a) \(\frac{999}{10000}=\frac{99,9}{1000}>\frac{99}{100}\)

=> kết luận

b)  \(1-\frac{97}{99}=\frac{2}{99}>1-\frac{98}{100}=\frac{2}{100}\)

\(\Rightarrow\frac{97}{99}< \frac{98}{100}\)

=> kết luận

12/11 lớn hơn vì 12/11 lớn hơn 1 còn 2005/2006 bé hơn 1

Ta có A=1/10²⁰⁰⁵(-7-15/10)=1/10²⁰⁰⁵.(-8,5)   (1)                                                                                                 B=1/10²⁰⁰⁵(-15-7/10)=1/10²⁰⁰⁵.(-15,7)        (2)                                                                                                   (1)(2)-> A>B

C=1/2.(3/60.63+....+3/117.120)+1/1003

C=1/2.(1/60-1/63+....+1/117-1/120)+1/1003

....còn lại tự làm nha, bài còn lại cũng tương tự

Bạn ơi còn \(\frac{5}{2006}\)xử lý sao

Ta có:

\(C=\dfrac{2}{60.63}+\dfrac{2}{63.66}+...+\dfrac{2}{117.120}+\dfrac{2}{2006}\)

\(C=2\left(\dfrac{1}{60.63}+\dfrac{1}{63.66}+...+\dfrac{1}{117.120}\right)+\dfrac{2}{2006}\)

\(C=2.\dfrac{1}{3}\left(\dfrac{3}{60.63}+\dfrac{3}{63.66}+...+\dfrac{3}{117.120}\right)+\dfrac{2}{2006}\)

\(C=\dfrac{2}{3}\left(\dfrac{1}{60}-\dfrac{1}{63}+\dfrac{1}{63}-\dfrac{1}{66}+...+\dfrac{1}{117}-\dfrac{1}{120}\right)+\dfrac{2}{2006}\)

\(C=\dfrac{2}{3}\left(\dfrac{1}{60}-\dfrac{1}{120}\right)+\dfrac{2}{2006}\)

\(C=\dfrac{2}{3}.\dfrac{1}{120}+\dfrac{2}{2006}\)

\(C=\dfrac{1}{180}+\dfrac{2}{2006}\)

Ta lại có:

\(D=\dfrac{5}{40.44}+\dfrac{5}{44.48}+...+\dfrac{5}{76.80}+\dfrac{5}{2006}\)

\(D=5\left(\dfrac{1}{40.44}+\dfrac{1}{44.48}+...+\dfrac{1}{76.80}\right)+\dfrac{5}{2006}\)

\(D=5.\dfrac{1}{4}\left(\dfrac{4}{40.44}+\dfrac{4}{44.48}+...+\dfrac{4}{76.80}\right)+\dfrac{5}{2006}\)

\(D=\dfrac{5}{4}\left(\dfrac{1}{40}-\dfrac{1}{44}+\dfrac{1}{44}-\dfrac{1}{48}+...+\dfrac{1}{76}-\dfrac{1}{80}\right)+\dfrac{5}{2006}\)

\(D=\dfrac{5}{4}\left(\dfrac{1}{40}-\dfrac{1}{80}\right)+\dfrac{5}{2006}\)

\(D=\dfrac{5}{4}.\dfrac{1}{80}+\dfrac{5}{2006}\)

\(D=\dfrac{1}{64}+\dfrac{5}{2006}\)

Vì \(\dfrac{1}{180}< \dfrac{1}{64}\)

\(\dfrac{2}{2006}< \dfrac{5}{2006}\)

\(\Rightarrow\dfrac{1}{180}+\dfrac{2}{2006}< \dfrac{1}{64}+\dfrac{5}{2006}\)

\(\Rightarrow C< D\)

dở ẹt nhu cu net ma ko biet lamb tao hoc lop mau giao tao cung biet tra loi dung la ngu

Ta có:    1-2004/2005=1/2005

              1-2005/2006=1/2006

   Mà 1/2005>1/2006                  (sử dụng phần bù)

=>2004/2005<2005/2006

2004/2005 < 2005/2006

ko tk nha

Vì 2003 / 2004 < 1 và 1 < 2006 / 2005 => 2003 / 2004 < 2006 / 2005

Trả lời:

Vì \(\frac{2003}{2004}< 1;1< \frac{2006}{2005}\)

\(\Rightarrow\frac{2003}{2004}< \frac{2006}{2005}\)

Vậy \(\frac{2003}{2004}< \frac{2006}{2005}\)

\(A=\frac{100^{2007}+1}{100^{2008}+1}\Rightarrow100.A=\frac{100^{2008}+100}{100^{2008}+1}=\frac{100^{2008}+1+99}{100^{2008}+1}=1+\frac{99}{100^{2008}+1}\)

\(B=\frac{100^{2006}+1}{100^{2007}+1}\Rightarrow100.B=\frac{100^{2007}+100}{100^{2007}+1}=\frac{100^{2007}+1+99}{100^{2007}+1}=1+\frac{99}{100^{2007}+1}\)

Vì \(\frac{99}{100^{2007}+1}>\frac{99}{100^{2008}+1};1=1\Rightarrow1+\frac{99}{100^{2007}+1}>1+\frac{99}{100^{2008}+1}\)hay \(A>B\)

Vậy \(A>B\)

Nghỉ hè rồi