Dễ

\(\frac{2}{5}+\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}-\frac{2}{5}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{57}{10}\)

\(\left(3x-3,7\right)=-\frac{57}{10}\div\frac{3}{5}\)

\(3x-3,7=-\frac{19}{2}\)

\(3x=-\frac{19}{2}+3,7\)

\(3x=-\frac{29}{5}\)

\(x=-\frac{29}{5}\div3\)

\(x=-\frac{29}{15}\)

Chúc bạn học tốt ^^

x : 2/5 + 3/5 . (3x - 3,7) = -53/10

x. 2/5 + 3/5. 3x - 3/5. 37/10 = -53/10

x . 5/2 + 9/5.x - 111/50 = -53/10

x. ( 5/2 + 9/5) = -53/10 + 111/50

x . 43/10 = -73/25

x = -73/25 : 43/10

x = -146/215

\(\frac{2}{5}+\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{53}{10}-\frac{2}{5}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=\frac{-53-4}{10}\)

\(\frac{3}{5}\times\left(3x-3,7\right)=-\frac{57}{10}\)

\(3x-3,7=-\frac{57}{10}\div\frac{3}{5}\)

\(3x-3,7=-\frac{57}{10}\times\frac{5}{3}\)

\(3x-3,7=-\frac{19}{2}\)

\(3x=-\frac{19}{2}+\frac{37}{10}\)

\(3x=\frac{-95+37}{10}\)

\(3x=-\frac{58}{10}\)

\(x=-\frac{29}{5}\div3\)

\(x=-\frac{29}{5}\times\frac{1}{3}\)

\(x=-\frac{29}{15}\)

Chúc bạn học tốt

Mà ban nè -29/5 ở mo ra rứa bạn

\(-\frac{29}{5}\) là rút gọn của \(-\frac{58}{10}\) đó bn

\(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)

\(\frac{3}{5}.\left(3x-3,7\right)=\frac{-57}{10}\)

\(\left(3x-3,7\right)=\frac{-19}{2}\)

\(3x=-5,8\)

\(x=\frac{-29}{15}\)

Vậy \(x=\frac{-29}{15}\)

Dễ quá mà bn ko biết làm à 

2/3x -3/2x=5/12

x(2/3-3/2)=5/12

x=5/12. (-5/6)

x=-25/72

a) \(x=-\frac{1}{2}\)

b) \(x=-\frac{29}{15}\)

c) \(x=\frac{5}{6}\)

**** cho mình nhé

a) -1/2

b) -29/15

c) 5/6

****

a) \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)

=> \(\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}-\frac{2}{5}\)

=> \(\frac{3}{5}.\left(3x-3,7\right)=\frac{-57}{10}\)

=> \(\left(3x-3,7\right)=\frac{-19}{5}\)

=>\(3x=\frac{-19}{5}+\frac{37}{10}\)

=>\(3x=\frac{-1}{10}\)

=>\(x=\frac{-1}{30}\)

Ko biết đúng hay sai!!?

a) \(\left(\dfrac{3}{5}+0,415-\dfrac{3}{200}\right).2\dfrac{2}{3}.0,25\)

\(=\left(\dfrac{3}{5}+\dfrac{83}{200}-\dfrac{3}{200}\right).\dfrac{8}{3}.\dfrac{1}{4}\)

\(=\left(\dfrac{3}{5}+\dfrac{2}{5}\right).\dfrac{2}{3}\)

\(=1.\dfrac{2}{3}=\dfrac{2}{3}\)

b) \(\dfrac{2}{5}+\dfrac{3}{5}.\left(3x-3,7\right)=\dfrac{-53}{10}\)

\(\dfrac{3}{5}.\left(3x-\dfrac{37}{10}\right)=\dfrac{-53}{10}-\dfrac{2}{5}=\dfrac{-57}{10}\)

\(3x-\dfrac{37}{10}=\dfrac{-57}{10}:\dfrac{3}{5}=\dfrac{-19}{2}\)

\(3x=\dfrac{-19}{2}+\dfrac{37}{10}=\dfrac{-29}{5}\)

\(x=\dfrac{-29}{5}:3=\dfrac{-29}{15}\)

a)

   \(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)

   \(\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}\)

    \(\frac{1}{3}:x=\frac{-1}{15}\)

     \(x=\frac{1}{3}:\frac{-1}{15}\)

    \(x=-5\)

b)

     \(\frac{10}{3x}+\frac{67}{4}=-13.25\)

      \(\frac{10}{3x}+\frac{67}{4}=\frac{-53}{4}\)

       \(\frac{10}{3x}=\frac{-53}{4}+\frac{67}{4}\)

       \(\frac{10}{3x}=\frac{7}{2}\)

      \(\Rightarrow10.2=7.3x\)

            \(20=21x\)

            \(x=\frac{20}{21}\)

c)

        x+30%x=-1.3

        x+0.3x=-1.3

        x (1+0.3) = -1.3

        x . 1.3 = -1.3

        x = -1.3 : 1.3

        x = 1

d)

          \(\left(\frac{14}{5x}-50\right):\frac{2}{3}=51\)

           \(\frac{14}{5x}-50=51.\frac{2}{3}\)

             \(\frac{14}{5x}-50=34\)

             \(\frac{14}{5x}=34+50\)

              \(\frac{14}{5x}=84\)

               \(84.5x=14\)

              420x = 14

                   \(x=\frac{1}{30}\)

a, \(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)

=> \(\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}\)

=>\(\frac{1}{3}:x=\frac{-1}{15}\)

=> \(x=\frac{1}{3}:\frac{-1}{15}\)

=> \(x=\frac{-1}{5}\)

mình sai chỗ kết quả cuối bằng -5 nhé