Bằng 0 nha

2x + 3x - 5x = ?

Trả lời

2x + 3x - 5x 

= 5x - 5x 

= 0

Vậy 2x |+ 3x - 5x = 0

Study well 

2x+3x- 5x=x *(2+3-5)=x*0

= 0

  study well

=1 bạn ạ vì x chỉ có thể =3 thôi nên 3x=9-2=7:7=1

 = 0; 1 va 3 nhe ban

 = 0; 1 va 3 nhe ban

 = 0; 1 va 3 nhe ban

CÓ \(7⋮2x-3\)

\(\Rightarrow2x-3\inƯ\left(7\right)=\left\{1;-1;7;-7\right\}\)

Ta có bảng sau :

Vậy để \(7⋮2x-3\)

\(\Rightarrow x\in\left\{2;1;5;-2\right\}\)

10/12=5/6

X -  \(\frac{5}{12}\) =    \(\frac{2}{3}\) -      \(\frac{1}{4}\) 

X -  \(\frac{5}{12}\)  =   \(\frac{5}{12}\) 

X                 =      \(\frac{5}{12}\)  +    \(\frac{5}{12}\)

X                 =         \(\frac{10}{12}\)    =  \(\frac{5}{6}\)     TK MÌNH  NHÉ BẠN

ban phai lam day du thi to moi biet duoc chu

\(5x^3\)\(-x^3+2x^3=6x^3\)

5x³-x³+2x³=6x³

\(5x^3-x^3+2x^3=5x^3-1x^3+2x^3=\left(5-1+2\right)x^3=6x^3\)

k mk nha

\(\left(3x-1\right)\left(x^2+2\right)=\left(3x-1\right)\left(7x-10\right)\)

\(\Leftrightarrow\left(3x-1\right)\left(x^2+2\right)-\left(3x-1\right)\left(7x-10\right)=0\)

\(\Leftrightarrow\left(3x-1\right)\left(x^2+2-7x+10\right)=0\)

\(\Leftrightarrow\left(3x-1\right)\left(x^2-7x+12\right)=0\)

\(\Leftrightarrow\left(3x-1\right)\left(x^2-3x-4x+12\right)=0\)

\(\Leftrightarrow\left(3x-1\right)\left[x\left(x-3\right)-4\left(x-3\right)\right]=0\)

\(\Leftrightarrow\left(3x-1\right)\left(x-3\right)\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}3x-1=0\\x-3=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=3\\x=4\end{matrix}\right.\)

Vậy tập nghiệm của ohuowng trình là \(S=\left\{\dfrac{1}{3};3;4\right\}\)

\(1\frac{1}{2}\)\(+1\frac{1}{3}\)\(=\frac{3}{2}\)\(+\frac{4}{3}\)\(=\frac{9+8}{6}\)\(=\frac{17}{6}\)

~ HOK TỐT ~