Câu b:

\(\frac{21}{8}:\frac{5}{6}+\frac{1}{2}:\frac{5}{6}\)

= \(\frac{63}{20}+\frac{3}{5}\)

= \(\frac{15}{4}\)

\(\left(\frac{21}{8}+\frac{1}{2}\right):\frac{5}{6}\)

\(\frac{25}{8}:\frac{5}{6}\)

\(\frac{25}{8}.\frac{6}{5}\)

\(\frac{30}{8}\)

\(1\)) \(70:\frac{4x+720}{x}=\frac{1}{2}\)

\(\Leftrightarrow\frac{4x+720}{x}=70:\frac{1}{2}\)

\(\Leftrightarrow\frac{4x+720}{x}=140\)

\(\Leftrightarrow\left(4x+720\right):x=140\)

\(\Leftrightarrow4x+720=140.x\)

\(\Leftrightarrow4x-140x=-720\)

\(\Leftrightarrow x.\left(-136\right)=-720\)

\(\Leftrightarrow x=-720:\left(-136\right)\)

\(\Leftrightarrow x=\frac{90}{17}\)

\(2\)) Mình đang nghĩ

Cách làm 

Bài 1:     25 + 3(x - 8) = 106

                      3(x - 8) = 106 - 25

                      3(x - 8) = 81

                        (x - 8) = 81 : 3

                        (x - 8) = 27

                                x = 27 + 8

                                x = 25

Bài 2:       720 : [41 - (2x - 5)] = 2³ . 5

                720 : [41 - (2x - 5)] = 8 . 5

                720 : [41 - (2x - 5)] = 40

                         [41 - (2x - 5)] = 720 : 40

                         [41 - (2x - 5)] = 18

                                  (2x - 5) = 41 - 18

                                  (2x - 5) = 23

                                          2x = 23 + 5

                                          2x = 28

                                            x = 28 : 2

                                            x = 14

a, \(3^2\left(x+14\right)-5^2=5.4\)

\(\Rightarrow9\left(x+14\right)-25=20\)

\(\Rightarrow9x+126=20+25\)

\(\Rightarrow9x+126=45\)

\(\Rightarrow9x=45-126\)

\(\Rightarrow9x=-81\Rightarrow x=-9\)

Vậy x = 9 

a,\(3^2\left(x+14\right)-5^2=5.4\)

\(\Rightarrow9\left(x-14\right)-25=20\)

\(\Rightarrow9\left(x-14\right)=20+25=45\)

\(\Rightarrow x-14=45:9=5\)

\(\Rightarrow x=5+14\)

\(\Rightarrow x=19\)

Vậy x = 19

b,\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)

\(720:\left[41-2x+5\right]=40\)

\(\Rightarrow41+5-2x=720:40\)

\(\Rightarrow46-2x=18\)

\(\Rightarrow2x=46-18=28\)

\(\Rightarrow x=28:2\)

\(\Rightarrow x=14\)

Vậy x = 14

~Study well~

b, \(720\div\left[41-\left(2x-5\right)\right]=2^3.5\)

\(\Rightarrow720\div\left[41-\left(2x-5\right)\right]=8.5\)

\(\Rightarrow720\div\left[41-\left(2x-5\right)\right]=40\)

\(\Rightarrow41-\left(2x-5\right)=\frac{720}{40}\)

\(\Rightarrow41-\left(2x-5\right)=18\)

\(\Rightarrow2x-5=41-18\)

\(\Rightarrow2x-5=23\)

\(\Rightarrow2x=23+5\)

\(\Rightarrow2x=28\Rightarrow x=\frac{28}{2}=14\)

Vậy x = 14 

\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)

\(720:\left[41-\left(2x-5\right)\right]=40\)

\(41-\left(2x-5\right)=720:20\)

\(41-\left(2x-5\right)=18\)

\(2x-5=41-18\)

\(2x=23+5\)

\(x=28:2=14\)

