Ta có:S=23+43+63+…+203

=>S=23+43+63+…+203+3+3+3+…+3-3-3-3-…-3

=>S=(23+3)+(43+3)+(63+3)+…+(203+3)-(3+3+3+…+3)

=>S=26+46+66+…+206-(3+3+3+…+3)

Từ 26 đến 206 có:

                  (206-26):20+1=10(số)

=>S=26+46+66+…+206-3.10

=>S=2.(13+23+33+…+103)-30

mà 13+23+33+…+103=3025

=>S=2.3025-30

=>S=6050-30

=>S=6020

Vậy S=6020.

ta co : 13 + 23 +...+ 103 = 3025

=>2.13 + 2.23+...+2.103 = 2.3025

=> 26 + 46 +...+ 206 =6050

=> [23 + 3] + [ 43 + 3] + ...+ [203 + 3] =6050

=> 23 + 43 +... 203 = 6050  - 3.10

=> S = 6020

Ta có :  

13 + 25 + ... + 103 = 3025

=> 2,13 + 2,23 + .... + 2,103 = 2,3025

=> 26 + 46 + .... + 206 = 6050

=> ( 23 + 3 ) + ( 43 + 3 ) + ..... + ( 203 + 3 ) = 6050

=> 23 + 43 + .... 203 = 6050 - 3,10

=> S = 6020

ta có: 13 + 23 + 33 +...+103 = 3025

⇒ 2.13 + 2.23 +..+ 2.103 = 2.3025

⇒ 26 + 46 +..+206 = 6050

⇒ (23+3) + (43+3) +..+(203+3) = 6050

⇒ 23 + 43 +..+203 = 6050 - 3.10

⇒ S = 6020

ta có: 13 + 23 + 33 +...+103 = 3025

⇒ 2.13 + 2.23 +..+ 2.103 = 2.3025

⇒ 26 + 46 +..+206 = 6050

⇒ (23+3) + (43+3) +..+(203+3) = 6050

⇒ 23 + 43 +..+203 = 6050 - 3.10

⇒ S = 6020

ta có: 13 + 23 + 33 +...+103 = 3025

⇒ 2.13 + 2.23 +..+ 2.103 = 2.3025

⇒ 26 + 46 +..+206 = 6050

⇒ (23+3) + (43+3) +..+(203+3) = 6050

⇒ 23 + 43 +..+203 = 6050 - 3.10

⇒ S = 6020 

\(1^3+2^3+3^3+...+10^3=3025\\ S=2^3+4^3+6^3+...+20^3\\ =\left(2\cdot1\right)^3+\left(2\cdot2\right)^3+\left(2\cdot3\right)^3+...+\left(2\cdot10\right)^3\\ =2^3\cdot1^3+2^3\cdot2^3+2^3\cdot3^3+...+2^3\cdot10^3\\ =2^3\left(1^3+2^3+3^3+...+10^3\right)\\ =8\cdot3025\\ =24200\)

Ta có:

\(S=2^3+4^3+6^3+...+20^3.\)

\(\Rightarrow S=2^3.1^3+2^3.2^3+2^3.3^3+...+2^3.10^3.\)

\(\Rightarrow S=2^3\left(1^3+2^3+3^3+...+10^3\right).\)

\(\Rightarrow S=8.3025=24200.\)

Vậy \(S=24200.\)

huỳnh thị ngân hà, nau te, trần như tính sao ra z? 

S = 13+10+23+20+33+30+...+103+100

S =  13+23+33+...+103+10.100

S = 3025+1000

S = 4025

6020 , chắc chắn đúng 10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%

Ta có: 

\(S=23+43+63+...+203\)

\(S=\left(10+13\right)+\left(20+23\right)+...+\left(100+103\right)\)

\(S=\left(10+20+...+100\right)+\left(13+23+...+103\right)\)

\(S=10\cdot\frac{10\cdot11}{2}+3025\)

\(S=550+3025=3575\)

Ta có: 13 + 23 + ... + 103 = 3025

=> 2 . 13 + 2 . 23 + ... + 2 . 103 = 2 . 3025

=> 26 + 46 + ... + 206 = 6050

=> ( 23 + 3 ) + ( 43 + 3 ) + ... + ( 203 + 3 ) = 6050

=>23 + 43 + ... + 203 = 6050 - 3 . 10

=>S = 6020

1³ + 2³ + ... + 10³ = 3025 ( như này thì đúng hơn á )

S = 2³ + 4³ + 6³ + ... + 20³

= (2.1)³ + (2.2)³ + (2.3)³ + ... + (2.10)³

= 2³.1³ + 2³.2³ + 2³.3³ + ... + 2³.10³

= 2³( 1³ + 2³ + ... + 10³ )

= 8.3025 = 24 200