làm ơn tl giùm vs ajk!!

a) <=>80-x+6=9.8
    <=>86-x=72
    <=>x=14
b) <=>495-5x-20=10
    <=>475-5x=10
    <=>5x=465
    <=>x=93

a) ( 15x +2.2\(^3\)) -4=10

\(\Rightarrow15x+2^4=14\)

\(\Rightarrow15x=14-16\)

\(\Rightarrow x=\left(-2\right):15\)

\(\Rightarrow x=-\frac{2}{15}\)

b)\(3x.15^5=15^6\)

\(\Rightarrow3x=15^6:15^5\)

\(\Rightarrow3x=15\)

\(\Rightarrow x=\frac{15}{3}=5\)

a) (15x+2.2³)-4 = 10

15x+2.2³ = 10+4

15x+2.2³ = 14

=> 15x+2⁴=14

15x+16=14

15x=14-16

15x = -2

x = -2:15

x = -2/15

b) 3x.15⁵ = 15⁶

3x = 15⁶ : 15⁵

3x = 15¹

x = 15 : 3

x = 5

a) <=> 15x + 16 - 4 = 10

    <=> 15x             = -2

    <=>    x             = -2/15

b) <=> 3x = 15

    <=>  x = 5

ngu nguoi

dung khong

`#3107`

b)

`2.3^x = 162`

`\Rightarrow 3^x = 162 \div 2`

`\Rightarrow 3^x = 81`

`\Rightarrow 3^x = 3^4`

`\Rightarrow x = 4`

Vậy, `x = 4`

c)

`(2x - 15)^5 = (2 - 15)^3`

\(\Rightarrow \)`(2x - 15)^5 - (2x - 15)^3 = 0`

\(\Rightarrow \)`(2x - 15)^3 . [ (2x - 15)^2 - 1] = 0`

\(\Rightarrow\left[{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=15\\\left(2x-15\right)^2=\left(\pm1\right)^2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\2x-15=1\\2x-15=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\2x=16\\2x=-14\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=8\\x=-7\end{matrix}\right.\)

Vậy, `x \in`\(\left\{-7;8;\dfrac{15}{2}\right\}.\)

`d)`

\(3^{x+2}-5.3^x=?\) Bạn ghi tiếp đề nhé!

`e)`

\(7\cdot4^{x-1}+4^{x-1}=23?\)

\(4^{x-1}\cdot\left(7+1\right)=23\\ \Rightarrow4^{x-1}\cdot8=23\\ \Rightarrow4^{x-1}=\dfrac{23}{8}\)

Bạn xem lại đề!

`f)`

\(2\cdot2^{2x}+4^3\cdot4^x=1056\)

\(\Rightarrow2\cdot2^{2x}+\left(2^2\right)^3\cdot\left(2^2\right)^x=1056\\ \Rightarrow2\cdot2^{2x}+2^6\cdot2^{2x}=1056\\ \Rightarrow2^{2x}\cdot\left(2+2^6\right)=1056\\ \Rightarrow2^{2x}\cdot66=1056\\ \Rightarrow2^{2x}=1056\div66\\ \Rightarrow2^{2x}=16\\ \Rightarrow2^{2x}=2^4\\ \Rightarrow2x=4\\ \Rightarrow x=2\)

Vậy, `x = 2`

_____

\(10 -{[(x \div 3+17) \div 10+3.2^4] \div 10}=5\)

\(\Rightarrow\left[\left(x\div3+17\right)\div10+48\right]\div10=10-5\)

\(\Rightarrow\left[\left(x\div3+17\right)\div10+48\right]\div10=5\)

\(\Rightarrow\left(x\div3+17\right)\div10+48=50\)

\(\Rightarrow\left(x\div3+17\right)\div10=2\)

\(\Rightarrow x\div3+17=20\)

\(\Rightarrow x\div3=3\\ \Rightarrow x=9\)

Vậy, `x = 9.`

=> 3x + 1/5 = 136 - 8/10

=> 3x + 1/5 = 125,2

=> 3x = 125

=> x = 125/3

  tick đúng cho mình néh !

vậy cậu giải luôn hộ tớ cái bài lúc này nhé !

2.2.\(\frac{-2}{\frac{3}{x}}\)= \(\frac{4}{\frac{9}{-10}}\)

\(\frac{-2}{\frac{3}{x}}\)= \(\frac{4}{\frac{9}{-10}}\): 4

-2/3 : x = -1/90

x = 60