\frac{18.34+18.\left(-124\right)}{9.\left(-4\right).17+9.\left(-52\right)}=\frac{18\left(-124+34\right)}{9.\left(-68\right)+9\left(-52\right)}\)\(=\frac{18\left(-90\right)}{9\left(-120\right)}=\frac{18.\left(-90\right)}{9.2\left(-60\right)}=\frac{18.\left(-90\right)}{18.\left(-60\right)}=\)\(\frac{-90}{-60}=\frac{3}{2}\)
rút gọn:
\(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
giải chi tiết nha
\(\dfrac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\) =\(\dfrac{18.34-18.124}{9.\left(-4\right).17+9.\left(-52\right)}=\dfrac{18.\left(34-124\right)}{9.\left(-68\right)+9.\left(-52\right)}\) =\(\dfrac{18.\left(-90\right)}{9.\left(-68-52\right)}=\dfrac{18.\left(-90\right)}{9.\left(-120\right)}=\dfrac{3}{2}\)
\(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}=\frac{18.34-18.124}{9.\left(-4\right)+17+9.\left(-52\right)}=\frac{18.\left(34-124\right)}{9.\left(17-52\right).\left(-4\right)}\)
\(\frac{18.\left(-90\right)}{9.\left(-35\right).\left(-4\right)}=\frac{18.\left(-90\right)}{9.140}=\frac{9.2.\left(-9\right).10}{9.7.2.10}=\frac{-9}{7}\)
a)\(\frac{-135}{540}\)
b)\(\frac{25.13}{26.35}\)
c)\(\frac{6.9-2.17}{63.3-119}\)
d)\(\frac{3.13-13.18}{15.40-80}\)
e)\(\frac{-5^3.40.4^4}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
f)\(\frac{2929-101}{2.1919+404}\)
g)\(\frac{-1997.1996+1}{\left(-1995\right).\left(-1997\right)+1996}\)
h)\(\frac{2.3+4.6+14.21}{3.5+6.10+21.35}\)
i)\(\frac{3.7.13.37.39-10101}{505050-70707}\)
k)\(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
rút gọn các biểu thức sau:
\(c=\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
nhớ làm đầy đủ, mik tk
\(C=\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}=\frac{18.\left(34-124\right)}{9.\left(-4.17-52\right)}=\frac{18.\left(-90\right)}{9.\left(-120\right)}=\frac{3}{2}\)
\(c=\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
\(=\frac{18.34+18.\left(-124\right)}{9.-3.17+9.\left(-52\right)}\)
\(=\frac{18.\left(34+\left(-124\right)\right)}{9.\left(-3+17\right).\left(52\right)}\)
tk ủng hộ mk nha!!!!!!!!!!
\(c=\frac{18.34=\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
= \(\frac{18.34+18.\left(-124\right)}{36.\left(-17\right)+9.\left(-52\right)}=\frac{18.\left(-124+34\right)}{9.4.\left(-17\right)+9.\left(-52\right)}\)\(=\frac{18.\left(-90\right)}{9.\left(-68\right)+9.\left(-52\right)}=\frac{18.\left(-90\right)}{9.\left[-68+\left(-52\right)\right]}\)
\(=\frac{18.\left(-90\right)}{9.\left(-120\right)}\)\(=\frac{2.\left(-9\right)}{1.\left(-12\right)}=-\frac{18}{12}=\frac{-3}{2}\)
Tìm x:
LƯU Ý: VD: A VÀ A/B CÓ NGHĨA LÀ HỖN SỐ NHÉ !
a) 2/3x-1/2x= 5/12
b) 5 và 8/17: x+(-4/17):x+3 và 1/7:17 và 1/3=4/11
Bài 2: Rút gọn phan số
a) \(\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
h)\(\frac{2.3+4.6+14.21}{3.5+6.10+21.35}\)
k)\(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
Câu cuối: \(\frac{3.7.13.37.39-10101}{505050-70707}\)
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