Tìm x:
5x . 7 . 5x+1 = 875
Những câu hỏi liên quan
Tìm X
5x+1+ 6,5x+1 =875
(5+6,5)x = 875-1-1
11,5x = 873
x = 873:11,5
x = \(\frac{1746}{23}\)
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Tìm x biết
(5x-1)2-(5x-4)(5x+4)=7
`(5x-1)^2-(5x-4)(5x+4)=7`
`\Leftrightarrow 25x^2-10x+1-25x^2+16-7=0`
`\Leftrightarrow -10x+10=0`
`\Leftrightarrow x=1`
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1 TÌM x,biết
a,2^x-1+2^x+1=20
b,3^5x+1-5.3^5x-1=594
c,5^x+1+6.5^x+1=875
2Tìm x,y thuộc N
a,2^x+1.5^y=20^y
b,10^x : 5^y=20^y
Giups mik với nha!!!
a) 2x - 1 + 2x + 1 = 20
=> 2x : 2 + 2x . 2 = 20
=> 2x . 1/2 + 2x . 2 = 20
=> 2x.(1/2 + 2) = 20
=> 2x . 5/2 = 20
=> 2x = 20 : 5/2
=> 2x = 8
=> 2x = 23
=> x = 3
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Bài 1: Tìm x, biết .
a. 5x( 12x + 7) - 3x ( 20x - 5) = -100
b. 5x( 2x - 7) + 2x ( 8 - 5x) = 5
a)\(60x^2+35x-60x^2+15x=100\)
35x+15x=100
50x=100 =>x=2
b)\(10x^2-35x+16x-10x^2=5\)
-35x+16x=5
-19x=5 =>x=-5/19
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a)60x2+35x−60x2+15x=10060x2+35x−60x2+15x=100
35x+15x=100
50x=100
=>x=2
b)10x2−35x+16x−10x2=510x2−35x+16x−10x2=5
-35x+16x=5
-19x=5
=>x=-5/19
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Tìm x
(5x-1)2 _ (5x-4)(5x+4)= 7
\(\left(5x-1\right)^2-\left(5x-4\right)\left(5x+4\right)=7^{ }\)
\(\Leftrightarrow25x^2-10x+1-25x^2+16=7\)
\(\Leftrightarrow17-10x=7\)
\(\Leftrightarrow10-10x=0\)
\(\Rightarrow x=1\)
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Bài 2 : Tìm x , biết
a) ( 3x -1 ) (2x+7) - ( x +1) (6x-5 ) = 16
b) ( 10x +9 )x - ( 5x -1 ) (2x+3 )= 8
c) ( 3x - 5 ) ( 7- 5x ) + ( 5x +2 )( 3x-2 ) -2 = 0
d) x(x + 1) ( x+6 ) - x3 = 5x
1. Tìm x
a. (5x-7)(x-9)-(-x+3)(-5x+2)= 2x(x-4)-(x-1)(2x+3)
b. (x-3)(-x+10)+(x-8)(x+3)= (5x^2-1)(x+3)-5x^3-15x^2
ta có
a. (5x-7)(x-9)-(-x+3)(-5x+2)= 2x(x-4)-(x-1)(2x+3)
\(\Leftrightarrow5x^2-52x+63-\left(5x^2-17x+6\right)=2x^2-8x-\left(2x^2+x-3\right)\)
\(\Leftrightarrow-35x+57=-9x+3\Leftrightarrow26x=54\Leftrightarrow x=\frac{27}{13}\)
b. (x-3)(-x+10)+(x-8)(x+3)= (5x^2-1)(x+3)-5x^3-15x^2
\(\Leftrightarrow-x^2+13x-30+x^2-5x-24=5x^3+15x^2-x-3-5x^3-15x^2\)
\(\Leftrightarrow8x-54=-x-3\Leftrightarrow9x=51\Leftrightarrow x=\frac{17}{3}\)
Tìm x biết:
a) 5x.(x-1)-(x+2).(5x-7)=6
b) (x+2)2-(x2-4)=0
`a)5x(x-1)-(x+2)(5x-7)=6`
`<=>5x^2-5x-(5x^2-7x+10x-14)=6`
`<=>5x^2-5x-(5x^2+3x-14)=6`
`<=>-8x+14=6`
`<=>8x=8<=>x=1`
Vậy `x=1`
`b)(x+2)^2-(x^2-4)=0`
`<=>x^2+4x+4-x^2+4=0`
`<=>4x+8=0`
`<=>4x=-8`
`<=>x=-2`
Vậy `x=-2`
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a)5x.(x-1)-(x+2).(5x-7)=6
<=> 5x2-5x-(5x2-7x+10x-14)=6
<=> 5x2-5x-5x2+7x-10x+14=6
<=> -8x+14=6
<=> -8x=-8 => x=1
Vậy x=1
b) (x+2)2-(x2-4)=0
<=> (x+2)2-(x2-22)=0 <=> (x+2)2-(x-2)(x+2)=0
<=> (x+2)[(x+2)-(x-2)]=0
<=> (x+2)(x+2-x+2)=0
<=> (x+2).4=0
=> x+2=0
=> x=-2
Vậy x=-2
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3x+2\5x+7=3x-1/5x+1
Tìm x
\(\frac{3x+2}{5x+7}=\frac{5x-1}{5x+1}\) tìm x
\(\frac{3x+2}{5x+7}=\frac{5x-1}{5x+1}\)
\(\Leftrightarrow\left(3x+2\right)\left(5x+1\right)=\left(5x-1\right)\left(5x+7\right)\)
\(\Leftrightarrow15x^2+3x+10x+2=25x^2+35x-5x-7\)
\(\Leftrightarrow25x^2+30x-7-15x^2-13x-2=0\)
\(\Leftrightarrow10x^2+17x-9=0\)
.............
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