a) \(\dfrac{3}{5}:x=3\)

\(x=\dfrac{3}{5}:3\)

\(x=\dfrac{3}{5}\times\dfrac{1}{3}\)

\(x=\dfrac{1}{5}\)

b) \(\dfrac{x}{5}:\dfrac{3}{8}=\dfrac{8}{5}\)

\(\dfrac{x}{5}=\dfrac{8}{5}\times\dfrac{3}{8}\)

\(\dfrac{x}{5}=\dfrac{3}{5}\)

\(=>x=3\)

a,x=3/5:3/

x=3/5.1/3

x=1/5

b,x/5=8/5.3/8

x/5=3/5

=> x=3

`a)3/5:x=3`

`x=3/5:3=3/5xx1/3`

`x=1/5`

`b)x/5:3/8=8/5`

`x/5=8/5xx3/8`

`x/5=3/5`

`x=3`

x – 8 = (–3) – 8

x = (–3) – 8 + 8 (chuyển –8 từ vế trái sang vế phải)

x = –3 + 8 – 8

x = –3.

Vậy x = –3.

\(a,\left(x+2\right)^{10}+\left(x+2\right)^8=0\\ \Leftrightarrow\left(x+2\right)^8\left[\left(x+2\right)^2+1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x+2\right)^8=0\\\left(x+2\right)^2+1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x+2=0\\\left(x+2\right)^2=-1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-2\\x\in\varnothing\end{matrix}\right.\\ b,\left(x+3\right)^{10}-\left(x+3\right)^8=0\\ \Leftrightarrow\left(x+3\right)^8\left[\left(x+3\right)^2-1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x+3\right)^8=0\\\left(x+3\right)^2-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x+3=0\\\left(x+3\right)^2=1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-3\\x+3=1\\x+3=-1\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-2\\x=-4\end{matrix}\right.\)

x.8+56+x.4-28=x.3+9+x+4*(1-3)

=>12x+(56-28)=(3x+x)+9+4*(-2)

=>12x+28=4x+9-8=4x+1

=>12x-4x=1-28

8x=-27

x=-27/8

\(x^3-6x^2+12x-8=-8\\ \Leftrightarrow\left(x-2\right)^3=\left(-2\right)^3\\ \Leftrightarrow x-2=-2\\ \Leftrightarrow x=0\)

Vậy x = 0 là nghiệm của pt

\(\dfrac{7}{8}-x=\dfrac{2}{3}+\dfrac{1}{8}\)
\(\dfrac{7}{8}-x=\dfrac{16}{24}+\dfrac{3}{24}\)
\(\dfrac{7}{8}-x=\dfrac{19}{24}\)
\(x=\dfrac{7}{8}-\dfrac{19}{24}\)
\(x=\dfrac{21}{24}-\dfrac{19}{24}\)
\(x=\dfrac{2}{24}=\dfrac{1}{12}\)

`7/8-x=2/3+1/8`

`=>7/8-x=19/24`

`=>x=7/8-19/24`

`=>x=1/12`

\(\frac{8}{3}:x=\frac{16}{9}:\frac{8}{3}\)

\(\frac{8}{3}:x=\frac{16}{9}.\frac{3}{8}\)

\(\frac{8}{3}:x=\frac{2}{3}\)

       \(x=\frac{8}{3}:\frac{2}{3}\)

      \(x=\frac{8}{3}.\frac{3}{2}\)

    \(x=4\)

Vậy x = 4