\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)

\(720:\left[41-\left(2x-5\right)\right]=8.5\)

\(720:\left[41-\left(2x-5\right)\right]=40\)

\(41-\left(2x-5\right)=720:40\)

\(41- \left(2x-5\right)=18\)

\(2x-5=41-18\)

\(2x-5=23\)

\(2x=23+5\)

\(2x=28\)

\(x=28:2\)

\(\Rightarrow x=14\)

kết quả =18 và 14

18 vaf14 

\(720:\left[41-\left(2x-5\right)\right]=2^3.5\)

\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=40\)

\(\Leftrightarrow41-\left(2x-5\right)=720:40\)

\(\Leftrightarrow41-\left(2x-5\right)=18\)

\(\Leftrightarrow2x-5=41-18\)

\(\Leftrightarrow2x-5=23\)

\(\Leftrightarrow2x=28\)

\(\Leftrightarrow x=14\)

Ta có :\(720:\left[41-\left(2X-5\right)\right]=2^3\cdot5\)

\(\Leftrightarrow41-\left(2X-5\right)=18\)

\(\Leftrightarrow2X-5=23\)

\(\Leftrightarrow2X=28\)

\(\Leftrightarrow X=14\)(TMĐK)

Vậy X= 14 là giá trụ cần tìm.

1/2 . 1/3 . 1/4 . 1/5 . 1/6 . ( x - 1,010 ) = 1/360 - 1/720

1/2 . 1/3 . 1/4 . 1/5 . 1/6 . ( x - 1,010) = 1/720

( x - 1,010 ) . 1/2 . 1/3 . 1/4 . 1/5 . 1/6 = 1/720

( x - 1,010 ) . 1/720 = 1/720

x - 1,010 = 1/720 : 1/720

x - 1,010 = 1

          x  = 1 + 1,010

          x  = 2,01

1) Tính : 

a) \(\left(2008.2009.2010.2011\right).\left(1+\frac{1}{2}:\frac{2}{3}-\frac{4}{3}\right)\)

\(=\left(2008.2009.2010.2011\right).\left(1+\frac{1}{3}-\frac{4}{3}\right)\)

\(=\left(2008.2009.2010.2011\right).\left(\frac{4}{3}-\frac{4}{3}\right)\)

\(=\left(2008.2009.2010.2011\right).0\)

\(=0\)

2) Tìm x 

a) \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x.\left(x+1\right)}=\frac{2011}{2013}\)

\(\Rightarrow2.\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{x.\left(x+1\right)}\right)=\frac{2011}{2013}\)

\(\Rightarrow2.\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x.\left(x+1\right)}\right)=\frac{2011}{2013}\)

\(\Rightarrow2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{2011}{2013}\)

\(\Rightarrow2.\left(\frac{1}{2}-\frac{1}{x+1}\right)=\frac{2011}{2013}\)

\(\Rightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{2011}{2013}:2\)

\(\Rightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{2011}{4026}\)

\(\Rightarrow\frac{1}{x+1}=\frac{1}{2}-\frac{2011}{4026}\)

\(\Rightarrow\frac{1}{x+1}=\frac{1}{2013}\)

\(\Rightarrow x+1=2013\)

\(\Rightarrow x=2012\)

b) \(\frac{1}{2}.\frac{1}{3}.\frac{1}{4}.\frac{1}{5}.\frac{1}{6}.\left(x-1,010\right)=\frac{1}{360}-\frac{1}{720}\)

\(\Rightarrow\frac{1}{2.3.4.5.6}.\left(x-1,01\right)=\frac{1}{720}\)

\(\Rightarrow\frac{1}{720}.\left(x-1,01\right)=\frac{1}{720}\)

\(\Rightarrow x-1,01=\frac{1}{720}:\frac{1}{720}\)

\(\Rightarrow x-1,01=1\)

\(\Rightarrow x=1+1,01\)

\(\Rightarrow x=2,01\)