a)Đặt \(A=\dfrac{6}{1.4}+\dfrac{6}{4.7}+\dfrac{6}{7.10}+...+\dfrac{6}{97.100}\)

\(3a=3-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{3}{7}+\dfrac{3}{7}-\dfrac{3}{10}+...+\dfrac{3}{97}-\dfrac{3}{100}\)

\(=3-\dfrac{3}{100}\)

\(=\dfrac{297}{100}\)

b)Đặt \(B=\dfrac{4}{1.3}+\dfrac{16}{3.5}+\dfrac{36}{5.7}+...+\dfrac{9604}{97.99}\)

\(=2b=\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{97.99}\)

\(2b=2-\dfrac{2}{3}+\dfrac{2}{3}-\dfrac{2}{5}+\dfrac{2}{5}-\dfrac{2}{7}+...+\dfrac{2}{97}-\dfrac{2}{99}\)

\(2b=2-\dfrac{2}{99}=\dfrac{198}{99}-\dfrac{2}{99}=\dfrac{196}{99}\)

c) Tương tự! Bạn tự làm nhé!

Đặt \(A=1.2+2.3+3.4+...+19.20\)

Ta có: \(A=1.2+2.3+3.4+...+19.20\)

        \(3A=1.2.3+2.3.3+3.4.3+...+19.20.3\)

        \(3A=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-1\right)+...+19.20.\left(21-1\right)\)

        \(3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+19.20.21-18.19.20\)

        \(3A=19.20.21\)

           \(A=19.20.7\)

           \(A=2660\)

\(1\cdot2+2\cdot3+...+19\cdot20=\frac{1\cdot2\cdot\left(3-0\right)+2\cdot3\cdot\left(4-1\right)+...+19\cdot20\cdot\left(21-17\right)}{3}\)

   \(=\frac{1\cdot2\cdot3+2\cdot3\cdot4-1\cdot2\cdot3+...+19\cdot20\cdot21-18\cdot19\cdot20}{3}\)\(=\frac{19\cdot20\cdot21}{3}=2660\)

của bạn Tạ Đức Hoàng Anh là đúng đấy

Ta có:  1/1.2 = 1- 1/2 

           1/3.4 = 1/3 - 1/4 

          ...............

             1/19.20 = 1/19 - 1/20 

Cộng vế với vế ta đc: 

    A = 1- 1/20 = 19/20   

\(A=\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{17.18}+\frac{1}{19.20}\)

\(A=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{17}-\frac{1}{18}+\frac{1}{19}-\frac{1}{20}\)

\(A=\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{17}+\frac{1}{19}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+..+\frac{1}{18}+\frac{1}{20}\right)\)

\(A=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{17}+\frac{1}{18}+\frac{1}{19}+\frac{1}{20}\right)-2\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{18}+\frac{1}{20}\right)\)

\(A=\left(1+\frac{1}{2}+...+\frac{1}{20}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{9}+\frac{1}{10}\right)\)

\(A=\frac{1}{11}+\frac{1}{12}+\frac{1}{13}+...+\frac{1}{19}+\frac{1}{20}\)

\(\frac{A}{B}=1\)

\(A=\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+...+\frac{1}{19.20}\)

\(\Rightarrow A=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{19}-\frac{1}{20}\)

\(\Rightarrow A=\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{19}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{20}\right)\)

\(\Rightarrow A=\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{20}\right)-2\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{20}\right)\)

\(\Rightarrow A=\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{20}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{10}\right)\)

\(\Rightarrow A=\frac{1}{11}+\frac{1}{12}+\frac{1}{13}+...+\frac{1}{20}=B\)

\(\Rightarrow\frac{A}{B}=1\)

D=1.2+3.4+4.5+...+19.20

3D=1.2.(3-0)+2.3.(4-1)+4.5(6-3)+...+19.20.(21-18)

3D=1.2.3-0.1.2+2.3.4-1.2.3+4.5.6-3.4.5+...+19.20.21-18.19.20

3D=(1.2.3+2.3.4+3.4.5+...+19.20.21)-(0.1.2+1.2.3+2.3.4+...+18.19.20)

3D=19.20.21

3D=7890

D=2660

 Tính tổng : A=1.2+2.3+3.4+..+19.20 

               3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ..... + 19.20.21

               3A = 19.20.21

                A = \(\frac{19.20.21}{3}=3990\)

Tính tổng : A=1.2+2.3+3.4+..+19.20

3a=1.2.3-1.2.3.+2.3.4-2.3.4+......+19.20.21

3a=19.20.21

a=19.20.21:3=3990

L-iek giùm tôi vs bn oi

2660 bạn nhé

\(M=1\cdot2+2\cdot3+3\cdot4+...+19\cdot20=\)

\(3\times M=1\cdot2\cdot3+2\cdot3\cdot3+....+19\cdot20\cdot3=\)

\(3\times M=1\cdot2\cdot3+2\cdot3\cdot\left(4-1\right)+....+19\cdot20\cdot\left(21-18\right)=\)

\(3\times M=1\cdot2\cdot3+2\cdot3\cdot4+...+19\cdot20\cdot21-1\cdot2\cdot3-...-18\cdot19\cdot20=\)

\(3\times M=19\cdot20\cdot21\)

\(M=\frac{19\cdot20\cdot21}{3}\)

\(M=2660\)

  M = 1.2+2.3+3.4+...+19.20

3M= 1.2.3+2.3.3+3.4.3+...+19.20.3

3M=1.2(3-0)+2.3(4-1)+3.4(5-2)+...+19.20(21-18)

3M=0.1.2-1.2.3+1.2.3-2.3.4+2.3.4-3.4.5+...+18.19.20-19.20.21

3M=19.20.21

3M=7980

M=2660