\(\left(\frac{-5}{3}\right)^3< x< \frac{-24}{35}.\frac{-5}{6}\)
Giup minh tim x
Tìm số nguyên x biết: (\(\left(\frac{-5}{3}\right)^3
Tìm số nguyên x biết : \(\left(\frac{-5}{3}\right)^3
\(\left(-\frac{5}{3}\right)^3=\left(-\frac{5}{3}\right).\left(-\frac{5}{3}\right).\left(-\frac{5}{3}\right)=-\frac{125}{27}\)
Đáp số: \(-\frac{125}{27}\)
Chúc bạn học tốt nha Linh Trần Thị Thùy
\(\left[-\frac{2}{5}x^3.\left(2x-1\right)^m+\frac{2}{5}x^{m+3}\right]:\left(-\frac{2}{5}x^3\right)\)
tim x nguyen
giai ra giup minh voi
\(\left[\frac{-2}{5}x^3.\left(2x-1\right)^m+\frac{2}{5}x^{m+3}\right]:\left(\frac{-2}{5}x^3\right)\)
\(=\left[\frac{2}{5}x^3\left(2x+1\right)^m+\frac{2}{5}x^3.\left(\frac{2}{5}\right)^m\right]:\left(\frac{-2}{5}x^3\right)\)
\(=\left\{\frac{2}{5}x^3.\left[\left(2x+1\right)^m+\left(\frac{2}{5}\right)^m\right]\right\}:\left(\frac{-2}{5}x^3\right)\)
\(=\left\{\frac{2}{5}x^3.\left[2x+\frac{7}{5}\right]^m\right\}:\frac{-2}{5}x^3\)
\(=-\left(2x+\frac{7}{5}\right)^m\)
đến đây thì mình chịu
\(\left(\frac{-5}{3}\right)^3< x< \frac{-24}{35}.\frac{-5}{6}\)
\(Tính:\left(\frac{-5}{3}\right)^3< x< \frac{-24}{35}.\frac{-5}{6}\)
Tìm số nguyên x , biết:\(\left(\frac{-5}{3}\right)^3< x< \frac{-24}{35}\cdot\frac{-5}{6}\)
Tìm x:
\(\left(\frac{-5}{3}\right)^2< x< \frac{-24}{35}.\frac{-5}{6}\)
Ta có:
\(\left(\frac{-5}{3}\right)^2=\frac{25}{15}=\frac{5}{3}\)
\(\frac{-24}{35}\cdot\frac{-5}{6}=\frac{120}{210}=\frac{4}{7}\)
Quy đồng \(\frac{5}{3}\)và \(\frac{4}{7}\),ta được:
\(\frac{35}{21}\)và \(\frac{12}{21}\)
Vì 35 > 12 nên \(\frac{5}{3}>\frac{4}{7}\)
mà x lại lớn hơn \(\frac{5}{3}\)và bé hơn \(\frac{4}{7}\)
\(\Rightarrow\)Không tồn tại x
Tìm x
a) \(\left(\frac{-5}{3}\right)< x< \frac{-24}{35}.\left(\frac{-5}{6}\right)\)
b) \(\left(7x-11\right)^3=\left(-3\right)^2.15+208\)
Tìm x biết \(\left(-\frac{5}{3}\right)^2< x< -\frac{24}{35}\cdot-\frac{5}{6}\)