abd=m(2)," role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-block; float:none; font-size:15.82px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; overflow-wrap:normal; padding:1px 0px; position:relative; white-space:nowrap; word-break:break-word; word-spacing:normal" class="MathJax_CHTML mjx-chtml">abd=m(2), Ta cần chứng minh rằng bd=ab′m=b.ad=ba′" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-block; float:none; font-size:15.82px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; overflow-wrap:normal; padding:1px 0px; position:relative; white-space:nowrap; word-break:break-word; word-spacing:normal" class="MathJax_CHTML mjx-chtml">bd=ab′m=b.ad=ba′ Do đó ta chọn abd=[a,b]," role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-block; float:none; font-size:15.82px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; overflow-wrap:normal; padding:1px 0px; position:relative; white-space:nowrap; word-break:break-word; word-spacing:normal" class="MathJax_CHTML mjx-chtml">abd=[a,b], Tức là ab=1535⇒a15=b35" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-block; float:none; font-size:15.82px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; overflow-wrap:normal; padding:1px 0px; position:relative; white-space:nowrap; word-break:break-word; word-spacing:normal" class="MathJax_CHTML mjx-chtml">ab=1535⇒a15=b35

a15=b35=k" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-block; float:none; font-size:15.82px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; overflow-wrap:normal; padding:1px 0px; position:relative; white-space:nowrap; word-break:break-word; word-spacing:normal" class="MathJax_CHTML mjx-chtml">a15=b35=k ab=3991" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-block; float:none; font-size:15.82px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; overflow-wrap:normal; padding:1px 0px; position:relative; white-space:nowrap; word-break:break-word; word-spacing:normal" class="MathJax_CHTML mjx-chtml">a=39,b=91⇒ab=3991

(a,b)*[a,b]=a*b

a,60 phần 75                                                                                                                                                                                b, 90 phần 150                                                                                                                                                                            c, 39 phan 91 

mới nhìn câu hỏi thôi là thấy đau đầu rồi đó

a)\(\frac{a}{b}=\frac{36}{45}=\frac{4}{5}\)

\(=>\frac{a}{b}=\frac{4k}{5k}\)

\(=>ƯCLN\left(a,b\right)=ƯCLN\left(4k,5k\right)=4.5.k=20k=300\)

\(=>k=\frac{300}{20}=15\)

\(=>a=4.15=60;b=5.15=75\)

\(=>\) \(\frac{a}{b}=\frac{60}{75}\)

b)\(\frac{a}{b}=\frac{21}{35}=\frac{3}{5}\)

\(=>\frac{a}{b}=\frac{3.30}{5.30}=\frac{90}{150}\)

c)\(\frac{a}{b}=\frac{15}{35}=\frac{3}{7}\)

\(=>\frac{a}{3}=\frac{b}{7}\)hay\(\frac{a}{3}.\frac{b}{7}=\left(\frac{a}{3}\right)^2=\frac{ab}{21}=\frac{3549}{21}=169\)

\(\frac{a}{3}=13;-13=>a=39;-39,b=91;-91\)

\(=>\frac{a}{b}=\frac{39}{91}hay\frac{a}{b}=\frac{-39}{-91}\)

kết bạn với mình nha

a) \(\frac{a}{b}=\frac{36}{45}=\frac{4}{5}\)

\(\RightarrowƯCLN=\frac{a}{4}\).

Mà BCNN = \(\frac{ab}{ƯCLN}\)

\(\Rightarrow300=\frac{ab}{\left(\frac{a}{4}\right)}\) 

Suy ra b = 75

Suy ra a = 60 

b với c tương tự nha bn!!!

Theo bài ra , ta có : 

2135 =35 =ab mà UCLN(a,b) = 30 

=) ab =35 =3×305×30 =90150 

Vậy phân số mới là 90150  

Ta có: a/b=36/45=4/5 Suy ra a=4k, b=5k

Suy ra BCNN(a;b)=BCNN(4k;5k)=2².5.k=20k

Mà BCNN(a;b)=300

Suy ra 20k=300

Suy ra k=300:20=15 Suy ra a=60,b=75

b) Ta có 21/35=3/5

ta có 3/5 là phân số tối giản bằng phân số a/b suy ra phân số a/b đã chia cho ƯCLN (a;b)=30 để được 1 phân số tối giản là 3/5

Suy ra a=3.30=90, b=5.30=160

c) Ta có BCNN(a;b).ƯCLN (a,b)=ab=3549

Ta có: a/b=15/35=3/7 suy ra a=3k, b=7k

Suy ra a.b=3k.7k=3549

Suy ra 21.k²=3549

Suy ra k²=169 Suy ra k=13

b,90/150

A,60/75

B,90/150

C, minh ko hieu... xl nhe