ta có

2 mũ 3 = 8

3 mũ 2=9

vì 8<9 nên 2 mũ 3 <3 mũ 2

Ta có:

202⁴⁰⁴ = 101⁴⁰⁴.2⁴⁰⁴ = 101²⁰².101²⁰².(2²)²⁰² = 101²⁰².101²⁰².4²⁰² 

404²⁰².33⁴ = 101²⁰².4²⁰².33⁴ < 101²⁰².101²⁰².4²⁰²

=> 202⁴⁰⁴ < 404²⁰².33⁴

\(404^{600};505^{450}\)

\(=404^{600}>505^{450}\)

\(\text{Mấy bạn k cho mình nhé !}\)

\(2^{50}=\left(2^5\right)^{10}=32^{10}\)

\(5^{20}=\left(5^2\right)^{10}=25^{10}\)

Suy ra: 2⁵⁰ > 5²⁰

b)

\(9^{200}=\left(9^2\right)^{100}=81^{100}\)

Suy ra: 99¹⁰⁰ > 81¹⁰⁰

\(5^{202}=\left(5^2\right)^{101}=25^{101}\)

\(2^{505}=\left(2^5\right)^{101}=32^{101}\)

Suy ra: 5²⁰² < 2⁵⁰⁵

404/505=4/5

8/10=4/5

=> 404/505=8/10

\(\frac{404}{505}=\frac{4.101}{5.101}=\frac{4}{5}\)

\(\frac{8}{10}=\frac{8:2}{10:2}=\frac{4}{5}\)

vì \(\frac{4}{5}=\frac{4}{5}\)

nên \(\frac{404}{505}=\frac{8}{10}\)

Ta có : \(\frac{404}{505}\)bỏ 2 con số 0 ở tử và mẫu thành \(\frac{44}{55}=\frac{44:11}{55:11}=\frac{4}{5}\)

\(\frac{8}{10}=\frac{4}{5}\)

Suy ra : \(\frac{404}{505}=\frac{8}{10}\)\(hoặc\) \(\frac{4}{5}=\frac{4}{5}\)

\(\left(\frac{505}{707}+\frac{222}{333}\right)\cdot x=\frac{404}{909}\)

 =>     \(\left(\frac{5}{7}+\frac{2}{3}\right)\cdot x=\frac{4}{9}\)

=>                     \(\frac{29}{21}\cdot x=\frac{4}{9}\)

=>                               \(x=\frac{4}{9}:\frac{29}{21}\)

=>                              \(x=\frac{28}{87}\)

TK mk nha!

( 505/707+ 222/333) . x = 404/ 909

29/21 . x = 4/9

x= 4/9 : 29/21

x= 4/9 . 21/29

x= 28/87

Vậy x= 28/87

28/87